To calculate wind load for industrial steel structures and to apply it by using TSD

 

1. Generate manual wind loading in the design report based IS code as per the following input

• Basic wind speed = 39m/s
• Terrain category 2
• ans-

 

 

 

-basic wind speed select appendix A 

OF CODE BOOK IS 875 PART 3 THIS 

gives basic wind speed of diffrent cities .

-design wind speed Vz =Vb *K1* K2* K3

 

-Vz =depend local topography

,risk level ht. size of structural .

 

-K1 =Probability factor  taken table 1 of is 875 lll

 

-

 

-take structure life 50 years wind speed 39m/s ;  K1=1

 

K2 HEIGHT STRUCTURAL FACTOR TAKEN TABLE 2=1.05 

 

 

 

PROCEDURE -------

DESIGN WIND SPEED  Vz =Vb  x K1X K2 X K3 X K4

                                       =39 X1X1.05 X1X1.15 =47.09M/S

 

Vb =basic wind speed =39m/s

 

 

DESIGN WIND PRESSURE Pz =0.6 xvz ^2^2 =1330 n/m2 

LENGTH =18M

WIDTH =18M

HEIGHT =16.88 M

 

L/W =1  AND  H/W =.937

-EXTERNAL PRESSURE COFFICIENT  FOR 

WALL IS TAKEN TABLE 5 IS 875 111

 

 

ROOF ANGLE calculated roof angle is 20  degree.

is875- 111

 

RESULTS

 

 

 

 Calculation are done for

wall panel .

 

 

 

 

 

2. Based on the above calculation apply the loadings on the model

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

• Open TEKLA structural software and open week 4 file
• Select load tab, in that select load cases and add new load cases
• Now as per value apply the load
• Frame 1 = Wind+y+cpi = 0.253 kN/m^2
• Apply load on Frame 5 = Wind +y+cpi = -0.951 kN/m^2
• Negative value means wind acting away from the wind panel
• Apply load on face 1 = wind+y-cpi = 1.52 kN/m^2
• Apply load on face 5 = wind+y-cpi =0.317 kN/m62
• Apply load on face C =wind+y+cpi = -1.394 kN/m^2
• Apply load on face D=wind+y-cpi = -0.127 kN/m^2
• Now we will apply load of -y
• All loading will be similar just the direction of wind is changed
• Frame 5 = wind-y+cpi = -0.253 kN/m^2
• Apply load on Frame 1 - wind-y+cpi = 0.951 kN/m^2
• Apply load on Frame 5 = wind-y-cpi = -1.521 kN/m^2
• Apply load on Frame 1 = wind-y-cpi = -0.317 kN/m^2
• Apply load on frame D = wind-y+cpi = 1.394kN/m^2 on global X axis
• Apply load on frame A=wind-y-cpi = 0.127 kN/m^2 on global X axis
• Apply load on face C = wind+y-cpi = 0.317kN/m^2

 

Now apply wind load on roofs and take roof angle as 25 degree

• From IS 875 part  3 table 3 clause 6.2.3.2 

Now apply roof load on  PQ

• Frame 2 =wind+y+cpi = -1.204 kN/m^2
• Apply load on frame 2= wind+y-cpi = 0.063kN/m^2

Roof XY

• Apply load on frame 1 = wind+y-cpi = 0 kN/m^2

 

Roof PQ

• Apply load on frame 1= wind -y+cpi = 1.204kN/m^2
• Apply load on frame 1=wind-y-cpi= -0.063 kN/m^2 on roof PR
• Apply load on frame 2 of roof XY = wind -y+cpi = 1.267 kN/m^2
• Apply 0 kN/m^2 on roof XY of frame 2  

 

RESULT :

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

3. On a separate model generate wind loading using wind wizard

 

ans-delete previous  wind load

 

click wind wizard in load tab 

-click on worst case data 

 

 

 

 set height ,typical industrial and wind speed  39 m/s click it .

 

 next ,set terrain category fetch distance 10m 

 

click next for result and diretion .

add wind load in load cases .

 

 

 

wind load generate in wind wizard .