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AIM- To carryout design of RCC model in etabs . -Design in here rcc moment resisting frame . -provided rcc reinforcement in longitudinal and shear in 2 beams -give reason of failure of middle span along grid A . INTRODUCTION - IN THIS CH. 2 BEAM DETAILING IS DONE. …
Bunti Parashar
updated on 01 Feb 2023
AIM-
To carryout design of RCC model in etabs .
-Design in here rcc moment resisting frame .
-provided rcc reinforcement in longitudinal
and shear in 2 beams
-give reason of failure of middle span along
grid A .
INTRODUCTION -
IN THIS CH. 2 BEAM DETAILING IS DONE.
1) 3 span continuous beam along grid A
2) 7 span continuous beam along grid 3
Address the following issues thereafter.
• Provide details of longitudinal and
shear reinforcement for the two continuous beams.
Sketch the beam elevation details or draft it using
autocad software. A sample of how beam elevation
details is prepared in consultancy firms is provided below.
-IN order to calculate maximum shear force in any of
span of continious beam.
-IS 13920- 2016, Clause 6.3.3 b
is followed which state that
-shear force capacity of beam larger than
a] factored shear force as per linear structural
analysis .
-b]factored gravity shear force plus equilibirium shear force ehn plastic hinges are formed at both the ends of beam given by
1.For sway to right :
2. For sway to left:
.PROCEDURE -
-intially open etabs .
-go to analysis > check model .
-
-After that go to analysis and analysis model
by run analysis option .
-after complete analysis go to concerete frame
design , drop down and carry out design of
beam by chossing start design check option .
-after completion , reinfocement values are
obtain for display ,design info option in concerete
frame design option .
-now we need to carryout detailing of grid A
and grid 3 continious beam .
-intially detailing is done for grid A
-maximum values of reinforcement AT top
is 2045 mm2 and at the bottom 1945 mm^2
-hense provide 2 no. of 32mm dia. at top and
bottom i.e 1608mm^2
-then ,we will provided 25 mm dia. bar to
satisfy remaing .
-cover provided is 30mm .
-shear reinforcement at 10mm bars @50mm c/c
throughout then beam .
-now detailing is carried out for grid 3
-maximum values of reinforcement at
top 1940 mm2 and at and bottom is 1501 mm^2 .
-hence provided 2no. of 32 mm dia bars to
satisfy remaing [only at top ].
-cover provided 30mm .
-shear reinforcement provided as 10mm
dia bars @100mm c/c through out of beam.
-
-
beam detailing is complete .
-possible reason for failure of middle span
along grid A .
failure due to higher shear stress , shear stress devloped
is 3.11 mpa > allowable shear stress 3.1 mpa which leads to failure of this beam .
possible ways to solved at that type issues .
-using higher grade of concerete which increase permissible stress in it .
-shear strenghth of beam can be increased by redusing effective depth of beam .
now for grid A sway left to right
HOGGING MOM. AND SAGGING MOM. RESISTANCE 173.97 KNM , 292.99 KNM .
Factored shear force due to vertical load acting on span .
,Vu,bD+L=114.9754kN
Clear span,
LAB= 4.725m
So as per IS13920 sway shear is calculated as:
Vu,b= 253.32kN for sway to right
Now, for sway to left the sway shear is calculated as:
Vu,b= 252.43kN for sway to left.
Shear force demand calculated by etabs : 237.54 kN
Take the shear sway to be 253 kN.
Grid 3:
Sway to right
Hogging moment of resistance = 161.07 kN m
Sagging moment of resistance = 219.39 kN m
Factored shear force due to vertical loads acting on the span ,Vu,bD+L= 88.23 kN
Clear span,
LAB= 3.95 m
So as per IS13920 sway shear is calculated as:
Vu,b= 240.4 kN for sway to right
Now, for sway to left the sway shear is calculated as:
Vu,b= 243.386 kN for sway to left.
Shear force demand calculated by etabs : 209.552kN
Hence take the shear sway as 240 kN.
Result :
Hence, the entire detailing and designing of beam is completed.
-
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