Challenge

Week 4 -Wire Bending Challenge

Aim-

For this project we will have to perform an analysis to simulate the bending of a wire in ANSYS. We will have to use Copper Alloy (Non Linear), Aluminium Alloy (Non-Linear), and Magnesium Alloy (Non-Linear) for the wire alone. We need to find out the Equivalent stress and Equivalent strain on the wire alone.

Procedure-

  • We have to first start as new project in the ansys workbench and select the proper material for the weld joint plate.
  • Here material has been specified in the project so we will select materials as per case.

  • Now we have to import the model for that right click on the geometry tab and hit import>>then select the file from saved location and hit ok.

  • Now we have to open mechanical Model and wait for a while till our model loads.
  • For wire select material as copper alloy NL.
  • We have to now remane the parts name and the proceed further for connections.

Connections-

  • Now we have to delete the two old connections and then need to duplicate connections.
  • Now for first connection we keep frictional contact from wire to lever, (right click on connection and select rename based on connection).

  • Now for duplicated contact we have reverse the connections and and select the contact as lever and target as wire.

  • As our lever is going to rotate to bend the wire we need to define a revolute joint there.

Mesh-

  • For meshing first we create the patch method to it, to do so right click on mesh>>insert>>method>>select all components and in type select tetrahedrons.

  • Now we have to insert sizing for refined mesh to wire (here I have done meshing for copper alloy NL wire only since solution was not convering). To do So right click on mesh>>insert>>sizing.

  • But for rest two materials I have selected total 4 surface refer below snap.

  • Now for get proper result for bending we need to refine the mesh in area near wheel cutout, for that we have to create a new co-ordinate, near wheel cutout fillet & also need to do X & Z as 6mm and -3mm respectively, as shown in snap.

  • For mesh right click on mesh>>insert>>sizing, refer below snap for reference.

Mesh for copper alloy NL

Mesh for Aluminium alloy NL & Magnesium alloy NL

Analysis setting-

  • Go to analysis setting and set number of set as 8 and refer below setting for 1st step, Keep all output parameters ON.

  • For 2 to 8 refer below snap

  • Now we have to apply fixed support to wheel and wire as shown in snap.

  • Now we have to apply joint load to lever bottom refer below snap,

Solution-

  • Now for stress right click on the solution>>insert>>stresses>>equivalent (von-Mises).
  • Now for strain right click on the solution>>insert>>strins>>equivalent (von-Mises).

Results-

1. Equivalent Stress on Wire-

Copper Alloy NL-

Aluminium Alloy NL-

Magnesium Alloy NL-

2. Equivalent Elastic Strain-

Copper Alloy NL

Aluminium Alloy NL-

Magnesium Alloy NL-

Result Comparision

Material

Equivalent Stress (MPa)

Equivalent Strain

Min.

Max.

Min.

Max.

Copper Alloy NL

0.003649

328.62

7.335E-8

0.0030176

Aluminium Alloy NL

0.0024106

327.74

7.216E-8

0.0048122

Magnesium Ally NL

0.001539

248.61

7.439E-8

0.0055294

  • From above table we can say that the max. stress induced in copper alloy and least is in magnesium alloy.
  • Similarly max. strain induced in magnesium alloy and least in copper alloy.
  • So we can say that copper alloy will not bend easliy and vice versa magnesium alloy we deform easliy so bending is easy in it.

Animated result-

1. Copper Alloy NL-

Equivalent stress-

2. Equivalent Elastic Strain-

Aluminium Alloy NL-

1. Equivalent Stress-

2. Equivalent Elastic Strain-

Magnesium Alloy NL-

1. Equivalent Stress-

2. Equivalent Elastic Stress-

Conclusion-

  • A concise finite element model for simple wire strand subjected to pure bending has been established. Precise analytical boundary condition has been developed.
  • From results we can conclude that the copper is most elastic material and magnesium is least one.
  • Characteristics we can enhance or decrease include:

    • Strength
    • Abrasion resistance
    • Corrosion resistance
    • Crushing resistance
    • Fatigue resistance
    • Rotation resistance. Flexibility
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