Week 2 Railwheel and Track

objective:To perform the static structural analysis on the rail wheel and track and then compare the results of the bearing load of 100000 with the 500000N and evaluate the results.

procedure:

1.Import the geometry model and then check the material is assigned to the components and edit the model in the model section.

2.Define the contacts based on the defination and between the wheel and the track and wheel and the shaft define the frictional contact between the wheel and the track and frictionless contact between the wheel and the shaft and assign the frictional coefficient of 0.3 .

3.Define the joint load fixed to the track body and fixed in all dof's and the translational motion of the shaft in the x axis in z direction and planar motion of the wheel in the face of the wheel is selected.

4.Mesh of the wheel and the track region of 35mm size by introducing the mesh sizing, and remaining parts will be meshed to a 50mm size.

5.In the analysis settings first take the step 5 and current step no will be 1 and then take the step 5 with the current step no as the 2 with the carry over time step with the min time step of 1e-03 and max of 0.1.

6.Introduce the joint load displacement as the 500mm with a 5 steps of each step with 100mm for the wheel displacement and the bearing load of the 100000N select the bearing region .

7.In the solution part add the vonmises equivalent stress ,elastic strain , total deformation and the same results will be evaluate for the only wheel section and introduce the pressure ,probe and the user defined results .

8.After setting all click on the solve and the solver output as force convergence and wait till the solver completed the full solve and evaluate the results.

9.After the evaluating of all results compare the results of the bearing load of 100000N with the bearing load of 500000N also calculate the deformation that obtained in both the cases.

10.Tabulate the both the results obtained in the both the bearing load of 100000N with the bearing load of 500000N .

case1 :Bearing load of 100000N

Fig shows the frictional contact between the wheel and the track.

fig shows the frictionless contact between the wheel and the shaft.

fig shows the meshing of the component with mesh sizing .

fig shows the fixed of the running rail with respect to all dof's

fig shows the tranlational displacement of the wheel in x direction.

fig shows the planar displacement of the wheel.

fig shows the bearing load of 100000N in y direction.

fig shows the displacement of the wheel about the 500mm.

fig shows the deformation of min 0mm and the maximum of 1001mm.

fig shows the equivalent elastic strain of min and max minimum elastic strain of 4.5884e-15 and max elastic strain of 0.00041879mm/mm

fig shows the equivalent stress of min of 5.6511e-10 mpa and max of 74.748mpa.

fig shows the equivalent elastic strain of the only wheel is that min of 8.135e-08 and max of 0.00029868mm/mm.

fig shows the equivalent stress of min 0.0056822mpa and max of 41.576mpa .

fig shows the min and max pressure of 0 mpa and maximum of 87.697mpa in between the wheel and the track.

fig shows the pressure between the shaft and the wheel.

fig shows the user defined result with the minimum and maximum angle of -61.833 and 2.0279e-15 degrees.

fig shows the force convergence curve for the min of 8.011e-02N and max of 7.0815e+09N

case2:Bearing load of 500000N

fig shows the bearing load of 500000N at the bearing section.

fig shows the total deformation of min 0mm and max of 1000.7mm.

Fig shows the equivalent elastic strain of min of 1.3008e-17 and max of 0.0045756mm/mm.

fig shows the min and max equivalent stress of min of2.1479e-12 and max of 443.22mpa.

fig shows the equivalent elastic strain of min and max of 0.00081032mm/mm and min of 3.1983e-07 mm/mm for the only wheel section.

fig shows the equivalent stress of min of 0.025436 and max of 149.99mpa.

fig shows the min and max pressure of 0mpa and max of 394.7mpa of between the wheel and the track.

fig shows the min and max pressure of the wheel and the shaft of min 0 and max of 31.651mpa.

fig shows the user defined result as the angle of min-61.78 degree and max of 3.2771e-16 degree.

case1: Multiply the bearing load by 5 times and compare the results with the load of 100000 N (As done in week 2 video). Compare the Total Deformation, Equivalent stress and the life under both the loads.

cases	Total deformation(mm)	Equivalent stress(mpa)	Elastic strain(mm/mm)	Force convergence(N)
Bearing load of 100000N	Min:0 Max:1001mm	Min:5.6511e-10 Max:74.748	Min:8.1354e-08 Max:0.00029868	Min:8.011e-02 Max:7.0815e+09
Bearing load of 500000N	Min:0 Max:1000.7	Min:2.1479e-12 Max:443.22	Min:0.0045756 Max:1.3008e-17	Min:0.49871 Max:1.0901e+10

• The max deformation is in the bearing load of 100000N with max of the 1001mm.
• The max equivalent stress will be max for the bearing load of 500000N with max of 443.22mpa.
• The max elastic strain in the bearing load of 100000N will be of 0.00029868mm/mm.
• The max force convergence will be for the bearing load of 500000N with of 1.0901e+09.

case2: Implement a User defined result and calculate the Total Deformation from this result and check if it is the same as that obtained by the inbuilt result by ANSYS for a load of 100000 N.

cases	Total deformation(mm)	user defined result(in terms of angle)
Bearing load of 100000N	Max:1001mm	Min:-61.833 Max:2.0279e-15
Bearing load of 500000N	Max:1000.7mm	Min:-61.78 Max:3.2771e-16

• The total deformation in the bearing load of 500000N is 1000.7mm which is same as the bearing load of 100000N of 1001mm.
• The max user defined result (angle) is max for the bearing load of 100000N is 2.0279e-15.

Conclusion: In this challenge perform the static structural analysis for the rail wheel track and compare the results of both the loads of 500000N and the 100000N and tabulate the results.

Note: The links for the bearing load of both the cases.

https://drive.google.com/file/d/1iRY6sNQ67tzlPbOPSpLejlXVus0z29SD/view?usp=sharing

https://drive.google.com/file/d/1Q7Dic1zzHMoT7xy9OtCOYp4KsZo4zWcx/view?usp=sharing