Week 11 Challenge
1. Friction load determination
A pipe carrying LNG rests on the shoe having vertical force of 125 kN. Calculate the Friction load on the axis. Also find the friction force, if TEFLON pad is used between shoe and pipe support.
Given vertical force=125 KN
- TEFLON pad is used between shoe and pipe support
Procedure:
- Friction force=pipe gravity load x friction coefficient
- Friction force=125x0.15
- Stainless friction coefficient=0.15
- Friction force=18.75 KN
- Friction coefficient for teflon=0.1
- Friction force due to teflon=125x0.1=12.5 KN
2. Support Types
Identify the type of support as Spring, Guyed, Stop or Semi Anchor (Guyed + Rest + Stop ) or Rigid Strut from following images.
Figure 1
- Fixed support because both ends are jointed pr fixed to members.
Figure 2
- Pinned Support
Figure 3
- Fixed Support
Figure 4
- Fixed and pinned both
Figure 5
- Pinned support
Figure 6
- Pinned support because both jointed by pin support
3. Design of a pipe rack
Design a typical pipe rack bent in oil plant. The pipe rack configuration shall be as shown in Figure 1 and the plan layout as shown in Figure 2.
Given:
Spacing between two columns= 7.5m
Total height= 9m
7 Spans at 6m
Cable tray=150mm.Pipe diameter=24,12,18,8 inches.
2 tier spacing=1.5m
Center to center distance between column=0.75m
Procedure:
- OPen STAAD> create new model>define nodes and beams as per given data.


- Properties>add section>assign property


- Support >create support >assign support

Loading add load definition > add load case details > assign loads to members
- Uniform operatig dead load= 1.9 KN/m^2
- Pipe load=1.9x7.5=14.28 KN/m
60% of it = 14.28 x 0.6 =8.5 KN/m
- Point load= 15 KN
- 60% of it= 9KN


- LOad combination > add > envelope > add combinations and loads.

- Design parameters > add parameters.

Run analysis > check results