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AIM: Foundation design using SAFE PROCEDURE: Q1) 1. Define material properties 2. Define slab properties 3.Define Load Pattern 4. Define Soil Subgrade modulus 5. Assign point load 6.Assign load combinations 7.Check design preferences (min cover 50mm) 8. Run analysis and design Q2) Aim :- To…
C Mallika
updated on 11 Feb 2023
AIM: Foundation design using SAFE
PROCEDURE:
Q1)
1. Define material properties
2. Define slab properties
3.Define Load Pattern
4. Define Soil Subgrade modulus
5. Assign point load
6.Assign load combinations
7.Check design preferences (min cover 50mm)
8. Run analysis and design
Q2)
Aim :-
Introduction :-
Procedure :-
Step : 01
Single Footing was selected.
Subgrade modulus = F.O.S x S.B.C / max settlement
= (3x150) / 0.05 = 9000 KN/m³
The compression axial load for the load combination (1.5DL + 1.5LL) is 2000 KN.
Unfactored load = 2000 / 1.5 = 1333.3 KN
Dead load breakup= 1333.3 / 2 = 666.5 KN
Live load breakup= 1333.3 / 2 = 666.5 KN
Therefore, Footing thickness 800 mm.
Step : 02
Click define > material properties
Rebar yielding strength(Fy) = 500 N/mm²
Rebar ultimate strength (Fu) = 545 N/mm²
M25 grade of concrete
Modulus of elasticity
E = 25x5000 = 25000 N/mm²
Step : 03
Step : 04
Step : 05
Step : 06
Step : 07
Step : 08
Step : 09
Step : 10
Step : 11
Two-way shear is 0.719, Hence OK.
Step : 12
Bending Moment :-
Shear Force :-
Step : 13
RESULT :-
Procedure :-
Given.
Column size = 600 x 600 mm
Unfactored load = 1175 KN
Pile length = 16m
Pile diameter = 500 mm
Load carrying capacity = 200 KN.
Calculations :-
Number of pilers = 1175 / 200 = 5.6 = 6
Spring constant = ExA / L
Where, E = 25000 N/mm²
A = (π4)">(π4)(4)(500)² = 196375 mm²
L = 16000 mm
Spring constant =25000 x 196375 / 16000=306835 N/mm or 306835 KN/m
Edge spacing is taken as 200 or 300 mm.
Step : 01
Step : 02
Step : 03
Click define > material properties >M25 grade of concrete.
Modulus of elasticity
E = 25x5000 = 25000 N/mm²
Fe 500 rebar was added next as shown below.
Step : 04
Step : 05
Step : 06
Step : 07
Step : 08
Step : 09
Step : 10
Bending Moment :-
Shear Force :-
RESULT :-
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