Project 1_Analyze and design a steel building to 10T CRANE as per IS standard code using TEKLA STRUCTURAL DESIGNER.

Aim :-

 To analyse and design a steel building to 10T CRANE as per IS standard code in TEKLA STRUCTURAL DESIGNER.

Procedure:

• Open the TEKLA software and select structure window.
• Now enter the levels as base, ground floor, first floor and roof as per the question
• 
• Now select the grid lines and draw them according to the ground floor plan
• 
• Now from the Manage property sets, define a new concrete column as 400*800 with grade of M45 and place the columns on the grid intersections
• 
• Now define a steel column of section ISMB 500, and place it at the grid intersections of first floor.
• 
• 
• Now define the primary beams as ISMB 500 and place it on the ground floor
• 
• Similarily draw the same beams on the first floor and roof.
• 
• Now define the frames for the model and select any one frame and draw a central vertical line. Slope of the roof is 18 degree, so the height at which the rafter has to be placed should be determined. tan 18 = ht./19 => ht. = 6m
• 
• 
• Now we have to go to the slab sections and define a slab of thickness of 300mm and grade M50. Since the first layer is a square shape, it has to be a two way slab and the other two rows are one way.
• The same process is repeated for all the three floors
• 
• Now we have to assign the roof panels and wall panels
• 

Calculation of Dead load:

• Finish of 50 mm = 0.5*25 = 1.2KN/m
• Brickwall load for ground floor = 0.15*20*5 =15.5KN/m
• Brickwall load for first floor, second floor and roof = 0.15*20*7 = 21.2KN/m

• Now apply all these loads to the entire model
• 

Calculation of Live Load:

• Meeting room = 2KN/m
• Toilet = 2KN/m
• Office Room = 2.5 KN/m
• Maintenance room = 2.5KN/m
• Pantry =5KN/m
• Staircase = 5KN/m

• Now we have to apply all these loadsto each floor of the model
• 

Calculation of Wind Loads:

• Vz= Vb*k1*k2*k3*k4

Vb = 39 m/s

From Table 1, IS 875-3 , k1 = 1

From Table 2, IS 875-3, k2 = 1.03

k3 = 1 ; k4 =1

Vz = 39&1*1.03*1*1 = 40.17 m/s

• Pz = 0.6*Vz^2

Pz = 0.6*40.17^2 = 0.968 KN/m^2

• Along face A

Interior

• H= 18m
• L= 90m
• w= 38m
• Cpe =0.7
• Cpi =0.5
• Cp= 0.2
• Pz = 0.968KN/m^2
• Load = 0.1936 KN/m

Exterior

• H= 18m
• L= 90m
• w= 38m
• Cpe =0.7
• Cpi =-0.5
• Cp= 1.2
• Pz = 0.968KN/m^2
• Load = 1.16 KN/m

• Along face B
  

Interior

• H= 18m
• L= 90m
• w= 38m
• Cpe =-0.25
• Cpi =0.5
• Cp= -0.75
• Pz = 0.968KN/m^2
• Load = -0.726 KN/m

Exterior

• H= 18m
• L= 90m
• w= 38m
• Cpe =-0.25
• Cpi =-0.5
• Cp= 0.25
• Pz = 0.968KN/m^2
• Load = 0.242 KN/m

• Along face C
  

Interior

• H= 18m
• L= 90m
• w= 38m
• Cpe =-0.6
• Cpi =0.7
• Cp= -1.3
• Pz = 0.968KN/m^2
• Load = -1.25 KN/m

Exterior

• H= 18m
• L= 90m
• w= 38m
• Cpe =-0.6
• Cpi =-0.7
• Cp= 0.1
• Pz = 0.968KN/m^2
• Load = 0.0968 KN/m

• Along face D
  

Interior

• H= 18m
• L= 90m
• w= 38m
• Cpe =-0.6
• Cpi =0.1
• Cp= -0.7
• Pz = 0.968KN/m^2
• Load = -0.6776 KN/m

Exterior

• H= 18m
• L= 90m
• w= 38m
• Cpe =-0.6
• Cpi =-0.1
• Cp= -0.5
• Pz = 0.968KN/m^2
• Load = -0.484 KN/m

• Loads to roof considering one part as EF (Slope = 18 degree)
  

Interior

• H= 12m
• L= 90m
• w= 38m
• Cpe =-0.4
• Cpi =0.7
• Cp= -1.1
• Pz = 0.968KN/m^2
• Load = -1.06 KN/m

Exterior

• H= 12m
• L= 90m
• w= 38m
• Cpe =-0.4
• Cpi =-0.7
• Cp= 0.3
• Pz = 0.968KN/m^2
• Load =0.2904 KN/m

• Now we have to apply the loads along each face of the model
• 

Calculation of Crane load:

• Weight of crab = 35KN
• Weight of crane = 160KN
• Crane capacity = 100KN
• Wheel base =3m
• Distance between gantry rails = 20m
• Distance between gantry column = 6m
• Max wheel load = Max point load + Weight of crab =135KN
• Self weight of crane = 160KN/20 = 8KN

• Taking moment about A,

Rb*20-135*1-8*20*10 =0

Therefore Rb= 86.75KN

• Taking moment about B,

Ra*20-135*19-8*20*10=0

Therefore Ra= 208.25 KN

• Max load on each wheel =Ra/2 = 104.13 KN
• Assume self weight of gantry girder =1.5KN/m
• Total dead load =1.8KN/m

• Taking moment about C,

Rd*6-104.13(0.75+3)-104.13*0.75=0

Therfore, Rd = 78.9 KN

• Taking moment about D,

Rc*6-104.13(2.25+3)-104.13*2.25=0

Therefore, Rc=130.15KN

Now, Rc+Rd = 208.25 KN

• Bending moment under wheel load due to live load = 78.9*2 = 156.18KNm
• Bending moment due to impact = 0.10*156.18 = 15.618 KN
• Total bending moment due to live load and impact load = 171.79KNm
• Bending moment due to dead load =WL/2 = 8.1 KN/m
• Max bending moment = 171.79 + 8.1 = 179.89 KNm
• Max shear force at D , Rc*16-104.13*6-104.13*3=0 . Therefore Rc= 156.18 KN

• First we will have to draft a rough postion of beams and columns in the plan using paint  tool

Ground floor :

 First floor :

• The rough beam and column position are created for ground floor and first floor .
• after this new tekla file is opened  and save it as project 1 .
• New > Model > construction levels .

• Construction levels 
• Base level > ground floor > 0.5 m 
• Ground level > first floor > 5m
• first floor > roof beam level > 7m 

•  After this we have to go to the base level 
• Add the grids 
• First we add the vertical grids according to the dimensions 
• select grid lines , pick the first point > grid 1 
• Then select  quick parallel  >grid 2 > 6m .
• 12m > grid 3 > 18m >grid 4 > 24m > grid 5 and soo on till grid 16 

• Now select perpendicular grid line  and name the grid as A

• After this parallel quick is selected and grid B is drawn with distance 8m 
• 14m > grid C , 5.070 m >grid D , 4.925 m > grid  E

• After this in the base level rc columns are created till ground floor Level 
• Manage property sets > Concrete column > 400 x 800 section > M45 

• Then steel column is added 
• Manage property sets > steel column > ground floor to roof beam level 
• ISMB> Universal columns > section > 365 X406 X393

•  After this primary and secondry steel beams are added 
• In ground floor , first floor and roof floor 
• Manage property sets > steel beam >uk > universal beams >1016X305x437

Ground floor :

 First floor :

roof beam level:

•  Click on frame option and select grid 1

•  draw grid lines at each end of distance 1328 mm with the help of construction line 
• and draw the mid point the help of the construction line 
• as we known the slope is 18 degree 
• horizontal distance is 18 m , therefore vertical distance is 6 m