Sketch a G+1 residential plan according to Vaastu Shastra and Calculation of Loads as per IS code

    AIM OF PROJECT:-

Sketch a G+1 floor residential plan, according to Vaastu Shastra, and list down the names of the structural drawings required to be provided to the site for construction.

Also, assume the sizes of the structural elements (Column, Beam, Slab, etc.,) and accordingly calculate the individual corresponding loads from the members as per IS code.

     Procedure:

Drawing/Plan of G+1 as per vaastu shastra is as below;

                           GROUND FLOOR PLAN                                                           FIRST FLOOR PLAN

                                                           ( NOTE :- ALL DIMENSIONS ARE IN METER)

Dimensions of ground floor plan:-

• Master bedroom (4.3*4.25)m
• Dining room (2.45*4.25)m
• Kitchen (3*4.25)m
• Bath + toilet (3*1.2)m
• Bedroom (2.45*6)m
• Living room (3*6.25)m
• W/c (1.2*1)m
• Bath (3.25*1.4)m

Dimensions of first floor plan:-

• Guest room  (4.3*4.25)m
• Study room (2.45*4.25)m
• Bedroom (2.45*6)m
• W/c (1.2*1)m
• Bath  (3.25*1.4)m
• Bath + toilet  (3*1.2)m
• Terrace space (3*10.5)m

Vaastu shastra followed during drawing of plan are as below;

• Entrance in the house is provided on east side of plan as a this is the symbol of  progression in life.
• Living room placed in the north east direction.
• Kitchen is placed in south east direction.
• Study room placed in the east direction.
• Staircae is placed at  northwest corner .
• Bathroom is in west direction.
• Master bedroom is in south west direction.

 Specific Dimensions:-

• Thickness of wall = 250 mm
• Thickness of slab = 230 mm
• Column dimensions = (0.25*0.3)m
• Beam dimensions = (0.3*0.3)m
• Height of floor = 3.1 m

SUB AIM :-  To calculate the load coming on a structural members like column, beam, slab and walls.

                                CALCULATIONS OF DEAD LOAD FOR COLUMN

   Given,

            The size of column as (250mm * 300mm)

                                i.e

                      t = 250 , b = 300

Let ,

         the height of the floor be 3.1 m

Height of column = (2* thickness of slab)+(2*height of floor)

                          =(2*0.23)+(2*3.1)

                          = 0.46+6.2

                          =6.66 m

So ,

   Total volume of column = 0.25 *0.3 *6.66

                                          = 0.4995 m3

   Unit weight of reinforced  concrete = 25 KN/m3.

Therefore,

        Dead load of the column = 25 * 0.4995

                                                       =  12.487 KN

 as the all the column in the building are of same dimensions the dead load also the same for all.i.e 12.487 KN.

                     CALCULATIONS OF DEAD LOADS FOR  BEAMS FOR UNIT LENGHT

  Given,

           The size  of beam as (300mm* 300mm).

                                    i.e

                    t = 300 mm,b = 300 mm

  So,

       The volume of reinforced beam for unit lenght = 0.3 * 0.3 *1.................1 denotes ,its is for unit lenght 

                                                                                  = 0.09 m3

       Unit weight of reinforced concrete = 25 KN/m3

 Therefore, 

         Dead load of beam for unit lenght = 25 * 0.09 = 2.25 KN/m

                                       CALCULATION OF WALL LOAD ;
Given,

          Height of wall = 3.1 m,

          Thickness of wall = 250 mm i.e 0.25 m,

      Unit weight of brick wall = 20 KN/m3

Therefore ,

        Dead Load i.e wall load on beam = Unit weight of brick wall *Thickness of wall *Height of wall

                                                            = 20 * 0.25* 3.1

                                                            = 15.5 KN

As the thickness of external and internal wall is same , the load of wall on beam also the same i.e 15.5 KN

                            CALCULATIONS OF LOADS FOR SLABS UNIT AREA

1. Dead load i.e self weight of slab is,

Given,

`nbsp;         Thickness (t) = 230 mm = 0.230 m

for unit area of slab ;

Assume,
             Length = 1m ( L )

             Width = 1m ( W )

Volume of concrete slab = L *W *t

                                       = 1*1*0.125

                                       = 0.125m3

Unit weight of reinforced concrete slab = 25 KN/m3

Therefore;

Dead load or the self-weight of unit area RCC slab = Unit weight of concrete × Volume of concrete unit area slab

                                                                                 = 25*0.125

                                                                                 = 3.125 KN

Therefore ,

               The Dead load for unit area slab is 3.125 KN

2. Live load for the slabs

As per table 1 of IS 875:1987 (PART 2)

Live load for bath = 2 KN/m2

Live load for bedroom = 2 KN/m2

Live load for store room = 3 KN/m2

Live load for kitchen = 2 KN/m2

Live load for living room = 2 KN/m2

Live load of terrace or balcony shows in obove plan = 3 KN/m2

3. Wind load for the slab for unit area slab;

As per the IS 875 :1987 , Wind load is designed when the height of building equal to 10 or exceed 10 ,

bjt in that case we have the height of building as 6.66 m so its is less than 10.

therefore ,

      the calculations for wind load are not required.

                                      Result:-

Dead load calculated as per the code, IS857:1987  is obtained as follows:

• The dead load of the column = 5.81 KN 
• The dead load of the beam = 2.25 KN
• The dead load of the slab = 3.125 KN
• The dead load of the wall = 15.5 KN 
• Live load for a residential building is obtained from Table 1: Imposed loads for different occupancies; of IS857:1987 (Part II)
• Wind load is calculations is not required as height of building is less than 6.66m

NOTE:- Code use for this loads calculation are ;

• IS 857 : 1987;  Revised 2018 (part I) for dead load.
• IS 857 : 1987;  Revised 2008 (partII) for live load.
• IS 857 : 1987;  Revised 2015 (Part III) for wind load.
• IS 456 : 2000 for reinforced concrete