Week 2 Challenge : Surface meshing on a Pressure valve

PROJECT REPORT AIM:             To explore GUI of GT SUITE and do the following tasks List down modules available with description Locate the given settings Explore intercooler tutorial and explore the given settings Perform an example with given data in intercooler…

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PROJECT REPORT   AIM: To learn about surface wrapping around an assembly, which is surface meshing along the entire volume. For the given model we need to do topo clean up and merge all the 3 components and then perform meshing Target length = 3mm INTRODUCTION: Surface wrap is the process of meshing where the designer…

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PROJECT REPORT OBJECTIVE: Part I Performing combustion simulation for natural gas and plotting the graph and contours for the mass fraction of all the species involved in the combustion and Soot formation And No Pollutant Part II As we know Formation of Soot and No Pollutant is not good for environment, so we can control…

PROJECT REPORT INTRODUCTION: Gate valves are used to control the flow of fluid through pipes When fully open typical gate valves give maximum fluid mass flow rate The outlet mass flow rate depends on the opening of the valve Depending on the construction, a partially open gate can vibrate from the fluid flow   GEOMETRY:…

PROJECT REPORT Aim:                Performing the analysis on the cyclone separator model by varying the particle size with a constant inlet velocity of 3m/s for particle and continuous phase velocity.  Also, calculate the separation efficiency…

                                                                           PROJECT REPORT AIM: To perform the steady state CHT simulation on a graphics card model To check the various difference occurs as we change the velocity of incoming air INTRODUCTION:                In conjugated heat transfer analysis, there are…

                                                                 PROJECT REPORT Aim: Perform Rayleigh-Taylor instability simulation in Ansys fluent, for two…

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PROJECT REPORT   Part 1- Geometry- The geometry we are using is a 2D where entire computational domain is of 60m X 20m   Of the cylinder which is a circle in our case is 2m We will record the data for air incoming at different velocity from left to right we will change the velocity of air to record different…

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1)  Assumptions (same as previous challenge) Reynolds no: 2100 Length of Pipe = 1.5m Dia of pipe = 0.01m At 20 degree Celsius, Density = 998 kg/m^3 Kinematic Viscosity = 1.004e^-6 m2/s now v, after solving  Initial velocity = 0.2 2) Boundary condition Pressure inlet = ZeroGradient  Pressure outlet = 0 Velocity…

Hagen- Poiseuille's equation is very important equation with many applications, it basically suggests how the flow can be affected by various factors. By experiments it the equation was derived which eventually stated that, flow(Q) is directly proportional to change in pressure and inversely proportional to length…

1. Finite Volume method:                                          FVM is similar to Finite Difference method, its only that in this method adjesent volume is taken under consideration, volume in which all our characteristics are preserved, By this method we donot have make assumtion regarding area and by integrating the…

1) For GF value is 1, all cells are uniform through out  when grading factor is one the geometry becomes simple and the as the value of dx is ame throughout, the CFL value are same for entire block  though there is not any major difference in velocity flow throughout by changing GF but when we check the velocity…

1) Non- conservative form Please find the code for non-conservative form clear all close all clc %input n=31; x=linspace(0,3,n); dx= x(2)-x(1); gama=1.4 ; %calculating initial proffile rho= 1-0.3146*(x); t = 1-0.2314*x; % t=temprature v=(0.1+1.09*x).*t.^0.5; %area a= 1+2.2*(x-1.5).^2; %time step nt=1000; dt=0.04; th=round(n/2);…

clear all close all clc % steady state heat conducrion equation d^2t/dx^2 + d^2t/dy^2=0 nx=10; ny=10; T=450*ones(nx,ny); %k1=aplha*(dt/dx^2) %fase tempreture TL= 400; TR= 800; TT = 600; TB= 900; %BC T(:,1)=TL; T(:,ny)=TR; T(1,:)=TT; T(nx,:)=TB; %edge refinement T(1,1)=(T(2,1)+T(1,2))/2; T(nx,1)=(T(nx-1,1)+T(nx,2))/2; T(nx,ny)=…

close all clear all clc %right side skued scheme %analatical fig. = exp(x)*cox(x) dxx=linspace(pi/40,pi/4,40); x=pi/4; i=@(x) exp(x).*cos(x); a_d= -2.*exp(x).*sin(x); %right side skued a=15/4; b=-77/6; c=107/6; d=-13; e=61/12; g=-5/6; % central diff. a1=-1/12; b1=4/3; c1=-5/2; d1=4/3; e1=-1/12; %backward diff a2=15/4;…