Week 9 Tension and Torsion test challenge

Objective:

To perform the tension and torsion test on the specimen provided below the video corresponding to the challenge.

For the tension test, displace one end of the specimen to 18mm while keeping the other fixed. You will need to find out the total deformation, equivalent stress and temperature of the specimen

For the torsion test, you will need to displace one end of the specimen to an angle of 1200 degree. Find out the total deformation, equivalent stress and temperature of the specimen

Procedure:

Tension Test:

open Explicit dynamics and rename as tension test

• Add steel 1006 material to the library

• import the geometry
• open model in mechanical apdl
• create two coordinate systems for two faces of the specimen

• generate mesh with using method tetra hedral and use mesh sizing and type=sphere of influence

• select analysis settings change end time to be 1e-003

• select solution insert displacement

• insert fixed support for another side and run the simulation

Results:

Total deformation:

eqivalent stress:

temperature:

Torsion test:

Duplicate the tension test and change the mesh by select two faces sizing of 1.5mm

select centere face create new coordinate system as type of cylindrical at the cente

insert displacement

insert fixed support and Run the simulation

Results:

Total deformation:

eqivalent stress:

temperature:

Result comparisson:

	deformation(mm)	stress(Mpa)	temperature(C)
Tension Test	18.002	581.33	272.8
Torsion Test	16.12	647.55	423.18

conclussion :

In Torsion Test more stress and temperatute will developed compared to tensile test.in tesile test more deformation will occur compared to torsion test