Week 2 Railwheel and Track

Objective:

Perform a static structural analysis on the Railwheel and Track setup and

Case 1: Multiply the bearing load by 5 times and compare the results with the load of 100000 N (As done in week 2 video). Compare the Total Deformation, Equivalent stress and the life under both the loads

Case 2: Implement a User defined result and calculate the Total Deformation from this result and check if it is the same as that obtained by the inbuilt result by ANSYS for a load of 100000 N

First we need to perform static analysis by taking bearing load as 100000N

• Go to Engineering Data and select material as structural steel
• Go to geometry and import the model.remove the unwanted portion of gear.
• now go to model and click on edit mechanical APDL will open.
• we have to create two contacts between Rail wheel and track with friction.another one is between railwheel and shaft which is friction less contact

• Create three joints one is fixed and  one is translational joint last one is planar joint for wheel

• generate a mesh size of 50mm all assembly except contacting area of rail wheel and track is 35mm

• Go to analysis settings

• create joint load by selecting  static structural

• Apply bearing load by insert

•  select output parameters of deformation,euivalent stress,equivalent strain and Life of component.

Deformation:

Equivalent stress:

Equivalent strain:

Life:

Case1:Now change the Bearing load 500000N then do the simulation.Check the results 

Deformation:

 

Equivalent strain:

Equivalent stress:

Life:

Case2: Implement a User defined result and calculate the Total Deformation from this result and check if it is the same as that obtained by the inbuilt result by ANSYS for a load of 100000 N.

• from above result we can say that user defined result=sqrt(UX^2+UY^2+UZ^2) is 1001.8 mm which is equal to ansys result 1001.8mm

Result comparisson:

	Stress(MPa)	strain	Deformation(mm)	Life(No of cycles)
when 100000N Bearing load applied	107.64	0.0007542	1001.8	2.78e5
when 500000N Bearing load applied	447.22	0.0031851	1002	7.10e-14

Conclussion:

• From results we can conclude that increasing bearing load can increase stress,strain,deformation and life of the component is reduced drastically.