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Week 4 Challenge
Consider the following operating points of a fuel cell during a short period of operation. 15 W/cm2 3 W/cm2 27 W/cm2 Where would these points go in the diagram below? The power at some points are as follows P1=1V*0A/cm2 =0w/cm2 P2=0.75*0.3= 0.225 w/cm2 P3= 0.6*0.75 =0.45 w/cm2 P4=0.25*1.15 =0.2875 from the above points…
Satish M
updated on 23 Jun 2021
Consider the following operating points of a fuel cell during a short period of operation.
- 15 W/cm2
- 3 W/cm2
- 27 W/cm2
- Where would these points go in the diagram below?
The power at some points are as follows
P1=1V*0A/cm2 =0w/cm2
P2=0.75*0.3= 0.225 w/cm2
P3= 0.6*0.75 =0.45 w/cm2
P4=0.25*1.15 =0.2875
from the above points it is conclude the that power of the fuel cell is oscillating low to high to low form zero current to peak current
The current is changing according to change in load. But the given points is in w/cm2, hence to get the values is in w/cm2, the necessary cells must be connected either in series or parallel.
The point 3w/cm2 is exists at earlier stages of the curve i,e between open circuit loss and rapid drop
The point 27w/cm2 exists at linear drop region
The point 15 w/cmw exists at mass transfer loss due to high current densities.
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Read more Projects by Satish M (26)
Project 1 (Mini Project on Vehicle Direction Detection
Project Title: Vehicle Direction Determination Aim To create a Simulink model of Vehicle Direction Detection as per the Requirement data. General Overview: Identifying the direction of the vehicle is one of the important & diverse features in Autonomous driving & Advanced Driver Assistance Features. This particular sub-feature…
15 Oct 2023 06:26 PM IST
Project 1
Boost Converter (CCM): Vi=20-30V V0=40V Vo/Vi=1/1-D Range of Duty Cycle if Vi is 20 40/20=2 1-D=0.5 D=0.5 If Vi=30 Vo/vi=4/3 1-D=1.33 D=0.33 Calculation of Load Resistor: As per given data P=600W V0=40V R=Vo^2/P R=1600/600 R=2.66 ohm Calcultion of Inductance: Assume fs=100khz current ripple is 20% Inductor current…
10 Nov 2021 06:47 AM IST
Week 4 Challenge
Consider the following operating points of a fuel cell during a short period of operation. 15 W/cm2 3 W/cm2 27 W/cm2 Where would these points go in the diagram below? The power at some points are as follows P1=1V*0A/cm2 =0w/cm2 P2=0.75*0.3= 0.225 w/cm2 P3= 0.6*0.75 =0.45 w/cm2 P4=0.25*1.15 =0.2875 from the above points…
23 Jun 2021 08:23 AM IST
Week 7 Challenge
The vehicle parameters for modeling in MATLAB/Simulink is as follows fr = coefficient of rolling resistance =0.015g = gravitational acceleration=9.81M = vehicle mass=1910.2kgQ = air density=1.29Cx = aerodynamic drag coefficient=0.4170A = frontal surface area of the vehicle=2.86 The simulation is divided into four sections…
20 May 2021 11:58 AM IST
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