Project 1

Boost Converter (CCM):

Vi=20-30V

V0=40V

Vo/Vi=1/1-D

Range of Duty Cycle

if Vi is 20

40/20=2

1-D=0.5

D=0.5

If Vi=30

Vo/vi=4/3

1-D=1.33

D=0.33

Calculation of Load Resistor:

As per given data

P=600W

V0=40V

R=Vo^2/P

R=1600/600

R=2.66 ohm

Calcultion of Inductance:

Assume fs=100khz

current ripple is 20%

Inductor current = IL= Vin/(1-D)^2 R

IL=20/(1-0.5)^2 * 2.66

IL=20/0.25*2.66

IL=30.07A

L>(Vin/fs*Delta`IL)D

Delta IL=0.2*30.07.

Delta IL=6.014.

L>30/(100e3*6.014)*0.5

L>2.4942e-05

L=30microH

Calculation of Capacitor :

Assume 10 % ripple at outpur voltage

C=D/(Rfs(DeltaVo/Vo))

C=0.5/(2.66*100e3*0.1)

C= 1.8797e-05 F

C=18.8 microF

Output Voltage: