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Project 1
Boost Converter (CCM): Vi=20-30V V0=40V Vo/Vi=1/1-D Range of Duty Cycle if Vi is 20 40/20=2 1-D=0.5 D=0.5 If Vi=30 Vo/vi=4/3 1-D=1.33 D=0.33 Calculation of Load Resistor: As per given data P=600W V0=40V R=Vo^2/P R=1600/600 R=2.66 ohm Calcultion of Inductance: Assume fs=100khz current ripple is 20% Inductor current…
Satish M
updated on 10 Nov 2021
Boost Converter (CCM):
Vi=20-30V
V0=40V
Vo/Vi=1/1-D
Range of Duty Cycle
if Vi is 20
40/20=2
1-D=0.5
D=0.5
If Vi=30
Vo/vi=4/3
1-D=1.33
D=0.33
Calculation of Load Resistor:
As per given data
P=600W
V0=40V
R=Vo^2/P
R=1600/600
R=2.66 ohm
Calcultion of Inductance:
Assume fs=100khz
current ripple is 20%
Inductor current = IL= Vin/(1-D)^2 R
IL=20/(1-0.5)^2 * 2.66
IL=20/0.25*2.66
IL=30.07A
L>(Vin/fs*Delta`IL)D
Delta IL=0.2*30.07.
Delta IL=6.014.
L>30/(100e3*6.014)*0.5
L>2.4942e-05
L=30microH
Calculation of Capacitor :
Assume 10 % ripple at outpur voltage
C=D/(Rfs(DeltaVo/Vo))
C=0.5/(2.66*100e3*0.1)
C= 1.8797e-05 F
C=18.8 microF
Output Voltage:
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Read more Projects by Satish M (26)
Project 1 (Mini Project on Vehicle Direction Detection
Project Title: Vehicle Direction Determination Aim To create a Simulink model of Vehicle Direction Detection as per the Requirement data. General Overview: Identifying the direction of the vehicle is one of the important & diverse features in Autonomous driving & Advanced Driver Assistance Features. This particular sub-feature…
15 Oct 2023 06:26 PM IST
Project 1
Boost Converter (CCM): Vi=20-30V V0=40V Vo/Vi=1/1-D Range of Duty Cycle if Vi is 20 40/20=2 1-D=0.5 D=0.5 If Vi=30 Vo/vi=4/3 1-D=1.33 D=0.33 Calculation of Load Resistor: As per given data P=600W V0=40V R=Vo^2/P R=1600/600 R=2.66 ohm Calcultion of Inductance: Assume fs=100khz current ripple is 20% Inductor current…
10 Nov 2021 06:47 AM IST
Week 4 Challenge
Consider the following operating points of a fuel cell during a short period of operation. 15 W/cm2 3 W/cm2 27 W/cm2 Where would these points go in the diagram below? The power at some points are as follows P1=1V*0A/cm2 =0w/cm2 P2=0.75*0.3= 0.225 w/cm2 P3= 0.6*0.75 =0.45 w/cm2 P4=0.25*1.15 =0.2875 from the above points…
23 Jun 2021 08:23 AM IST
Week 7 Challenge
The vehicle parameters for modeling in MATLAB/Simulink is as follows fr = coefficient of rolling resistance =0.015g = gravitational acceleration=9.81M = vehicle mass=1910.2kgQ = air density=1.29Cx = aerodynamic drag coefficient=0.4170A = frontal surface area of the vehicle=2.86 The simulation is divided into four sections…
20 May 2021 11:58 AM IST
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