Project 1

AIM:

To design a multi-storey Residential Building located in Bangalore using STAAD Pro Connect Edition. 

INTRODUCTION:

•  A beam is a structural element that primarily resist loads applied laterally to the beams axis.
•  Beams are used to support the weight of floors ceilings and roofs of abuilding and to transfer the load to a vertical load bearing element of the structure.
•  Beams are flexural members the beam takes to load by bending and flexural members carry bending moment and shear force.The design of beams is for bending moment,Shear force,Torsion.
• Clumn is a compression member the effective length of which exceeds three times the least lateral dimension.
• Columns are structural elements used primarily to support compressive loads.
• Column transmit the loads into foundation.
• The columns are different shapes like rectangle,circular square,octagonal etc.

PROCEDURE:

 DBR - Design Basis Report 

 Step 1. Given data 

 Step 2. Creating Geometry of the Model 

i) Create the geometry of the model 

ii) As it is Residential Building and it has following dimensions

iii) L = 16m 

iv) B = 25 m

v) H = 30 m

vi) Once geometry is created assign support condition as Fixed 

 Step 3. Material Specification 

 i) Assume the size of beams - 0.300 x 0.450 m

ii) Assume the size of columns - 0.500 x 0.500 m

 Step 4. Loads 

 Calculation of Loads:

 1) Calculation of Dead Load - IS 875 part 1

 i)Dead load on Floor 

i) Dead load due to slab = 0.150 x 25 

                                        = 3.750 Kn/m2

ii) Partitions = 1.5 Kn/m2

iii) Floor Finish = 2.5 Kn/m2

iv) Miscellaneous = 1 Kn/m2

v) Total Floor Load = 8.75 Kn/m2

 ii) Dead load on Roof 

i) Dead load of Roof Slab = 3.75 Kn/m2

ii) Insulaions and Water Proofing = 0.5 Kn/m2

iii) MEP Services = 0.5 Kn/m2

iv) Miscellaneous = 0.5 Kn/m2

v) Total Roof Load = 5.25 kn/m2

 2) Live Load - IS 875 part 2 

i) For Residential Building LL = 3 Kn/m2

 ii) For Roof = 1.5 Kn/m2

 3) Calculation of Wind load 

 i) Design Wind Speed 

 We know that 

Vz = Vb x k1 x k2 x k3 x k4 

 where , 

Vb=Basic wind speed (m/sec) 

K1=Risk coefficient (Table 1 of IS 875 (Part 3)-2015)

K2 = Terrain Roughness and height factor 

K3=Topography factor (Clause 6.3.3 of IS 875 (Part 3)-2015)

K4 =Importance factor for Cyclic Region

 AS Vb = 33 m/s ( Darjeeling ) Is 875 

K1 = 1 

K2 = 1.15 ( Ht for 30m) ( Category 1) 

K3 = 1

K4 = 1

 Therefore , 

 Vz = 33 x 1 x 1.15 x 1 x 1

    = 37.95 m/s

 ii) Wind Pressure = Pz

 Pz = 0.6 x Vz ^2 

    = 0.6 x 37.95 x 37.95

    = 864.121 N

    = 0.864 Kn 

 Similarly we can calculate for different heights 

 4) Calculation of Seismic load 

1) Design Base Shear 

 VB = Ah x W 

 where ,

Ah = Horizontal Coefficient of acceleration 

W = Seismic Weight 

 ii) Ah can be calculated by using formula 

 Ah = Z/2 x Sa/g x I/R

 As given building in location is in Bangalore - 

a) Seismic Zone (Z)  - Zone II ( 0.10 ) 

b) Soil condition or Soil type (Sa)  - Hard Soil 

c) Importance Factor - 1 ( For Residential Building ) 

d) Response Reduction Factor - 5 ( SMRF) 

2) 

i) Now we have to calculate the Sa/g ( Spctral Acceleraion cpefficient) which depends on Type of soils .

 ii) For hard Soil - 

 Sa/g = 1 + 15 T .........................0.00 < T < 0.10

           2.50 ...............................0.10 < T < 0.40

           1 / T ..............................0.40 < T < 4.00 

 iii) First we have to calculat Time peroiod in x and y direction  (20x 30m) 

 Tx = $\frac{0.09h}{\sqrt{d}}$

       =  $\frac{0.09X30}{4}$

Tx     =   0.68 sec 

 Ty = $\frac{0.09h}{\sqrt{d}}$

     =  $\frac{0.09X30}{5}$

 Ty    =  0.54 sec 

Considered Max time period i.e Tx = 0.68 sec 

 Sa / g = 1/T

           = 1.47 

 So put all the values in Ah equation 

 Ah = 0.10/2 x 1.47 x 1/5

 Ah = 0.0147 

3) Calculation of Seismic weight 

 i) Area of each Floor = 16 x 25

                               = 400 m^2

 ii) Due to Dead Loads , Typical Floor = DL = 8.75 Kn/m^2 

 So Total Dead load of all floors = 8.75 x 400

                                                 = 3500 Kn

iii) Due to Dead Loads ,Roof  = DL of roofs = 5.25 Kn/m^2 

So Total Dead load of all floors = 5.25 x 400

                                                  = 2100 Kn

iv) Due to Live Loads , Typical Floor = LL = 3 Kn/m^2 ( Is 875 part 2) 

 But as per IS 1893:2016 If Live load is greater than 3 Kn/m^2 we have to reduced LL by 50%

 Therefore reduced it by 50% 

 LL = 1.5 Kn/m^2

Total Live load for all floors = 1.5 x 600

                                        = 600 KN 

 v) Due to Live Loads , Roof - AS per IS 1893 : 2016 Live load due to roof is neglected in calculation of seismic weight .

 vi) Total Seismic Weight = W = DL + LL + DL

                                          = (3500+ 600) x 7 + 2100

                                          = 30800 Kn 

4)  Design Base Shear VB 

 VB = Ah x W

     = 0.0147 x 30800

     = 452.76 Kn 

Step 5) 

 i)WL + X direction

ii) WL -X direction 

iii) WL +Z direction 

iv) WL -Z direction 

v) DL and LL 

Step 6) Design of slab element 

 Step 1 ) Data 

i) Once setting is done 

ii) Click on Design and Click on Auto Design 

iii) All the load cases which we have defined will come 

iv) Select the type of load 

v) Click on Okay 

vi) Click on Add from Ananlysis option for adding Load combinations

 vii) Click on Okay 

Step 7) 

i) Once you click Okay 

ii) Software will design the beams 

iii) As we can see all the beams are in Green colour

iv) So all the beams are passed 

v) And We can see the design also 

 Step 8) Beam Design Calculation Report 

Step 9) - Preparing BBS 

i) For BBS

ii) Click on BBS 

iii) Click on Generate BBS 

iv) We can select All beams or we can select group wise 

v) Select B1-B2-B3-B4

vi)Click on Generate 

 Step 10) 

i) Click on Report 

ii) Click on Design Summary 

Similarly Follow the same procedure for Column Also:

 i) Create a New Project 

 As we can see grids are automatically created with column mark 

iDesi gn Foundations using STAAD Foundation.

 Step 1) 

i) Open the model 

 ii) Click on Staad Foundation 

iii) Create a Job 

 iv) Enter concrete and reinforcement details

 v) Enter Soil property 

vi) Click on Design 

vii) Once design is completed you will see the details of footing 

viii) Design output of footing 

 RESULTS:

The multi-story residential building located in banglore has been designed and analysed.

 i) DBR is prepared from Step 1 to Step 4 ( Input Details ) 

ii) Structural Model has been created and Analyze it successfully 

iii) DL, LL, WL and EQL load are calculated in above steps as per IS 875 standards 

iv) Slab element is designed and calculated in above steps 

v) Beam and Column is designed in RCDC and Calculation sheet is ptovided in above steps

vi) BBS is also prepared 

vii) Foundation is designed in Staad Foundation