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Aim To setup a full hydrodynamic case of PFI and perform simulation to determine the engine characteristics Introduction Using the boundary flagging and mesh motion obtained from the no-hydro case, this project involves spray and combustion modeling to perform a full hydrodynamic case of Port Fuel Injection system. The…
Vignesh Varatharajan
updated on 23 Feb 2021
Aim
To setup a full hydrodynamic case of PFI and perform simulation to determine the engine characteristics
Using the boundary flagging and mesh motion obtained from the no-hydro case, this project involves spray and combustion modeling to perform a full hydrodynamic case of Port Fuel Injection system. The case is simulated using a supercomputer and the output files are post-processed for engine characteristics.
Bore =0.086 m
Stroke = 0.09 m
Connecting rod length = 0.18 m
RPM = 3000
Run parameters
Simulation mode: No Hydro
Simulation time parameters
Start time: -520 deg
End time: 120 deg
Piston temperature - 450K
Liner temperature - 450K
Head temperature - 450K
Spark Plug temperature - 550K
Spark Plug electrode temperature - 600K
Exhaust ports temperature - 500K
Exhaust outflow - 1 bar
Exhaust outflow temperature - 800k
Exhaust species concentration - Calculate the stoichiometric condition
Exhaust valve top temperature - 525K
Exhaust valve angle temperature - 525K
Exhaust valve bottom temperature - 525K
Intake port - 1 temperature 425K
Intake port - 2 temperature 425K
Inflow pressure - 1 bar total pressure
Inflow temperature - 363K
Inflow species - Air
Intake valve top temperature - 480K
Intake valve angle temperature - 480K
Intake valve bottom temperature - 480K
Intake port - 1 (closer to combustion chamber)
ic8h18 - 0.025508
o2 - 0.20157
n2 - 0.77292
Temperature - 390k
pressure - 1 bar
Intake port - 2 (away from combustion chamber)
Air
Temperature - 370K
Pressure - 1 bar
Cylinder
Pressure - 1.85731 bar
Temperature - 1360K
Stoichiometric composition
Fuel flow rate = 7.5e-4 Kg/second
Injection start time = -480.0
Injection duration = 191.2
Fuel temperature = 330K
Nozzle diameter = 250 micro-meter
Circular injection radius = Nozzle radius
Spray cone angle = 10
Center 0.0823357 0.00100001 0.07019
Align Vector -0.732501 0.210489 -0.647408
Center 0.0823357 -0.00099999 0.07019
Align Vector -0.732501 -0.210489 -0.647408
Center 0.0823357 -0.0004 0.07019
Align Vector -0.5 -0.2 -0.647408
Center 0.0823357 0.0003 0.07019
Align Vector -0.5 0.2 -0.647408
Start of spark = -15 deg
Spark duration = 10 deg
Spark location = -0.003 0 0.0091
Spark radius = 0.0005m
With the inputs provided in the challenge description, find out the following:
4. Setup
4.1 Spray modeling
Materials -> Parcel simulation -> Pre-defined parcels-> IC8H18
We select IC8H18 because its characteristics are similar to that of gasoline
Species-> Parcel- > Add IC8H18
Physical models-> Spray modeling
4.1.1 Parameters of spray modeling
Parcel distribution: Evenly throughout the cone
Turbulent dispersion: O’Rourke model
Injector-> Add injector with IC8H18 parcel with mass fraction = 1.0
4.1.2 Rate shape
Rate shape is given to effectively control the flow rate of fuel injected into the combustion chamber. The graph shows the normalized profile using which Converge determines the mass flow rate for the given conditions of injection duration and mass of fuel injected.
4.1.3 Spray rate preview
It is to be noted that the given set of inputs do not include the injection pressure which is the most important parameter in design of an injector. This is because the given set of inputs can be used to calculate the injection pressure and using the spray rate preview tool in Converge, the below data can be obtained:
4.1.4 Injector models
Injector model-> Kelvin Helmholtz and Rayleigh- Taylor model (RT)
Set recommendations for-> Gasoline PFI
Injector temperature-> 330 K
4.1.5 Injector fuel mass calculation
The mass flow rate of injector is specified as kg/sec. However, during the crank angle rotation of 720 deg, the injection occurs only for 191.2 deg.
Considering engine speed = 3000 rpm = 50 rps = 18000 deg/s
For 1 deg rotation, time taken = 5.55 e-5 sec
For 720 deg, time taken = 0.04 sec
Given, Injector fuel rate = 7.5e-4 Kg/second
Therefore, total mass of fuel injected in one cycle = 3 e-5 kg
The default location of the injector is set up at the origin. For the given case, we set up the nozzles at intake region -1 as shown in the figure below using the nozzle positions given in the data sheet.
4.1.6 Fixed embedding for Injector
Entity-> Injector
Scale-> 4 ; Inner radius: 0.001 and outer radius: 0.002 m ; Length = 0.02 m
Combustion model-> SAGE combustion model with multi-zone model
Combustion start time is just before sparking. Based on given data, start time= -17 deg
Combustion end time is the time when exhaust valves are opened, end time= 130 deg
Physical models-> Source/sink modeling
Add two energy sources with sphere shape. We use two energy sources to map the below profile of spark ignition.
Source-1 duration: -15 to 14.5 deg
Source-2 duration: -15 to 5 deg
Black line refers to the experimental profile. To simulate this, we break it down and approximate it represented by the red curve.
To minimize numerical diffusion in the source terms, we add fixed embedding of spherical entity with scale-5 embedded with a larger sphere with scale-3 over the sources.
Velocity AMR and Temperature AMR in intake and cylinder regions are applied.
The timing map show the entire case setup timeline with events, embedding and mesh refinement duration. This can be used to verify the case setup in accordance with the given engine parameters.
9.1 Mesh motion
9.2 Parcel
The liquid spray drops in the cylinder region plot against the crank angle, as shown below, shows that the parcels are created at the start of the injection. These liquid droplets atomize during the compression stroke and are ignited using the spark.
At the end of the combustion stroke, it can be noted that there is no liquid spray drops in the cylinder region.
However, in the intake region close to the intake valves, there is residual fuel accumulation at the end of the intake stroke. This is captured in the plot below. The mass of IC8H18 at the end of the intake stroke is approximately 3% of the injected fuel.
9.3 Temperature
The mean temperature plot signifies the effect on combustion on the temperature. This data can be used to perform conjugate heat transfer analysis by constraining the case with boundary condition equivalent to the temperature profile obtained.
9.4 Pressure
The pressure plot indicates the combustion start and finish. Also, the peak pressure inside the cylinder region is found to be 3.88 MPa.
9.5 Emissions
The graph above shows the emissions in the cylinder region during the periodic cycle. This data can be used to benchmark the engine and design modifications and their impact on emissions can be iteratively determined.
9.6.1 What is the compression ratio of this engine?
Dataset |
Y min |
Min location |
Y max |
Max location |
Volume (m^3) |
5.70294e-05 |
-360.221 |
0.00057422 |
-176.239 |
From the graph, min volume = 5.70294 e-05 m^3 and max volume = 5.7422 e-04 m^3
Compression ratio = (Vs + Vc)/ Vc
Vs, the stroke volume is the difference between the maximum and minimum volume
Vc, the clearance volume is the minimum volume at the Top dead centre
Vs = 5.12872E-04 m^3 and Vc = 5.74E-05 m^3
Therefore compression ratio = 9.93
9.6.2 Why do we need a wall heat transfer model? Why can't we predict the wall temperature from the CFD simulation?
In IC engine analysis, the mass, momentum and energy conservation equations in the regions are solved using the turbulence and combustion model. As we are more interested in the fluid region and not the solid region, we treat the walls as adiabatic. This helps in arriving at a convergent solution using less computational resources without affecting the combustion characteristics. It is to be noted that heat equations are found to converge much faster than that of the solids, and treating walls as adiabatic helps us save time.
For studying the wall temperature, CHT analysis is performed by initializing the wall material with suitable heat transfer coefficient. Using this, the heat loss from through the walls is determined and the combustion efficiency calculated again.
9.6.3 Calculate the combustion efficiency of this engine
The heat release rate captures the energy that is released during the combustion. Using the integrated heat release, the total energy released during the combustion process can be determined.
Total energy from combustion process = Max value of Integrated HR curve = 1241.16 J
Energy content of the fuel = Mass of fuel x Lower Heating value of IC8H18
LHV of IC8H18 = 44.8 MJ/kg, Mass of fuel = 3e-5 kg
Combustion efficiency = Total energy from combustion process / Energy content = 92.4%
9.6.4 Use the engine performance calculator, to determine the power and torque for this engine
Tools -> Engine performance calculator
Work done = 486.64 N-m
Engine speed = 3000 rpm = 18000 deg/sec
Combustion duration = 240.199 deg
Total time = 0.01334sec
Power = Work done/Time
Power = 35.13 KW
We know, Power (P) = (2*π*N*T)/60
Therefore, torque T = P * 60 / (2*π*N) = 111.879 N-m
9.6.5 What is the significance of ca10, ca50 and ca90?
CA10 represents the crank angle at which 10% of the combustion is completed. Similarly, CA50 and CA90 gives the crank angle at which 50% and 90% of combustion is completed.
CA10 denotes the start of the combustion or ignition of fuel. The difference between the start of fuel injection and CA10 gives the ignition delay. CA50 denotes the end of premixed combustion and start of diffusion combustion of fuel in the chamber. CA90 denotes the end of the combustion and the difference between CA90 and CA10 gives the combustion duration. These values are also useful in validating the results with the experimental values.
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