Section Modulus calculation and optimization

SECTION MODULUS

              It is the ratio between moment of inertia of the beam cross section about the neutral

to the distance of extreme fiber from the neutral axis

           Section modulus is a geometric property for a given cross-section used in the design of beams or flexural members

S = I/Y

Where

I = moment of inertia

Y = distance of the extreme fibre from the neutral axis

AIM

   To calculate the section modulus for the created hood design and modify the design to

increase the strength

DESIGN 1

 

for the first design first the moment of inertia value I= 2.868e+5 mm^4

the measured distance of the extreme fibre is L = 875.30mm So, Y = L/2

                                                                  Y = 437.65mm

SECTION MODULUS FOR DESIGN 1 S= 2.868e+5/437.65

                                                      = 655.3mm^3

DESIGN 2

      

The moment of inertia for the 2nd Design I = 3.461e+5 mm^4

SECTION MODULUS FOR DESIGN 2

                                        S = 3.461e+5/437.65

                                           = 790.81mm^3

By comparing the design 1& 2

                The design 2 is having high moment of inertia by comparing design 1

CONCLUSION

         By increasing the distance between the inner panel and outer panel we will get more strength.