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Project 1 …
Sridharan p
updated on 20 Jan 2023
Project 1
Loss calculation for a DC/DC converter-MATLAB
EV REFRESHER
Q.1
Solution:
BOOST-CONVERTER:
A boost converter (step-up converter) is a DC-DC power converter that steps up voltage (while stepping down current) from its input (supply) to its output (load).
It is a class of Switched mode power supply (SMPS) containing at least two semiconductors (a diode and a Transistor) and at least one energy storage element: a capacitor, inductor, or the two in combination.
To reduce voltage ripple, filters made of capacitors (sometimes in combination with inductors) are normally added to such a converter's output (load-side filter) and input (supply-side filter).
Boost Converter Schematic
Simulink Model:
The following blocks:
Conduction Losses:
Conduction losses are a result of device parasitic resistances impeding the DC current flow in a DC/DC converter. These losses are in direct relationship with the duty cycle.
When the integrated high-side MOSFET turns on, the load current flows through it. The drain-to-source channel resistance (RDSON) causes power dissipation.
Formula:
Conduction Losses: Pc= I² * R *D
were,
p= Power Dissipation
I= Current through MOSFET
R= Resistance in Ohm
D=Duty Cycle= Vout / Vin
Diode losses:
The diode is forward-biased when the integrated MOSFET turns off. During this time, the inductor current ramps down through the output capacitors, the load and the forward-biased diode. Since the load current is now conducting through the diode, there will be power dissipation in Diode.
This will be calculated by using below
Formula:
Diode Losses: P= Vf * I* (1-D)
were,
Vf= forward voltage
I= Current output
D=Duty Cycle= Vout / Vin
Induction Losses:
The conduction losses depend on the load current. With heavier loads, the conduction loss in the MOSFET increases and is the dominating factor. Conduction losses plus switching, driver and internal low-dropout regulator (LDO) losses lead to a considerable generation of heat.
These losses can be calculated by using the below
Formula:
Pd= I² * R + {(rl / 12) (D* Vin / F*L)}
were,
I= Current output
D=Duty Cycle= Vout / Vi
F= Frequency
L= Inductance value
Capacitance losses:
While getting the output through the capacitor we can get some power dissipation in capacitor also.
this power dissipation is determined by using the following
Formula:
Pc= {rc* D*(1-D) I² + {rc / 12(1-D)}} *{(Din / C*F)}
were,
I= Current output
D=Duty Cycle= Vout / Vi
F= Frequency
C= Capacitance value
Simulink Model:
Voltage Measurement:
Output: (Scope)
MOSFET VOLTAGE AND CURRENT:
The Mosfet Current Graph will be the top graph from the one above.
The voltage graph will be in the bottom graph.
We can see from the graph that the duty cycle ratio is 0.5.
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