Challenge

Week 4 Challenge

1)

Aim: To Apply loading to the structure

Load Calculations:

a) Dead load of 1.2 Kn/m2

b) Finishes= 50mm * 24Kn/m3 =1.2Kn/m2

c) Brickwall Load= 0.15*20*5.2 = 15.6 Kn/m ( Ground to Intermediate Floor)

d) Brickwall load= 0.15*20*6.8 = 20.4 Kn/m2 ( Intermediate to roof Floor)

e) Brickwall load= 0.15*20*4.8 =14.4 Kn/m2 ( Roof to top Floor)

f) Roof load= 1.5Kn/m

g) Ceiling load= 0.3Kn/m

Procedure:

1.Opening TEKLA and in load defining the following load cases.

2. Defining the load combinations.

3. Selecting Load as dead and selecting the area load and entering the value of 1.2Kn/m applying the load from ground floor to the roof floor slabs.

4. Selecting Load as dead and selecting the Full udl load and applying the brickwall loads

Brickwall Load= 0.15*20*5.2 = 15.6 Kn/m ( Ground to Intermediate Floor)

Brickwall load= 0.15*20*6.8 = 20.4 Kn/m2 ( Intermediate to roof Floor)

Brickwall load= 0.15*20*4.8 =14.4 Kn/m2 ( Roof to top Floor)

5. Applying a roof load of 1.5Kn/m to the roof.

2)

Calculate live load in design report based on IS code and apply live load on the model

  • Assume the loading based on IS 875
  • Roof loading
  • Consider equipment loading as 5KN per sq m

Answer:

Ground Floor Rooms:

Stair case= 5KN/m^2

Workshop= 5KN/m^2 (Considering Light Machinery)

Corridor= 5KN/m^2

Meeting Room= 5KN/m^2

Store Room= 5KN/m^2

Toilet= 2KN/m^2

Canteen= 3KN/m^2

Office= 3KN/m^2

Conference= 5KN/m^2

Equipment= 10KN/m^2

First Floor Rooms:

Stair case= 5KN/m^2

Restroom= 2KN/m^2

Meeting= 5KN/m^2

Administration Room= 5KN/m^2

Office= 3KN/m^2

Toilet= 3KN/m^2

Live load applied= 10KN/m^2 on the slab for equipment room.

Live load applied= 5KN/m^2 on the slab for staircase.

Live load applied= 10 KN/m^2 on the slab for Equipment room.

Live load applied= 3 KN/m^2 on the slab for Office room.

  1. Generate a calculation for 5T crane loading based on following inputs
  • Centre to Centre of wheel = 10m
  • Weight of crab = 40 KN
  • Number of wheels = 4
  • Wheel base = 2m

Answer:

Crane capacity= 50KN

Self weight of crane girder excluding trolley= 40KN

Weight of trolly Car or Crab= 10 KN

Approximate minimum approach of the crane hook to gantry girder= 1m

c/c distance between gantry rails= 14m

C/c distance between column= 5.5m

Self weight of rail section= 300N/m=0.3KN/m^2

Yield stress of steel= 250 N/m^2= 0.25 KN/m^2

Wheel base= 2m

To find maximum wheel load of the crane:

Maximum point load on the crane= 50+10=60 KN

Self weight of crane= 40KN

To convert this in to UDL= (self weight of crane/ c/c distance between gantry rails)

= 40KN/10m = 4 KN/m

Consider the moment about B

RAx10-60x9-4x10x5=0

RA= 75.85 KN

Maximum wheel load on each wheel= 75.85/2= 37.92=38 KN

For Calculation of maximum bending moment

1. Considering the Dead loads

Assume self weight of gantry girder as 1.5 KN/m

Given self weight of rail section= 0.3 KN/m

Total dead load= 1.5+0.3= 1.8 KN/m

For absolute maximum bending moment the load and the resultant are equidistant from mid-span.

BM due to deadload M1= wl^2/8= 1.8x5.5^2/8 = 6.81 KN-m

2. Considering the live loads

Taking moments about C

RDx5.5-75.85x3.4375-75.85x0.6875=0

RD= 56.9 KN

Taking moments about D

RCx5.5-75.85x4.8125-75.85x2.0625=0

RC= 94.81 KN

Maximum bending moment will be below wheel load at M2= RDx2.0625

=56.9x2.0625

=117.35 KN-m

Impact load= 10% of maximum static wheel load

Maximum BM due to impact,M3=10% of M2

=0.1x117.35=11.735 KN-m

M=M1+M2+M3=6.81+117.35+11.735

=135.90 KN-m

For calculation of Maximum Shear Force due to vertical loads

1. For Dead load

Shear force due to self weight V= wl/2= 1.8x5.5/2

=4.95KN

For maximum shear force due to wheel loads,one of the wheel loads is at the support.

2. For Live loads

Taking moments about F

REx5.5-75.85x5.5-75.85x2.75=0

RE= 113.775 KN

3. For Impact loads

Impact load= 10% of maximum wheel load

Maximum shear force due to impact=0.1x113.775=11.38KN

Total Maximum shear force= 4.95+113.775+11.38=130KN

Lateral Load Analysis

Lateral load=5% of (the weight of the trolley+weight lifted by the crane)

=0.05x(10+50)

=3 KN

For one wheel,the lateral load= 3/4=0.75KN (since we have four wheels)

Maximum bending moments and shear force can be calculated by proportion method:

Maximum horizontal reaction due to lateral force by proportion at C

= (Lateral forcexlateral force due to reaction at C due to vertical load)/max wheel load due to vertical load

=0.75x56.9/75.85

=0.56 KN

Maximum horizontal reaction due to lateral force by proportion at D

= (Lateral forcexlateral force due to reaction at D due to vertical load)/max wheel load due to vertical load

=0.75x94.81/75.85

=0.94 KN

Total Lateral load=0.56+0.94=1.5 KN

Bending moment due to lateral load=0.75x117.35/75.85=1.16 KN-m.

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