Challenge

Section Modulus calculation and optimization

AIM : To study on section modulus calculation and design a new hood with improved strength

SECTION MODULUS :

                              Section modulus represents the strenght of a given component,higher the value higher its strength.

it is the ratio of moment of inertia about neutral axis with distance from the outer most fibre to the neutral axis

unit of section moduls is mm4

section modulus ,S = I/y

where , I = moment of inerta 

            y = distance from the outer most fibre to the neutral axis

MOMENT OF INERTIA :

               The moment of inertia is a measure of how resistant an object is to changes in its rotational motion.also it depicts the resistance offered by a cross section towards bending

moment of inertia ,I of a rectangle = bd3/12

               where,b = breadth

                         d = depth

NEUTRAL AXIS :

                 A layer in a particular cross section where no compression or tension applied

STUDY ON HOOD DESIGN :

                                  Took Intersection of the hood design and conducted section inertia analysis

 

                                                               minimum MOI,I=2.69*105 mm4

distance from the outer most fibre to the neutral axis,y= 876.81/2 = 438.40 mm

                                                          section modulus,S = I/y

                                                                                        =2.69*105 / 438.40

                                                                                        =613.59 mm3

IMPROVED HOOD DESIGN WITH IMPROVED STRENGTH:

                        From the equation of section modulus it is evident that, MOI is directly proportional to section modulus. so increasing MOI results with increased section modulus.

                        analysing the relation of MOI, breadth and three times of depth is directly proportional to MOI.so, improving value of depth improves the value of MOI significantly.

New depth increased hood design with section inertia analysis report :

            min MOI = 2.72*105 mm4

MOI value is increased

section inertia ,S = 2.72*105 / 438.40

                           =620.43 mm3

  CONCLUSION :

                           Comparing results of both designs it is observed that the improved design with increased depth value posses the greater strength. so it is concluded as sectional area of a component is directly proportional to the strength of particular component.

 
Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.