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SECTION MODULUS OF A HOOD Aim: To calculate section modulus of…
Sriram Kumar
updated on 07 Dec 2022
SECTION MODULUS OF A HOOD
Aim:
To calculate section modulus of hood and optimize the design to have improved section modulus.
Section modulus of an Hood:
S=I/Y
where 'I' moment of inertia
'Y' is the distance from the reference line (neutral axis) to one of the extreme end of an object.
That’s why formula represented as above.
By using the same principle i going to calculate the strength of an hood panel.
Here the moment of inertia was calculated by using the NX-software obtained values are
IMAX:-8.485481X105mm4
Imin:-3.18672x103mm4
Total length of 'Y' value was 488.8252mm
So, at neutral axis we need 'Y' value:-Y/2=488.8252/2=244.412mm
1) Section modulus(S):-I/Y=8.485481X105mm4/244.412mm
=3.471X103mm3(Maximum strength).
2) Section modulus(S):-I/Y=3.18672x103mm4/244.412mm
=0.013x103mm3(minimum strength).
So the strength of an hood varies from 0.013x103mm3to 3.471X103mm3
Now, one more trail is that, here the inner panel curve offsetting outside by 1mmi.e increasing in cross sectional area, the results shown below.
I obtained the values of
IMAX:-8.4462X105mm4
Imin:-3.61202x103mm4
Total length of 'Y' value was 488.8252mm
So,at neutral axis we need 'Y' value:-Y/2=488.8252/2=244.412mm
1)Section modulus(S):-I/Y=8.4462X105mm4/244.412mm
=3.455X103mm3(Maximum strength).
2) Section modulus(S):-I/Y=3.61202x103mm4/244.412mm
=0.014x103mm3(minimum strength).
So the strength of an hood varies from 0.014x103mm3to 3.455X103mm3.
Conclusion:
The strength of the material is directly proportional to the moment of inertia, hence increase in sectional area there is have increase in overall mass of an object ,hence have increase in strength.
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