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Aim- To Simulate a Rankine cycle using Extracting Steam and water properties from Xstram Calculating all the state points of the cycle based on User Plotting the T vs S and H vs S plot for the given Theory- A rankine cycle is an idealised Thermodynamic cycle which governs the working of a Heat Engine. In Rankine cycle,the…
Shlok Dixit
updated on 05 Jun 2022
Theory-
A rankine cycle is an idealised Thermodynamic cycle which governs the working of a Heat Engine. In Rankine cycle,the friction losses of a heat engine are neglected. It is a cycle which converts heat into mechanical energy which usually is converted into electrical energy . There are four components in this cycle which work on four different processes.The four components are turbine,Condensor,Pump and Boiler. Rankine cycle is nothing but a modification of Carnot cycle. Ideal Rankine cycle is very useful in steam power plants and gas power plants. To improve the efficiency of Rankine cycle in the steam power plant, there are some changes in Rankine cycle which differs from the Carnot cycle. Firstly, a pump is used in place of condenser to handle only liquid, not a mixture of liquid and vapour.Secondly, exhaust steam from the turbine is completely condensed in the condenser, see in the following diagram
There are four processes in the rankine cycle :
Back Work Ratio:
The fraction of the work produced by the turbine that is consumed by the compressor.
BW ratio=Wp/WtMATLAB PROGRAM FOR RANKINE CYCLE SIMULATOR
clear all close all clc
disp(' RANKINE CYCLE ');
disp('1-2 is Constant pressure heat addition in the boiler'); disp('2-3 is Isentropic Expansion in the Turbine');
disp('3-4 is Constant pressure heat removal in the Condenser'); disp('4-1 is Isentropic compression in the pump');
p1 = input('nValue of pressure at turbine inlet, p1(in bar) = ');
T1 = input('nValue of temperature at turbine inlet, T1(in degree.C) = '); p2 = input('nValue of pressure at condenser inlet, p2(in bar) = ');
% At State 1
h1 = XSteam('h_pT', p1, T1); % Extracting Enthalpy at state pt 1 s1 = XSteam('s_pT', p1, T1); % Similarly
% At State 2
s2 = s1; % Isentropic Expansion
sf2= XSteam('sL_p', p2); % Saturated Liquid Entropy sg2 = XSteam('sV_p', p2); % Saturated Vapour Entropy x2 = (s2-sf2)/(sg2-sf2);
hf2 = XSteam('hL_p', p2); hg2 = XSteam('hV_p', p2); h2 = hf2 + (x2*(hg2-hf2));
% At State 3
p3 = p2; % Constant pressure Heat rejection in Condenser s3= XSteam('sL_p', p3);
h3 = XSteam('hL_p', p3);
% At State 4 s4 = s3;
p4 = p1;
% Work done by turbine Wt = h1 - h2;
% Work done to run pump v3 = XSteam('vL_p', p3); Wp = v3*(p4 - p3)*100;
h4 = h3 + Wp;
%Net work
Wnet = Wt - Wp;
%Heat into the system Qin = h1 - h4;
%Heat out of the system Qout = h2 - h3;
%Thermal efficiency
thermal_eff = (Wnet/Qin)*100;
%Specific Steam Consumption
%SSC = mass flow rate/power SSC = (3600/Wnet);
% Back Work ratio BW = (Wp/Wt)
% Calculation of Temperatures at the state points T3 = XSteam('Tsat_p', p3);
T2 = T3;
Cp4 = XSteam('Cp_ps', p4, s4); Cv4 = XSteam('Cv_ps', p4, s4); k = Cp4/Cv4;
T4 = T3/((p3/p4)^((k-1)/k));
%Calculating Temperature, Entropy and Enthalpy at the vapour and liquid line for plotting T6 = XSteam('Tsat_p', p1);
s5 = XSteam('sL_p', p1); s6 = XSteam('sV_p', p1); h5 = XSteam('hL_p', p1); h6 = XSteam('hV_p', p1); T5 = T6;
%Plotting the saturation curve T = linspace(1,375,1000);
for i = 1:length(T)
sf(i) = XSteam('sL_T', T(i));
sg(i) = XSteam('sV_T', T(i));
hf(i) = XSteam('hL_T', T(i));
hg(i) = XSteam('hV_T', T(i)); end
%Plotting T-s diagram figure(1)
hold on
plot(sf, |
T, 'r','linewidth',1) |
|
||||
plot(sg, |
T, 'r','linewidth',1) |
|||||
plot([s1 |
s2], [T1 T2], 'b', 'linewidth', |
2) |
||||
plot([s2 |
s3], [T2 T3] ,'b', 'linewidth', |
2) |
||||
plot([s3 |
s4], |
[T3 |
T4], |
'b', |
'linewidth', |
2) |
plot([s4 |
s5], |
[T4 |
T5], |
'b', |
'linewidth', |
2) |
plot([s5 |
s6], |
[T5 |
T6], |
'b', |
'linewidth', |
2) |
sc1 = linspace(s6, s1, 1000); for l = 1:length(sc1)
Tc1(l) = XSteam('T_ps', p1, sc1(l)); end
plot(sc1, Tc1, 'b', 'linewidth', 2) text(s1+0.1, T1, '1')
text(s2+0.1, T2, '2')
text(s3, T3-20, '3')
text(s4, T4+20, '4')
title('Temp vs Entropy plot') xlabel('Entropy ,S (Kj/kgk')
ylabel('Temperature (degree C) ') legend('Saturation curve')
%Plotting h-s diagram figure(2)
hold on
plot(sf, hf, 'k', 'linewidth', 1)
plot(sg, hg, 'k', 'linewidth', 1)
plot([s1 s2], [h1 h2], 'r', 'linewidth', 2)
plot([s2 s3], [h2 h3], 'r', 'linewidth', 2)
plot([s3 s4], [h3 h4], 'r', 'linewidth', 2) hc = linspace(h4, h5, 100);
for r = 1:length(hc)
sch(r) = XSteam('s_ph', p1, hc(r)); end
plot(sch,hc, 'r', 'linewidth', 2)
plot([s5 s6], [h5 h6], 'r', 'linewidth', 2) for m = 1:length(sc1)
hc1(m) = XSteam('h_ps', p1, sc1(m)); end
plot(sc1, hc1, 'r', 'linewidth', 2) text(s1+0.1, h1, '1')
text(s2+0.1, h2, '2')
text(s3, h3-100, '3')
text(s4, h4 +200, '4')
title('Enthalpy vs Entropy plot') xlabel('Entropy , S (KJ/kgk) ')
ylabel('Enthalpy , H (KJ/kg)')
legend('Saturation curve','location','northwest')
% Displaying the Results in the Command Window: disp('Results');
p1 = p1; T1 = T1;
p2 = p2;
disp('At stage point 1');
n1 = sprintf('P1 is %.3f bar',p1); disp(n1);
n2 = sprintf('T1 is %.3f C',T1); disp(n2);
n3 = sprintf('h1 is %.3f kJ/kg',h1); disp(n3);
n4 = sprintf('s1 is %.3f kJ/kgK',s1); disp(n4);
disp('At stage point 2');
n11 = sprintf('P2 is %.3f bar',p2); disp(n11);
n21 = sprintf('T2 is %.3f C',T2); disp(n21);
n31 = sprintf('h2 is %.3f kJ/kg',h2); disp(n31);
n41 = sprintf('s2 is %.3f kJ/kgK',s2); disp(n41);
disp('At stage point 3');
n12 = sprintf('P3 is %.3f bar',p3); disp(n12);
n22 = sprintf('T3 is %.3f C',T3); disp(n22);
n32 = sprintf('h3 is %.3f kJ/kg',h3); disp(n32);
n42 = sprintf('s3 is %.3f kJ/kgK',s3); disp(n42);
disp('At stage point 4');
n13 = sprintf('P4 is %.3f bar',p4); disp(n13);
n23 = sprintf('T4 is %.3f C',T4); disp(n23);
n33 = sprintf('h4 is %.3f kJ/kg',h4); disp(n33);
n43 = sprintf('s4 is %.3f kJ/kgK',s4); disp(n43);
n14 = sprintf('Wt is %.3f kJ/kg',Wt); disp(n14);
n15 = sprintf('Wp is %.3f kJ/kg',Wp); disp(n15);
n16 = sprintf('Wnet is %.3f kJ/kg',Wnet); disp(n16);
n17 = sprintf('Thermal_efficiency is %.2f Percent',thermal_eff); disp(n17);
n18 = sprintf('SSC is %.2f kg/kWh',SSC); disp(n18);
n19 = sprintf('Back work ratio is %.3f ',BW); disp(n19);
The performance of the Heat Engine was calculated and the following Observations were made:
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