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For this challenge, you will have to provide answers to the following questions: Q1. Describe Ahmed's body and its importance. Q2. Explain the reason for the negative pressure in the wake region. Q3. Explain the significance of the point of separation. Ahmed body is a general car body which captures essential car…
mohit tiwari
updated on 17 May 2020
For this challenge, you will have to provide answers to the following questions:
Q1. Describe Ahmed's body and its importance.
Q2. Explain the reason for the negative pressure in the wake region.
Q3. Explain the significance of the point of separation.
Ahmed body is a general car body which captures essential car body features which was firstly described experimentally by Ahmed [1]. Its a simple shape yet efficient to capture the aerodynamic features of automobile. The essential need of doing such simulation is to know the effect of drag which is one of the important parameter for efficient and smooth driving experience. The lower the drag forces the lower the fuel consumption and better the performance.
The rear part of the vehicle has a significant role in manipulating the drag forces. The Ahmed body is shown in figure 1. It has been observed that the slant angle ( ∅ ) greatly affects the drag results. This is majorly due to flow of seperation. Seperation of flow means that the flow instead of being attached or parallel to the surface gets detached from the surface and generates turbulence (by pressure gradient) which creates turbulent friction and hence creates drag force.
Step 1 :- Geometry and enclosure fomation
The dimesnions of the Ahmed body is as shown in figure. For analysis purpose the ahmed body is split into half in order to limit the number of elements during meshing and faster computation.The width of the body is 0.1945 m.
Step 2 :- Meshing
Cases | Description | Primary mesh size (mm) | Local refined mesh size (mm) | Ahmed body mesh size (mm) | Wheel mesh size (mm) | Inflation layer | Growth Rate | Total thickness (mm) | Min mesh quality | Avg mesh quality | Total nodes | Total elements |
Case A | Coarse Mesh with k Epsilon model & y+ = 300 | 120 | 80 | 15 | 10 | 6 | 1.2 | 10 | 0.137677527 | 0.754400827 | 42673 | 125816 |
Case B | Intermediate mesh with k Epsilon model & y+ = 300 | 100 | 70 | 12 | 10 | 6 | 1.2 | 10 | 0.127368705 | 0.770585913 | 71028 | 220825 |
Case C | Fine mesh with k Epsilon model & y+ = 300 | 80 | 60 | 10 | 8 | 6 | 1.2 | 10 | 0.154652863 | 0.780996502 | 102472 | 304076 |
Case D | Fine mesh with k Epsilon model & y+ = 300 | 60 | 50 | 8 | 6 | 6 | 1.2 | 10 | 0.139473029 | 0.788510064 | 168026 | 480383 |
Case E | Coarse Mesh with k Epsilon model & y+ = 200 | 120 | 80 | 15 | 10 | 6 | 1.2 | 7 | 0.16114727 | 0.755929095 | 43460 | 130311 |
Case F | Intermediate mesh with k Epsilon model & y+ = 200 | 100 | 70 | 12 | 10 | 6 | 1.2 | 7 | 0.164583632 | 0.769956141 | 72611 | 230253 |
Case G | Fine mesh with k Epsilon model & y+ = 200 | 80 | 60 | 10 | 8 | 6 | 1.2 | 7 | 0.166350841 | 0.781105117 | 104845 | 318084 |
Case H | Fine mesh with k Epsilon model & y+ = 200 | 60 | 50 | 8 | 6 | 6 | 1.2 | 7 | 0.158934985 | 0.789437863 | 172471 | 506654 |
Step 3 :- Solving.
The input datas are mentioned in the table and the reference values are shown in figure.
Solver | Inlet Velocity (m/s) | Outlet gauge pressure (Pa) | Material | Density (kg/m^3) | Dynamic Viscosity(kg.m/s) |
Pressure based solver with realizable k epsilon model with coupled algorithm and hybrid initilization | 25 | 0 | Air | 1.225 | 1.7894e-5 |
Reference values are extremely important while calculating the drag and lift coefficient.
Area was the frontal area of the ahmed body which is the height * width= 0.29*0.1945 = 0.0564 mm, Length was the total ahmed body length which is 1.044 m.
The velocity was then changed to 25 m/s.
Step 4 :- Results and Post processing
Case A:- Coarse Mesh (1.2 lakh) with k Epsilon model & y+ = 300
Case B:- Intermediate Mesh (2.2 lakh) with k Epsilon model & y+ = 300
Case C:- Fine Mesh (3.0 lakh) with k Epsilon model & y+ = 300
Case D:-Fine Mesh (4.8 lakh) with k Epsilon model & y+ = 300
Case E:- Coarse Mesh (1.2 lakh) with k Epsilon model & y+ = 200
Case F:- Intermediate Mesh (2.3 lakh) with k Epsilon model & y+ = 200
Case G:- Fine Mesh (3.3 lakh) with k Epsilon model & y+ = 200
Case H:- Fine Mesh (5 lakh) with k Epsilon model & y+ = 200
Cases | Description | Drag Coefficient | Lift Coefficient | Error percentage |
Case A | Coarse Mesh with k Epsilon model & y+ = 300 | 0.35935685 | 0.30164448 | 8.896015152 |
Case B | Intermediate mesh with k Epsilon model & y+ = 300 | 0.3502 | 0.30538938 | 6.121212121 |
Case C | Fine mesh with k Epsilon model & y+ = 300 | 0.33549993 | 0.28249514 | 1.666645455 |
Case D | Fine mesh with k Epsilon model & y+ = 300 | 0.31735634 | 0.28797621 | 3.831412121 |
Case E | Coarse Mesh with k Epsilon model & y+ = 200 | 0.35163485 | 0.3138578 | 6.556015152 |
Case F | Intermediate mesh with k Epsilon model & y+ = 200 | 0.34329022 | 0.30230387 | 4.027339394 |
Case G | Fine mesh with k Epsilon model & y+ = 200 | 0.32956883 | 0.29699846 | 0.130657576 |
Case H | Fine mesh with k Epsilon model & y+ = 200 | 0.3250308 | 0.27277282 | 1.505818182 |
Discussion:-
POST PROCESSING PRESSURE AND VELOCITY CONTOURS:-
Figure :- Comparision of the result with the literature [2] result indicating the effect of slant angle on back pressure
DISCUSSION:-
References:-
[1]Ahmed, S. R., et al. “Some Salient Features of the Time -Averaged Ground Vehicle Wake.” SAE Transactions, vol. 93, 1984, pp. 473–503. JSTOR, www.jstor.org/stable/44434262. Accessed 17 May 2020.
[2] Lienhart, H., Stoots, C. and Becker, S., 2002. Flow and Turbulence Structures in the Wake of a Simplified Car Model (Ahmed Modell). New Results in Numerical and Experimental Fluid Mechanics III, pp.323-330.
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