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BlockMesh Drill down challenge

    The main objective is to use the icoFOAM solver to simulate the flow through a backward facing step. Initially, The geometry is generated for a variation of the incompressible cavity flow problem in OpenFOAM.The mesh is generated according to the need of the structure|(i.e with or without grading).  …

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Read more Projects by Om Yadav (16)

Simulation of Flow through a pipe in OpenFoam part 2

Objective:

Objective: Write a Matlab program that takes an angle as input and generates a blockMesh file for the given angle 10,25,45 degree.  To compare the above results and discuss findings     Calculation  and Assumption Reynolds Number: 2100 Radius of pipe (r) :0.005 dynamics viscosity of water: 1.002 X 10^-3…

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19 May 2019 05:23 AM IST

  • CFD
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Simulation of Flow through a pipe in OpenFoam part 1

Objective:

    Objective: To write a program in Matlab that can generate the computational mesh automatically for any wedge angle and grading schemes  To show that the velocity profile matches with the Hagen Poiseuille\'s equation For a baseline mesh To show that the velocity profile is fully developed Post process…

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19 May 2019 05:22 AM IST

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BlockMesh Drill down challenge

Objective:

    The main objective is to use the icoFOAM solver to simulate the flow through a backward facing step. Initially, The geometry is generated for a variation of the incompressible cavity flow problem in OpenFOAM.The mesh is generated according to the need of the structure|(i.e with or without grading).  …

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07 Feb 2019 01:44 PM IST

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Simulation of a 1D Super-sonic nozzle flow simulation using Macormack Method

Objective:

   The objective in this project is to write code to solve the 1D supersonic nozzle flow equations using the Macormack Method. The governing equations for both conservative and nonconservative are solved and compared. Also, the iteration number and computational time are compared until the final…

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01 Nov 2018 12:39 AM IST

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    Solving the steady and unsteady 2D heat conduction problem

    Objective:

        RESULT: steady-state analysis  The 2D heat conduction equation by using the point iterative techniques are implemented for  the following methods 1. Jacobi 2. Gauss-seidel 3. Successive over-relaxation where absolute error criteria are 1e-4 Derivation of the different Numerical scheme…

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    01 Nov 2018 12:37 AM IST

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      programming statements mean

      Objective:

      1. A=[1,2,3,4,5] From the above command, we know that all the elements are separated from each other by commas and are enclosed in square bracket, it is called as Row vector .when the above-given row vector is executed in command window then it shows  A=       1  2 3 4  2. B=[1;2;3;4;5]…

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      29 Jan 2018 12:23 PM IST

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        expressions and units for the following variables equations

        Objective:

        -------------------------------------------------------------------------------------------------------- 1. Kinematic viscosity It is defined as the ratio between the dynamic viscosity and density of the fluid. It is denoted by the Greek symbol (v) called \'nu\'. thus mathematically,          …

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        29 Jan 2018 12:21 PM IST

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          4th order approximations of the second order derivative

          Objective:

           --------------------------------------------------------------------------------------------- clear all;close all;clc;% analytical function =(e.^x)*cos(x) % analytical_derivative%f\'\'(x)= (-)*2*(e.^x)*sin(x)x=linspace(pi/3,pi/2,10);for i=1:10 analytical_derivative(i)= (-2)*(exp(x(i)))*(sin(x(i)));end dx=pi/40; e=exp(1);%fourth…

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          26 Jan 2018 12:50 PM IST

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          first second and fourth order approximations

          Objective:

          function out = first_order_approximations(x,dx)% analytical_derivative%f\'(x)=(x^3(cos(x)-sin(x)*3*x^2)/x^6 analytical_derivative=((x.^3*cos(x))-(sin(x)*3*x.^2))/(x.^6); %numerical derivatives forward_differincing = (sin(x)*(x+dx)-sin(x)*(x))/dx; out=abs(forward_differincing - analytical_derivative);end  ----------------------------------------------------------------------------------------…

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          16 Jan 2018 12:55 AM IST

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            numerically and analytically solved solution

            Objective:

            clear all;close all;clc; x=linspace(pi/3,pi/2,10);for i=1:10 analytical_derivative(i)=((x(i)^3.*cos(x(i)))-(sin(x(i)).*3.*x(i).^2))/x(i).^6;end dx=pi/40; %first order approximationforward_differincing =((sin(x+dx)/(x+dx).^3)-(sin(x)/(x).^3))/dx; %second order approximationcentral_differincing =((sin(x+dx)/(x+dx).^3)-(sin(x-dx)/(x-dx).^3))/(2*dx);…

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            15 Jan 2018 09:52 AM IST

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              Simple Pendulum Animation

              Objective:

              Video: https://drive.google.com/open?id=1RMyRpTzHTM8hzB-sVwddRmpiLW3JoOKQ Code: https://drive.google.com/open?id=1jYxW08JpLZRAKvKOXXA4DoCRZnOsb3EC

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              13 Jan 2018 10:42 AM IST

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                n Vs ar Alkane Alkene Alkyne

                Objective:

                https://drive.google.com/open?id=1wYlH9lHTdyS_oZ6stmjuAIPq6jjhRQ9-

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                13 Jan 2018 10:29 AM IST

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                  units

                  Objective:

                  1. Kinematic viscosity It is defined as the ratio between the dynamic viscosity and density of the fluid. It is denoted by the Greek symbol (v) called 'nu'. thus mathematically,                       v=(viscosity/Density) The units of the kinematic viscosity is obtained as…

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                  28 Dec 2017 04:10 AM IST

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                    BOUNDARY CONDITIONS

                    Objective:

                    The boundary condition is a set of limitations that define the behavior of unknown functions on the spatial boundary of the domain. A PDE with a boundary condition is also called a boundary value problem.There are three types of boundary conditions, they are Dirichlet Condition It is types of boundary condition…

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                    27 Dec 2017 07:29 AM IST

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                      command expalantion

                      Objective:

                      1. A=[1,2,3,4,5] From the above command, we know that all the elements are separated from each other by commas and are enclosed in square bracket, it is called as Row vector .when the above-given row vector is executed in command window then it shows  A=       1  2 3 4  2. B=[1;2;3;4;5]…

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                      27 Dec 2017 06:15 AM IST

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                        command expalantion

                        Objective:

                        1. A=[1,2,3,4,5] From the above command, we know that all the elements are seperated from each other by commas and are enclosed in square bracket, it is called as Row vector .when the above-given row vector is executed in command window then it shows  A=       1  2 3 4  2. B=[1;2;3;4;5]…

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                        27 Dec 2017 01:43 AM IST

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