Section Modulus calculation and optimization

Objective:Use the section from your Hood design and calculate the section modulus using the formula S= I/y.

S = I/y

Where,

S = Section Modulus

I = Moment of Inertia

y = distance between the neutral axis and the extreme end of the object

Section Modulus:

The section modulus (S) is geometry property of the cross section used for designing beams and flexural members. It does not represent anything physically.

Neutral Axis: When beam is subjected to pure bending the top most fibres of the beam are subjected to maximum compression, while the bottom most fibre of the beams are subjected to maximum tension.

Case 1:Before Optimization of our original hood design-

The Hood which is already created is imported and the section inertia analysis is done.

We have to make sure that the curve obtained should be a single/closed curve.

MOI (max) = 8.195692506e+05 [mm^4]

MOI (min) = 4.166254347e+03 [mm^4]

As per the section modulus equation,

S = I/Y

I = MOI (min) value is considered

Y =Total distance =487.6076mm

Now S = 4166.254347mm^4/487.6076mm

S1 = 8.54427687 mm^3

2.Before Optimization of our original hood design-

In this case now we optimized our original hood by offsetting the lower curve at the distance of 0.6mm.And perform section inertia analysis we get following changes.

MOI (max) = 8.16563179e+05 [mm^4]

MOI (min) = 4.360818227e+03 [mm^4]

As per the section modulus equation,

S = I/Y

I = MOI (min) value is considered

Y =Total distance =487.6076mm

Now

S = 4360.818227mm^4/487.6076mm

S2 = 8.94343361 mm^3

Conclusion:

After comparing case 1 & case 2, we find that. The section modulus (s1)value of case 2 section modulus (s2) is higher than the case 1.which indicate that As we increase the section area, the moment of inertia & section modulus increases which means strength and load material also increase.