Section Modulus calculation and optimization
Section Modulus calculation and optimization
AIM- TO CALCULATE SECTION MODULUS OF HOOD AND OPTIMIZE THE DESIGN TO HAVE IMPROVED SECTION MODULUS.
SECTION MODULUS IS THE RATIO OF AREA MOMENT OF INERTIA ABOUT NEUTRAL AXIS AND TO THE DISTANCE OF OUTERMOST FIBER FROM THE NEUTRAL AXIS.
Z= I/y
Where,
Z = Section Modulus
I = Moment of Inertia
y = distance between the neutral axis and the extreme end of the object
NEUTRAL AXIS- LAYER IN PARTICULAR CROSS SECTION WHERE IS NEITHER TENSION NOR COMPRESSION.
AREA MOMENT OF INERTIA WILL DEPICT THE RESISTANCE OFFERED BY THE CROSS SECTION TOWARDS BENDING.
STEPS-
- CREATE DATUM PLANE AT THE MIDDLE OF THE HOOD PERPENDICULAR TO THE AREA WHERE FRONTAL IMPACT WILL TAKE PLACE.
- TAKE CROSS SECTION OF HOOD AREA USING INTERSECTION.
- PROJECT THE CROSS SECTION AND MAKE IT CLOSED.
- ANALYSIS THE SECTION.
AS WE TAKE MOI(Min) FOR FACTOR OF SAFETY
I= 2.808*10^5(mm^4)
y= Total length / 2
= 880.1676 / 2
= 440.0838 mm
Z= I/y
= 2.808*10^5 / 440.0838
= 638.06 mm^3
THIS IS THE SECTION MODULUS OF HOOD DESIGN.
FOR OPTIMIZATION OF HOOD DESIGN, WE TRY TO INCREASE THE DEPTH BY 0.5mm.
AFTER OPTIMIZATION
I = 2.844*10^5(mm^4)
y= Total length / 2
= 880.1676 / 2
= 440.0838 mm
Z= I/y
= 2.844*10^5 / 440.0838
= 646.24 mm^3
THIS IS THE SECTION MODULUS OF HOOD DESIGN AFTER OPTIMIZATION.
SECTION MODULUS IS INCREASED FROM 638.06 mm^3 TO 646.24 mm^3, WHICH INCREASE THE STRENGTH OF THE HOOD.
THE STRENGTH OF MATERIAL IS DIRECTLY PROPORTIONAL TO THE MOMENT OF INERTIA, THUS INCREASING THE SECTION AREA WILL INCREASE THE STRENGTH OF COMPONENT.