Reinforcement detailing of Columns from ETABS output

AIM - To Design and Analyze a G+3 Building using ETABS and Foundation Design using SAFE. INTRODUCTION - The ETABS is a well-known engineering software that helps in modeling tools and templates, analyzes the methods. Provide solutions and are based on code-based load prescription. It helps with understanding the static…

AIM - A)  To model the Isolated footing on SAFE ,to analyze and design it to verufy the size, depth and steel provided as per calculations. B)  To deisgn Pile Foundation for the given data on SAFE as per IS 2911 (part2) and SP 34.   SOLUTION  A) ISOLATED FOOTING DESIGN ON SAFE : 1. Open SAFE software…

AIM -      1. To design a square footing for column of size 400 X 400 mm.     2. To do the following checks : If gross bearing pressure under the footing is within the safe bearing capacity. Provide sufficient depth and longitudinal steel for resisting bending and shear. Sufficient anchorage for…

AIM- To model a G+7 residential building from the given architectural floor plan drawing using ETABS 2018. PROCEDURE - 1. Open ETABS and start a New Model. Enter the following settings:   2. Custom the grid settings and story settings according to the given plan : The plan is now shown as per the given details in…

AIM- To extract values of longitudinal steel ratio, boundary elements length and shear reinforcement from design results. To provide cross section steel arrangement from base to terrace w.r.t IS 13920-2016. To provide elevation drawings of reinforcement details of shear walls from base to terrace. PROCEDURE - 1. …

AIM - To provide details for longitudinal reinforcements for two columns from base to terrace. To sketch column cross section and elevation details. To show shear reinforcement and lapping details as per IS 13920 2016 clause 8.1 PROCEDURE - 1. ETABS> Check model and Run Analysis - 2. Design> Frame Design Preference…

AIM - Design of RCC Moment Resisting frame structure in ETABS. Calculate value of maximum shear force as per clasue 6.3.3 (b) IS 13920-2016. PROCEDURE - 1. Download and open the ETABS file provided: 2.  Check the model and Run analysis: 3. Select Design- Concrete frame design - Design comibantions : 4. Again select…

GIVEN : To compare the Factors influencing the dynamic charateristics, natural period and modes of shape of the given buildings: A, B, C, D, E, F, G, H, I, J, K 1. Illustrations for building A : start with the input 2. Add grid and stories- 3. View- 4. Define materials- 5. Define Beams, Columns and Slab- 6. Select pin…

GIVEN- Beam- 300X400mm Column- 800X800mm Slab - 150mm 1. Input the following into new model:   2. Add Grid settings : 3. Add storey settings: add plinth elevation as 1.5m from base and rest stories 3m. make the 1st storey as master storey and add all as similar to first except the 'plinth level'. 4. Define material…

1. Shear walls are a necessary element in the seismic design of buildings. Shear walls provide large strength and stiffness , which significantly reduces lateral sway of the building and thereby reduces damage to the structure. The best position for the shear walls is in the centre of each half of the building. (img B)…

1.        a) SYMMETRY : The given diagram is symmetric in nature. A symmetrical, well-distributed in-plan layout of structural elements is appropriate to achieve uniformity. Symmetry should be sought both in what concerns the plan wise distribution of stiffness and strength, but also that of mass distribution,…

Step 1 : Calculation of Mn Hence, Mn1 = 3.86m Mn2 = 3.86m Mn3 = 3.86m Mn4 = 3.86m Mn5 = 3.86m   Step 2 : Calculation of Ln  Hence, Ln1 = 4.121m Ln2 = -1.29m Ln3 = 0.68m Ln4 = 0.381m Ln5 = 0.175m   Step 3 : Calculation of Mn* Hence, Mn*1 = 4.398m Mn*2 = 0.432m Mn*3 = 0.119m Mn*4 = 0.357m Mn*5 = 0.0079m   Step 4 : Calculation…

 1. Given that the degree of freedom is 3. The elements ki1 in the first column, we determine the stiffness matrix by imposing u1=1 , with u2=u3=0. The elements ki2 in the second column, we determine the stiffness matrix by imposing u2=1, with u1=u3=0. The elements in ki3 in the third column, we determine the stiffness…

1 (a) MODE OF FAILURE : The above crack is due to the Shear failure of the beam. Shear failure occurs when the beam has shear resistance lower than flexural strength and the shear force exceeds the shear capacity of the materials of the beam. Cracks in concrete beams due to increase in their shear stress appears near the…

G+1 residential plan according to Vastu Shastra- List of drawings to be provided on the site-  Centre line drawing  Footing and Column layout with reinforcement details  Column Schedule with reinforcement details   Plinth beam layout with reinforcement details  First Floor beam layout with…

 Concrete Mix Design for M35 grade with fly ash- Stipulations for proportioning: Grade designation : M35 Type of cement: OPC 43 grade confirming to IS 8112 Type of mineral admixture: Fly ash confirming to IS 3812 (Part1) Maximum nominal size of aggregate: 20mm Minimum cement content: 320 kg/m^3 ( Table 5 of IS 456:2000-…