All Courses
All Courses
Courses by Software
Courses by Semester
Courses by Domain
Tool-focused Courses
Machine learning
POPULAR COURSES
Success Stories
PROJECT ON CONCRETE MIX DESIGN Aim- To calculate concrete mix design for M35 grade concrete with fly ash and M50 grade concrete without fly ash. Introduction- Concrete Mix Design means determination of the proportion of the concrete ingredients i.e. Cement,…
Aparna bhujbal
updated on 10 Jul 2021
PROJECT ON CONCRETE MIX DESIGN
Aim-
To calculate concrete mix design for M35 grade concrete with fly ash and M50 grade concrete without fly ash.
Introduction-
Concrete Mix Design means determination of the proportion of the concrete ingredients i.e. Cement, Water, Fine Aggregate, Coarse Aggregate which would produce concrete possessing specified properties such as workability, strength and durability with maximum overall economy.
Advantages of mix design concrete-
Objectives of concrete mix design-
Procedure-
CONCRETE MIX DESIGN FOR M35 GRADE CONCRETE WITH FLY ASH
1)Data-
Test data-
2)Target compressive strength
Target compressive strength=f’ck
f'ck=fck + 1.65s
From Table I of IS 10262:2009, Standard Deviation, s = 5 N/mm2.
f'ck= 35+1.65x5 =43.25 N/mm2
3)Selection of water cement ratio
From Table 5 of IS456:2000, For severe and RCC structure.
Maximum permissible water-cement ratio is 0.45
4)Selection of water content
From Table 2 of IS456:2000, maximum water content =186 litres (for 25 to 50 mm slump range) for 20 mm aggregate.
Note add 3% water content for every 25mm increase in workability.
water content for 100 mm slump =186+(6/100) x 186 =197 litres.
But as Super plasticizer is used so the water content can be reduced upto 20%.
Super plasticizer water content reduction of 20% has been achieved.
so,water content = 197-[197 x (20/100)] = 157.73 lit = 160lit
4)Calculation of cement content
Water-cement ratio =0.45
Cement content = 160/0.45 = 355.56 kg/m3
From Table 5 of IS 456, the minimum cement content for Severe exposure condition is 320 kg/m3
In our case, it is 355.56kg/m3 which is greater than 320 kg/m3, hence satisfied.
But fly ash is used partially with cement, so fly ash content used= 30% of cement content
Fly ash content requirement=355.56x0.3 =106.66kg/m3
Cement Content requirement =Cementious content – Fly ash =355.56-106.66= kg/m3
Calculation of Super Plasticizers @ 0.6 percent to the mass of cementitious content = 355.56x(0.6/100) = 2.13 kg
5)Aggregate content
From Table 3 of IS10262 , the Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone II) for a water-cement ratio of 0.50 = 0.62.
In the present case, the water-cement ratio= 0.45. Therefore, the volume of the coarse aggregate is required to be increased to decrease the fine aggregate content.
Note-at the rate of -/+ 0.01 for every ± 0.05 change in the water-cement ratio
Therefore, the corrected proportion of the volume of coarse aggregate for the water-cement ratio of 0.45 = 0.63
But, Volume of aggregate is reduced by 10% to get the ease for transportation, placing by pumps.
For pumpable concrete, these values should be reduced by 10 percent.
Therefore, volume of coarse aggregate = 0.63 x 0.9 = 0.567
Volume of fine aggregate content =1 – 0.567 =0.433
6)Mix calculations-
Calculations are done for every 1cu.m concrete.
a) Volume of concrete = 1m3
b) Volume of cement = (Mass of cement/specific gravity of Cement) X (1/1000)
= (249/3.12) X (1/1000)
=0.08m3
c) Volume of water = (Mass of water/specific gravity of water) X (1/1000)
= (160/1) X (1/1000)
= 0.160m3
d) Volume of superplasticizer = (Mass of superplasticizer / Specific gravity of admixture) X (1/1000)
= (2.13/1.12) X (1/1000)
= 0.002 m3
e)Volume of fly ash= (mass of fly ash/specific gravity of fly ash)X(1/1000)
=(106.66/2.5)X1/1000)
=0.042m3
e) Volume of all aggregate = (a – (b + d + e))
= 1 – (0.08 + 0.002 + 0.042)
= 0.843m3
f) Mass of coarse aggregate = Volume of all Aggregate X Volume of Coarse Aggregate X Specific Gravity of Coarse Aggregate X 1000
= 0.843 x 0.567x 2.74 x 1000
= 1309.66 kg
g) Mass of fine aggregate = Volume of all Aggregate X Volume of Fine Aggregate X Specific Gravity of Fine Aggregate X 1000
= 0.843 x 0.433 x 2.74 x 1000
= 1000.15 kg
7)Mix proportion
CONCRETE MIX DESIGN FOR M50 GRADE CONCRETE
1)Data-
Test data-
2)Target compressive strength
Target compressive strength=f’ck
f'ck=fck + 1.65s
From Table I of IS 10262:2009, Standard Deviation, s = 5 N/mm2.
f'ck= 50+1.65x5 =58.25 N/mm2
3)Selection of water cement ratio
From Table 5 of IS456:2000, For very severe and RCC structure.
Maximum permissible water-cement ratio is 0.45 & min cement content= 340kg
4)Selection of water content
From Table 2 of IS456:2000, maximum water content =186 litres (for 25 to 50 mm slump range) for 20 mm aggregate.
Note add 3% water content for every 25mm increase in workability.
water content for 100 mm slump =186+(6/100) x 186 =197 litres.
But as Super plasticizer is used so the water content can be reduced upto 20%.
Super plasticizer water content reduction of 20% has been achieved.
so,water content = 197-[197 x (20/100)] = 157.73 lit = 160lit
4)Calculation of cement content
Water-cement ratio =0.45
Cement content = 160/0.45 = 355.56 kg/m3
From Table 5 of IS 456, the minimum cement content for very Severe exposure condition is 340 kg/m3
In our case, it is 355.56kg/m3 which is greater than 340 kg/m3, hence satisfied.
Calculation of Super Plasticizers @ 0.6 percent to the mass of cementitious content = 355.56x(0.6/100) = 2.13 kg
5)Aggregate content
From Table 3 of IS10262 , the Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone II) for a water-cement ratio of 0.50 = 0.62.
In the present case, the water-cement ratio= 0.45. Therefore, the volume of the coarse aggregate is required to be increased to decrease the fine aggregate content.
Note-at the rate of -/+ 0.01 for every ± 0.05 change in the water-cement ratio
Therefore, the corrected proportion of the volume of coarse aggregate for the water-cement ratio of 0.45 = 0.63
But, Volume of aggregate is reduced by 10% to get the ease for transportation, placing by pumps.
For pumpable concrete, these values should be reduced by 10 percent.
Therefore, volume of coarse aggregate = 0.63 x 0.9 = 0.567
Volume of fine aggregate content =1 – 0.567 =0.433
6)Mix calculations-
Calculations are done for every 1cu.m concrete.
a) Volume of concrete = 1m3
b) Volume of cement = (Mass of cement/specific gravity of Cement) X (1/1000)
= (355.56/3.12) X (1/1000)
=0.113m3
c) Volume of water = (Mass of water/specific gravity of water) X (1/1000)
= (160/1) X (1/1000)
= 0.160m3
d) Volume of superplasticizer = (Mass of superplasticizer / Specific gravity of admixture) X (1/1000)
= (2.13/1.12) X (1/1000)
= 0.002 m3
e) Volume of all aggregate = a – (b + d)
= 1 – (0.113 + 0.002)
= 0.89m3
f) Mass of coarse aggregate = Volume of all Aggregate X Volume of Coarse Aggregate X Specific Gravity of Coarse Aggregate X 1000
= 0.89 x 0.567x 2.74 x 1000
= 1382.68 kg
g) Mass of fine aggregate = Volume of all Aggregate X Volume of Fine Aggregate X Specific Gravity of Fine Aggregate X 1000
= 0.89 x 0.433 x 2.74 x 1000
= 1055.91 kg
7)Mix proportion
Conclusion:
Mix proportion for M35 grade concrete with fly ash is given as CEMENT : FLY ASH : FA : CA
Therefore mix proportion for M35 grade concrete with fly ash is 1 : 0.64 : 4.01 : 5.25
and
Mix proportion for M50 grade concrete is given as CEMENT : FA : CA
Therefore mix proportion for M50 grade concrete is 1 : 2.96 : 3.88
Leave a comment
Thanks for choosing to leave a comment. Please keep in mind that all the comments are moderated as per our comment policy, and your email will not be published for privacy reasons. Please leave a personal & meaningful conversation.
Other comments...
Usage of Collaborate tool in REVIT
1) Open an architectural template. Using the Manage tab set project base point and project shared coordinates for the project. AIM- To open an architectural template. Using the Manage tab set project base point and project shared coordinates for the project. INTRODUCTION- REVIT- Autodesk Revit is a BIM software…
05 Jan 2022 06:42 AM IST
3D Creation of Celing, Roof, Architectural plan, Structural plan, Sectional view, Elevation view and Camera specific view for a house plan using REVIT
1) Based on the project saved from Week 3, proceed from the First Floor Level. Model a Ceiling from the architecture tab above the walls at the first-floor level. AIM- To model a ceiling from the architecture tab abaove walls at the first floor level. INTRODUCTION- REVIT- Autodesk Revit is a BIM software means a…
17 Nov 2021 05:18 PM IST
Introduction to National Building Code and Steps in a Construction project
1) Why are building codes or standards essential for the modeling/ efficiency of drawings in Revit ? Importance of national building codes while modeling in revit- National building codes are used while drawing because safety of structures is imporatant parameter for public. so to reduce risks to an acceptable level…
16 Nov 2021 09:55 AM IST
Creating Walls, Partition walls and Floors for a residential layout using REVIT
1) Use the project file created from Week 2. Use it for this assignment. Based on your layout from week 2, using floor tool under architecture tab and select the floor with appropriate material and thickness using the property browser create a layout in the Ground floor Level. Align the floor plan with grids created from…
21 Oct 2021 06:11 AM IST
Related Courses
Skill-Lync offers industry relevant advanced engineering courses for engineering students by partnering with industry experts.
© 2025 Skill-Lync Inc. All Rights Reserved.