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Foundation Design using SAFE 1).Model the isolated footing provided in week 11 challenge on SAFE. Analyze and design it to verify the size, depth and steel provided as per calculations. Aim: To Analyze and design the isolated footing from week 11 challenge on SAFE To verify the size, depth and steel provided as per calculations.…
Suhas B U
updated on 06 Sep 2022
Foundation Design using SAFE
1).Model the isolated footing provided in week 11 challenge on SAFE. Analyze and design it to verify the size, depth and steel provided as per calculations.
Aim:
Introduction:
Procedure:
Step:1
Single Footing was selected.
Subgrade modulus = F.O.S x S.B.C / max settlement
= (3x150) / 0.05 = 9000 KN/m³
The compression axial load for the load combination (1.5DL + 1.5LL) is 2000 KN.
Unfactored load = 2000 / 1.5 = 1333.3 KN
Dead load breakup= 1333.3 / 2 = 666.5 KN
Live load breakup= 1333.3 / 2 = 666.5 KN
Therefore, Footing thickness 800 mm.
Step:2
Click define > material properties
Rebar yielding strength(Fy) = 500 N/mm²
Rebar ultimate strength (Fu) = 545 N/mm²
M25 grade of concrete
Modulus of elasticity
E = 25x5000 = 25000 N/mm²
Step:3
Step:4
Step:5
Step:6
Step:7
Step:8
Step:9
Step:10
Step:11
Two-way shear is 0.719, Hence OK.
Step:12
Bending Moment.
Shear Force.
Step:13
RESULT:
2). A column of size 600x600 carrying an unfactored gravity load (DL+LL) of 1175 KN is to be supported on pile cap, which ultimately transfers load to the piles underneath. Piles of 16 metres length and 500 mm diameter are to be used. Each pile has a load carrying capacity of 200 KN. Model, analyse and design the pile cap on SAFE to evaluate the following:
Note: Participants must refer to IS 2911 (part 2) and SP 34 for 2nd challenge
AIM:
Procedure:
Given.
Column size = 600 x 600 mm
Unfactored load = 1175 KN
Pile length = 16m
Pile diameter = 500 mm
Load carrying capacity = 200 KN.
Calculations.
Number of pilers = 1175 / 200 = 5.6 = 6
Spring constant = ExA / L
Where, E = 25000 N/mm²
A = π4(500)² = 196375 mm²
L = 16000 mm
Spring constant =25000 x 196375 / 16000=306835 N/mm or 306835 KN/m
Edge spacing is taken as 200 or 300 mm.
Step:1
Step:2
Step:3
Click define > material properties >M25 grade of concrete.
Modulus of elasticity
E = 25x5000 = 25000 N/mm²
Fe 500 rebar was added next as shown below.
Step:4
Step:5
Step:6
Step:7
Step:8
Step:9
Step:10
Bending Moment.
Shear Force.
RESULT:
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