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Aim : To perform the tension and torsion test on the given specimen for the following cases : Testion Test : Displace one end of the specimen to 18mm while keeping the other fixed. Tortion Test : Displace one end of the specimen to an angle of 1200 degree. Find the Total deformation, Equivalent Stress and Temperature.…
Ashwin Deepak
updated on 31 Mar 2021
To perform the tension and torsion test on the given specimen for the following cases :
Find the Total deformation, Equivalent Stress and Temperature.
Equivalent Stress | |
Total Deformation | |
Temperature |
Equivalent Stress | |
Total Deformation | |
Temperature |
Tension Test | Torsion Test | |
Equivalent Stress (MPa) | 642.43 | 646.11 |
Total Deformation (mm) | 18 | 12.697 |
Temperature (C) | 301.43 | 398.44 |
We observe in both the cases when we apply tension and torsion the speciment reaches its Fracture point and breaks. The temperature for Tortion Test is higher due to twisting moment given at one end.
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