Challenge

Week 2 - Flow over a Cylinder.

Aim:

To Simulate the flow with the steady and unsteady case and calculate the Strouhal Number for Re= 100

and to Calculate the coefficient of drag and lift over a cylinder by setting the Reynolds number to 10,100,1000,10000 & 100000

Background theory:

Vortex shedding is a phenomenon, when the wind blows across a structural member, vortices are shed alternately from one side to the other, and where alternating low-pressure zones are generated on the downwind side of the structure giving rise to a fluctuating force acting at right angles to the wind direction

The Strouhal number is defined as St = fstD/U, where fst is the vortex shedding frequency (or the Strouhal frequency) of a body at rest, D is the diameter of the circular cylinder and U is the velocity of the ambient flow.

  1. Draw the model in space claim

2. Mesh the model with mesh length of 250 mm and do the edge sizing of 10 divisions and add 6 inflamation layers with growth ratio of 1.2

3. Insert a monitor point from 8m from the center of cylinder

4. Velocity calculation for different reynolds number

rho(kg/m3) 1 1 1 1 1 1
v(m/s) 1 0.1 1 10 100 1000
d(m) 2 2 2 2 2 2
viscosity mu(kg/ms) 0.05 0.02 0.02 0.02 0.02 0.02

5. Reynolds no 100-steady state

Flow is converged

Monitor point velocity

Coefficient of lift

Since this is steady state flow the the actual coefficient 0.1792 is not reached. There is no vortex shedding also

Coefficient of drag

Since this is steady state the actual coefficient 1.33 is not reached but it is nearer to it

velocity contour

no vortex shedding is seen

pressure contour

strouhal number

the average strouhal number is 0.25 

Conclusion:

Steady state simulation doesnt give results for vortex shedding

6. Reynolds number 100 - transient simulation 

solution is converged

monitor point velocity

coefficient of lift

Coefficient of drag

Velocity contour

pressure contour

strouhal number

average strouhal number is 1.24

Animation file

https://drive.google.com/file/d/1WD7vpqPGJ5o7_j2Dh-THN0y6fb6pAmPv/view?usp=drive_link

7. Reynolds number 10 steady state

set inlet velocity as 0.1 m/s to get reynolds no of 10

solution is converged

monitor point velocity

coefficient of drag

coefficient of lift

velocity contour

pressure contour

strouhal number

8. steady state Re 1000

inlet velocity is 10 m/s

solution is converged

monitor point velocity 

coefficient of lift 

coefficient of drag

velocity contour

pressure contour

strouhal number

9. Re = 10000, velocity=100 m/s steady state

Residual plot


monitor point velocity 


coefficient of lift 


coefficient of drag


velocity contour


pressure contour


strouhal number

10. steady state 100000 inlet velocity 1000 m/s

residual plot


monitor point velocity 


coefficient of lift 


coefficient of drag


velocity contour


pressure contour


strouhal number

Conclusion:

  inlet velocity  absolute viscosity Monitor point  velocity(m/s) drag coeff lift coeff Strouhal number
10 0.1 0.02 0.04 0.05 1.52E-05  
100(steady) 1 0.02 0.13 2.02 0.02 0.25
100(unsteady) 1 0.02 0.48 2.15 0.23 1.24
1000 10 0.02 1.75 88.87 12.55  
10000 100 0.02 13.35 8453 3937  
100000 1000 0.02 175 787082 551173  

The strouhal number for Re 100 is 1.24 and Coefficient of drag is 2.15  is near to the reference values

The lift and drag coefficient depends on the velocity and reynolds number.

Inference:

The solution and the convergence depends on the solvers..

Reference:

https://www.sciencedirect.com/science/article/pii/S0307904X08000243

https://apps.dtic.mil/sti/tr/pdf/ADA395503.pdf

mae5230-tritton-chap3.pdf (cornell.edu)

https://www.youtube.com/watch?v=DXaf_5gnGaY

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