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Question 1: A five storey structure with 5 translational DOF is shown here. Each storey has mass ‘m’. The eigenvalue problem has been solved and the 5 periods of vibration Tn and their corresponding mode shapes, φn has been derived. The fundamental period of vibration (T1 = 2 seconds) and…
Rahul Prajapati
updated on 11 Aug 2022
Question 1:
A five storey structure with 5 translational DOF is shown here. Each storey has mass ‘m’. The eigenvalue problem has been solved and the 5 periods of vibration Tn and their corresponding mode shapes, φn has been derived.
The fundamental period of vibration (T1 = 2 seconds) and its associated mode shape:
The second mode of vibration (T2 = 0.6852 seconds) and its associated mode shape:
The third mode of vibration (T3 = 0.4346 seconds) and its associated mode shape:
The fourth mode of vibration (T4 = 0.3383 seconds) and its associated mode shape:
The fifth mode of vibration (T4 = 0.2966 seconds) and its associated mode shape:
Objective:
As given in question:
We have to calculate:
considered mass in every floor as 'm'
forming mass matrix, m=[m00000m00000m00000m00000m]
modified mass matrix (M) =ϕnT⋅m⋅ϕn
or the first mode, = [0.3340.6410.8951.0781.173][m00000m00000m00000m00000m][0.3340.6410.8951.0781.173], (n=1)
M1=3.861m
Calculation of Model Property:
Model Property (L) = ϕnT⋅m⋅i
where i = influence vector (assuming 100% utilization of seismic force) = [11111]
for the first mode, = [0.3340.6410.8951.0781.173][m00000m00000m00000m00000m][11111], (n=1)
L1=4.121m
Calculation of participation factor:
model participation factor (Γ) = LM
or the first mode, (Γ) = L1M1, (n=1)
Γ1=4.121m3.861m
Γ1=1.0167
similarly,
Γ2=-0.335
Γ3=0.177
Γ4=-0.098
Γ5=0.045
Calculation of effective model mass:
effective model mass (M*) = Ln2Mn
for the first mode, M1* = L12M1, (n=1)
M1* = (4.121m)23.861m
M1* = 4.398 m
similarly,
M2* = 0.436 m
M3* = 0.121 m
M4* = 0.038 m
M5* = 0.008 m
Calculation of model mass participation ratio:
Model mass participation ratio = Mn⋅mj
where, mj = total mass of the building = m+m+m+m+m = 5m
Model mass participation ratio of the first mode (n=1) = 4.398 m /5 m = 0.88
similarly,
second mode (n=2) = 0.09
third mode (n=3) = 0.02
fourth node (n=4) = 0.01
fifth node (n=5) = 0.002
As per requirement, adding first 2 mode mass participantion ratio and got 0.88+0.09 = 0.97
to achive minimum 90% of modal mass participation ratio, first 2 modes are enough
Calculating base shear:
Base shear (Vb) = Mn* . An
for the first mode, Vb1 = 4.398 m x 0.27, (n=1)
Vb1 = 1.187 mg
similarly,
Vb2 = 0.327 mg
Vb3 = 0.126 mg
Vb4 = 0.039 mg
Vb5 = 0.008 mg
Average base shear is calculated by the method of SRSS (Square root of sum of square)
√(Vb1)2+(Vb2)2+(Vb3)2+(Vb4)2+(Vb5)2
Vb = 1.15 mg
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