Project 1 : Comparative study of different storey buildings for Seismic forces |
- Aim :- To model and analyse the building from A to K with the given structural data and compare the analysis between the models based on the different factors.
- Every building has a number of natural frequencies (how many?), at which it offers minimum resistance to shaking induced by external effects (like earthquakes and wind) and internal effects (like motors fixed on it).
- Each of these natural frequencies and the associated deformation shape of a building constitute a Natural Mode of Oscillation.
- The mode of oscillation with the smallest natural frequency (and largest natural period) is called the Fundamental Mode; the associated natural period T1 is called the Fundamental Natural Period.
- Regular buildings held at their base from translation in the three directions, have two fundamental translational natural periods, Tx1 and Ty1, associated with its horizontal translational oscillation along X and Y directions, respectively, and one fundamental rotational natural period Tθ1 associated with its rotation about an axis parallel to Z axis.

- The data required for modeling the building is as shown below

-
Step 1 : Model for Building A
- Open the ETAB software from the start menu
- Click > New Model
- One dialogue box will open
- Select model initializasation option as > Use Build-in setting with
- Select Display unit > Metric SI
- Steel section database > Indian
- Steel design code > IS 800:2007
- Concrete design code > IS 456:2000

Step 2
- To set the grids and story
- Select > Custom grid setting
- Click > Edit grid data
- One dialogue box will open
- Select > Display grid data as ordinates
- Fill the data in X-Grid data and in Y-Grid data as per shown below

- Select > Custom story data
- Click > Edit storey data
- one dialogue box will open
- Double click > Story 1 and rename it as > Plinth Level
- Select plinth level height > 1.5
- Double click > Story 2 and rename it as > Story 1 and keep height > 3
- Double click > Story 3 and rename it as > Roof Storey and keep height > 3
- Select master story > Yes only to > Story 1
- Keep all other remaining story > No
- Keep all other storeys similar to > Story 1
- Keep Plinth > Similar to > None

- It will shows the following results

Step 3
- Keep all the unnecessary viewports close
- Select Plan view > Story 1
- To select the material
- Go to define tab
- Select > Material Properties

- Click > Add new material
- Select Region > India
- Material Type > Concrete
- Standard > Indian
- Grade > M30

- Click > Ok
- One dialogue box will open
- Fill the data as per shown below

- Click > OK
- The concrete material is added
- Again go to add material
- Add the rebar for longitudinal reinforcement


- Click > Ok
- By this similar way, add the rebar for shear reinforcement


- Click > Ok
- All the three materials are added

Step 4
- To add the sizes of beam, column and slab
- Go to Define tab
- Select > Section properties
- Select > Frame sections


- Select > Rectangular concrete
- Select Property name > B 300 X 400
- Material > M30
- Select section dimension Depth > 400 and Width > 300

- Select > Modify rebar
- Fill the data as per shown below

- Click > Ok
- The beam is added
- Now, add another element > Column
- Click > Add new property

- Select > Rectangular concrete
- Select Property name > C 400 X 400
- Material > M30
- Select section dimension Depth > 400 and Width > 400

- Select > Modify rebar
- Fill the data as per shown below

- Click > Ok
- The column is added
- The beam and column is added

- To add the structural element > Slab
- Go to define tab
- Select > Section properties
- Select > Slab section
- Click > Add new property
- Propert name > Slab 150
- Slab material > M30
- Modeling type > Membrane
- All the slabs are two way slab, so no need to keep one way slab on

- Click > Ok
- The slab is added
Step 5
- To start the drawing, start with columns
- Keep > All story
- Go to > Plan view > Story 1
- Take Quick draw column command
- Select the appropriate column
- Provide the column, by clicking to all the intersection point of grids
- It will shows the following results


Step 6
- To draw the beam
- Open first story plan view
- Keep > All story
- Go to quick draw beam command
- Select appropriate property
- Click on all grids to provide the beams
- It will shows the following results


Step 7
- To draw the slab
- Open first story plan view
- Keep > Similar stories
- Go to quick draw floor command
- Select appropriate property
- Click in between grids to provide the slab
- It will shows the following results


Step 8
- To assign the base of building as > Pinned
- Go to plan view > Base plan
- Select > One story
- Select all the joints
- Go to assign
- Select > Joints
- Select > Restraints
- Select the base as pinned

Step 9
- To add the load pattern
- Go to define
- Select > Load patterns
- Add the loads as per shown below

- Select Eqx load
- Click > Modify lateral load
- Set all the things as per shown below

- Similarly modify lateral load for all other eq loads
Step 10
- To assign the live load
- Keep > Similar stories
- Select all the shells
- Go to assign tab
- Select > Shell loads
- Select > Uniform
- Set as per shown below

- It will shows the following results

Step 11
- To assign the loads of infill walls
- Go to select tab > Select > Object type > Beams > Select > Close
- All the beams are selected
- Go to assign > Frame loads > Distributed
- Select load > Brickwall
- Set as per shown below

- Click > Apply
- Click > Close
- The infillwall load is applied

Step 12
- To assign the mass source
- Go to define tab
- Select > Mass source
- Select > Modify existing mass source

Step 13
- To generate the load combination
- go to define tab
- Select > Load combination
- Click > Add default design combos
- Switch on > Concrete frame design
- Switch on > Convert to user combinations
- The load combinations are generated

Step 14
- To assign the diphragms
- Go to Select > Select > Object type > floor > Select > Close
- Go to assign
- Select > Shell > Diphragms
- one dialogue box will open
- Click > D1
- Click > Apply
- Click > Ok
- The diphragms are applied


Step 15
- To check the model
- Go to analyze
- Select > Check the model

- The model has been checked

Step 16
- The model is ready for analysis
- Go to run analysis
- It will shows the following results

Step 17
- After analysis, we need to check deflection
- Go to show deformed shapes
- One dialogue box will open
- Select the load for which, we want to see the deflection



Step 18
- To see the base reactions
- Go to display
- Select > Show tables

- Click > Ok
- It will shows the following results
- Modal mass participating ratio for A building is ready

Step 19 : Model for Building B
- Copy the model of building A
- Open the copied model of building A to prepare the model of building B
- Unlock the model
- Go to edit tab
- Select > Edit stories and grid system
- Click > Modify story data
- Add the stories and set as per shown below

- To check the model
- Go to analyze tab
- Click > Check model
- It will shows the following result
- The model is ready for analysis
- Go to run model
- It will shows the following result
- The model mass participating ratio for building B is ready
Step 20 : Model for Building C
- Copy the model of building B
- Open the copied model of building B to prepare the model of building C
- Unlock the model
- Go to define tab
- Select > Section properties
- Select > Frame section
- Select C 400 X 400 section
- Add copy to property
- Set as per shown below
- Go to select tab
- Select > Select
- Select > Object type
- Select > Column
- All the columns are selected
- Go to assign tab
- Select > Section properties
- Select C 550 X 300
- Click > Apply
- All the columns are applied
- To check the model
- Go to analyze tab
- Click > Check model
- It will shows the following result
- The model is ready for analysis
- Go to run model
- It will shows the following result
-
- The model mass participating ratio for building C is ready
-
Step 21 : Model for Building D
- Copy the model of building C
- Open the copied model of building C to prepare the model of building D
- Unlock the model
- Go to select > Select > Object type > Column > Close
- Go to assign > Frame > Local axes
- Apply > Ok
- All the columns are oriented as per shown below
- To check the model
- Go to analyze tab
- Click > Check model
- It will shows the following result
- The model is ready for analysis
- Go to run model
- It will shows the following result
-
- The model mass participating ratio for building D is ready
-
Step 22 : Model for Building E
- Copy the model of building A
- Open the copied model of building A to prepare the model of building E
- Unlock the model
- Go to edit tab
- Select > Edit stories and grid system
- Click > Modify story data
- Add the stories and set as per shown below

- Go to define tab
- Select > Section properties
- Select > Frame section
- Select C 400 X 400 section
- Add copy to property
- Set as per shown below
- Go to view tab
- Select > Building views limit
- Set as per shown below
- It will shows the following results
- Go to set display option
- Switch off the beams, joints and floors
- It will shows only columns on the screen
-
- Select > Column
- All the columns are selected
- Go to assign tab
- Select > Section properties
- Select C 600 X 600
- Click > Apply
- The column C 600 X 600 is applied from Base upto the 5th floor
- Go to view tab
- Select > Building views limit
- Click > Show all
- Go to set display option
- Switch on the beams, joints and floors
- To check the model
- Go to analyze tab
- Click > Check model
- It will shows the following result
- The model is ready for analysis
- Do to run model
- It will shows the following result
-
- The model mass participating ratio for building E is ready
-
Step 23 : Model for Building F
- Copy the model of building E
- Open the copied model of building E to prepare the model of building F
- Unlock the model
- Go to edit tab
- Go to view tab
- Select > Building views limit
- Set as per shown below
- Select > Column
- All the columns are selected
- Go to assign tab
- Select > Section properties
- Select C 600 X 600
- Click > Apply
- The column C 600 X 600 is applied from 6th to roof story
- Go to view tab
- Select > Building views limit
- Click > Show all
- Go to set display option
- Switch on the beams, joints and floors
- To check the model
- Go to analyze tab
- Click > Check model
- It will shows the following result
- The model is ready for analysis
- Do to run model
- It will shows the following result
-
- The model mass participating ratio for building F is ready
-
Step 24 : Model for Building G
- Copy the model of building F
- Open the copied model of building F to prepare the model of building G
- Unlock the model
- Go to edit tab
- Select > Edit stories and grid system
- Click > Modify story data
- Add the stories and set as per shown below


- Go to define tab
- Select > Section properties
- Select > Frame section
- Select C 800 X 800 section
- Add copy to property
- Set as per shown below
- Go to view tab
- Select > Building views limit
- Set as per shown below
-
- Select > Column
- All the columns are selected
- Go to assign tab
- Select > Section properties
- Select C 800 X 800
- Click > Apply
- The column C 800 X 800 is applied from Base upto the 10th floor
- Go to view tab
- Select > Building views limit
- Set as per shown below
-
- Select > Column
- All the columns are selected
- Go to assign tab
- Select > Section properties
- Select C 400 X 400
- Click > Apply
- The column C 400 X 400 is applied from 21st story upto the roof story
- Go to view tab
- Select > Building views limit
- Click > Show all
- Go to set display option
- Switch on the beams, joints and floors
-
- Copy the model of building H
- Open the copied model of building H to prepare the model of building K
- Unlock the model
- Set > All stories
- Go to select
- Select > Object type
- Select > Floors
- Click > Close
- All the slabs are selected
- Now as per instructions, we have to add imposed mass 20% larger than the building H
- Go to assign
- Select > Shell loads
- Select > Uniform
- Set as per shown below

- Click > Apply > Ok
- The imposed mass in increased by 20%
- To check the model
- Go to analyze tab
- Click > Check model
- It will shows the following result
- The model is ready for analysis
- Go to run model
-
- The model mass participating ratio for building K is ready

- The modal mass participating ratio of building A :

- The modal mass participating ratio of building B :

- The modal mass participating ratio of building C :

- The modal mass participating ratio of building D :

- The modal mass participating ratio of building E :

- The modal mass participating ratio of building F :

- The modal mass participating ratio of building G :

- The modal mass participating ratio of building H :

- The modal mass participating ratio of building J :

- The modal mass participating ratio of building K :

Factors influencing the Natural Period of a building
- Effect of stiffness on T: Compare fundamental natural periods of buildings E & F as well as G & H. Why is there a marginal or significant difference in the fundamental natural periods?
|
BUILDING E |
BUILDING F |
T ( X1 ) |
1.732 s |
1.735 s |
T ( Y1 ) |
1.676 s |
1.678 s |
|
BUILDING G |
BUILDING H |
T ( X1 ) |
4.17 s |
4.416 s |
T ( Y1 ) |
3.988 s |
4.222 s |
- Here,The time period of Building F and building H is marginally greater than the building E and building F because of uniformity in column sizes of building F and building H.
- The time period is directly proportional to the mass of the building, so here, in building E and building F the mass is increased and thats whye it results in increase in the time period.
- The arrangement will not effect much more on the stiffness
- Effect of mass on T: Compare fundamental natural periods of buildings H, J and K. Have the buildings become more flexible or stiff due to change in mass?
|
BUILDING H |
BUILDING J |
BUILDING K |
T ( X1 ) |
4.416 s |
4.425 s |
4.435 s |
T ( Y1 ) |
4.222 s |
4.231 s |
4.240 s |
- Here, All the above buildings are 25 story building only difference is that, the Building J and Building K has 10 % and 20 % more mass than the mass of building H.
- The time period is directly proportional to the mass of the building, so here, in building J and building K the mass is increased and thats whye it results in increase in the time period.
- More the time period of a building results in the more flexible and so the building K and building J is more flexible than the building H.
- Effect of Building Height on T: How does the fundamental natural periods of Buildings A, B, F and H change with change in building height?
|
BUILDING A |
BUILDING B |
BUILDING F |
BUILDING H |
T ( X1 ) |
0.5 s |
1.036 s |
1.735 s |
4.416 s |
T ( Y1 ) |
0.488 s |
1.01 s |
1.678 s |
4.222 s |
- Here, we can see that the funamental natural period of building is increases with the increasing in the building height
- As the height of the building increases, its mass increases but the overall stiffness will be reduces
- Effect of Column Orientation on T: How does the fundamental natural periods of Buildings B, C and D change with change in column orientation?
|
BUILDING B |
BUILDING C |
BUILDING D |
T ( X1 ) |
1.036 s |
1.145 s |
1.12 s |
T ( Y1 ) |
1.01 s |
0.929 s |
0.953 s |
- Here,The building B has the square columns, so the building B has nearly same natural period along the X axis and along the Y axis.
- In Building C, the columns are oriented along the X-axis so thats why, the building B has greater natural time period in X axis compared to the Y axis
Factors influencing the Mode shape of oscillations
- Effect of Flexural Stiffness of Structural Elements on mode shapes: Compare fundamental mode shape of Building B in two situations when flexural stiffness of beams relative to that of adjoining columns is very small versus when it is large.
- The time period of original building B is kept as it is, the building B model is copied
- Opened that copied model B and name it as B1 building
- Change the moment of inerta of beam as per shown below

- and the time period is noted for B1 building
|
BUILDING B |
BUILDING B1 |
T ( X1 ) |
1.036 s |
2.627 s |
T ( Y1 ) |
1.01 s |
2.549 s |
- Here, the time period is increased for modified building B1.
- It means, as the flexural stiffness of the building is reduced, the building becomes more flexible and hence it results in increases in the natural time period.
- Effect of Axial Stiffness of Vertical Members on mode shapes: Compare fundamental mode shape of Building H in two situations when axial cross-sectional area of columns is very small versus when it is large.
- The time period of original building H is kept as it is, the building H model is copied
- Opened that copied model H and name it as H1 building
- Change the Cross-Section (axial) Area of column as per shown below

- and the time period is noted for H1 building
|
BUILDING H |
BUILDING H1 |
T ( X1 ) |
4.416 s |
5.991 s |
T ( Y1 ) |
4.222 s |
5.312 s |
- Here, the reduction in the axial stiffness will results in the increment in the natural time period.
- Effect of Degree of Fixity at column bases on mode shape: Compare fundamental mode shape of Building B in two situations when base of columns is pinned versus when it is fixed.
- The time period of original building B is kept as it is, the building B model is copied
- Opened that copied model B and name it as B2 building
- Prepare the model B2 by keeping fixed condition at base
- And the time period is noted for B1 building
|
BUILDING B |
BUILDING B2 |
T ( X1 ) |
1.036 s |
0.941 s |
T ( Y1 ) |
1.01 s |
0.919 s |
- Here, after the application of fixed support to the building B it results in reducing the natural time period.
- We know that, fixed support is more rigid than the pinned support and hence the column rigidity will be higher and due to this the natural time period is reduced.