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Aim To perform the steady-state conjugate heat transfer simulation on the exhaust port when the air is coming at the inlet at a speed of 5m/sec. Objectives: Give a brief description of why and where a CHT analysis is used. Maintain the y+ value according to the turbulence model and justify the results. Calculate…
Kishoremoorthy SP
updated on 01 Feb 2023
Aim
To perform the steady-state conjugate heat transfer simulation on the exhaust port when the air is coming at the inlet at a speed of 5m/sec.
Conjugate Heat Transfer(CHT):
Conjugate heat transfer is a type of heat transfer analysis between solids and fluid(s). This type of heat transfer includes both convection (between fluids) and conductive (between solids) heat transfer, as well as both forced and natural convection. Common applications and use cases of this thermal simulation type include electronics cooling, heat exchangers, industrial machinery, some AEC cases, and more.
Numerical approaches are one of the simplest ways to realise conjugation. Iterative methods are used to set and solve the boundary conditions for the interface between a fluid and a solid. Other than by using the hit-and-miss approach, there is no way to make accurate assumptions about the values of the initial boundary condition for convergence.
Why CHT :
Understanding of the complex heat transfer mechanisms and the interactions between those mechanisms to improve the performance and increase the lifespan of the components to be analysed.
Conjugate Heat Transfer analysis provides the temperature distribution in solid and fluids, and clear insight on velocity distribution and mechanism of heat transfer of fluid, like in engines.
It is more accurate and fast to simulate the problem.
Can be used in complex scenarios like in automotive components or in power plant components.
Multiple number of regions can be simulated.
All types of region combination can be simulated like solid-fluid,fluid-fluid, etc.
Where is CHT analysis done :
Simulation precedure :
We are going to simulate the exhaust port refine mesh
Geometry :
1. Import the model of exhaust port.
2. Go in repair and clear the extra edges if any.
3. Then go in prepare and extract the inner volume.
4. After that select solid and fluid component move them to new componet.
5. Finally go in workbench and select shareprep and also share the topology in desing.
N.B-: Pink colour border tells that solid-fluid volume shared correctly
Mesh :
The here given in inflation has
total layer thickness =5mm
maxium layer = 6
growth rate = 1.2
Setup:
Inlet
velocity-5 m/s
Tempereture- 700°C
Outlet
Gauge presure- 0 pa
Outer wall convection
wall heat transfer co-efficient (h)= 20k
velocity- No slip
wall-solid-fluid-solid_volume
No slip
Heat flux - 0°C
Adiabatic
Result
How would you verify if the HTC predictions from the simulations are right? On what factors does the accuracy of the prediction depend on?
The typical flow conditions in automotive exhaust systems produce re in the range of 10^3 to 5*10^4. The exhaust flow often enters the region re<2300, especially in exhaust manifold runners. In spite of that, the flow remains actually turbulent since it has flowed through a substantial restriction. The exhaust valves and the persisting unsteady flow pulsation effects don’t favor the transition to the laminar region.
According to the sieder tate relation which correlates the Nu number with Re and Pr
Nu = 0.023*Re^0.8Pr^n
It means Nusselt no. is the function of Reynolds no and Prandtl number
As the turbulent boundary layer in the bend of the outlet port is the thin maximum velocity of flow is observed at bend and hence higher Reynolds number.
Now, Nu = h*L/k
As the length of pipe and thermal conductivity is a constant value of h will increase as Nu increases and Nu increases as Re increases.
As per our result, the heat transfer coefficient is high for a higher value of velocity and hence our results are correct.
Re=Density*velocity*lenght/dynamic viscosity
Re=1.204*5*0.166/1.1813e^-5
Re = 56867.66
By using the Dittus Bolter heat transfer coefficient relation in natural turbulent flowe the Diltus Bolter HT coefficient is determined by the Nusselt number which is related by the formula of
Nu(D) = 0.023* Re^0.8*pr^n here n=0.3 D = diamter of the pipe = characteristics length = 0.166 m
Prandtl number
pr = mu*cp/k here mu = 1.789*10^-5 cp = 1006.43 J/kg-k and k = thermal conductivity = 0.0242 w/mk
pr = (1.789*10^-5*20)/0.0242
pr= 0.744
Nusselt number is calculated as
NU = 0.023*56867.66 ^0.8*0.744^0.3
NU= 131.792
Nu= hD/k
NU=131.792=h*0.166/0.0242
h=19.52 w/m^2k.
Factors affects the quality of prediction:
Conclusions-
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