Understanding the concepts on Degrees of Freedom
Aim:
- To compute Ln , Mn and Γn for each five modes from the given equation.
- To calculate the effective modal mass Mn* and the modal mass participating ratio for the 5 modes. The mass matrix will be required to evaluate these parameters.
- To obtain obtain the base shear for each of the 5 modes of vibration and the combined base shear as per SRSS rule. The pseudo acceleration design spectrum to obtain the base shear for each mode is provided below.
- To obtain how many modes such that a modal mass participating ratio of 90% is obtained from the below graph
- How many modes are to be considered such that a modal mass participating ratio of 90% is obtained?
Procedure:
Step 1: To find 5 modes for the below equations
Mode1:
Mn = ɸnTmɸn
The first mode of vibration (T1) = 2 Seconds


M1 =3.861M
Mode 2: The second mode of vibration (T2) = 0.6852 Seconds


M2 =3.861M
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Mode 3: The second mode of vibration (T3) = 0.4346 Seconds


M3 =3.85M
Mode 4: The second mode of vibration (T4) = 0.3383 Seconds


M4 =3.861M
Mode 5: The second mode of vibration (T5) = 0.2966 Seconds


M5 =3.861M
****************
Step 2:
Ln = ɸnTmi
Mode 1: The first mode of vibration (T1) = 2 Seconds


L1 = 4.121 M
Mode 2: The first mode of vibration (T2) = 0.6852 Seconds


L2 = -1.298 M
Mode 3: The first mode of vibration (T3) = 0.4346 Seconds


L3 = 0.687 M
Mode 4: The first mode of vibration (T4) = 0.3383 Seconds


L4 = -0.381 M
Mode 5: The first mode of vibration (T5) = 0.2966 Seconds


L5 = 0.175 M
*****************
Step 3 :
Γn = Ln / Mn
Mode 1:
Γ1 = L1/M1
= 4.121M / 3.861M
= 1.067
Mode 2:
Γ2 = L2/M2
= -1.298M / 3.861M
= -0.33
Mode 3:
Γ3 = L3/M3
= 0.687M / 3.85M
= 0.178
Mode 4:
Γ4 = L4/M4
= -0.381M / 3.861M
= -0.09
Mode 5:
Γ5 = L5/M5
= 0.175M / 3.861M
= 0.04
**************
Step 4:
Mn* = Ln2/Mn
Mode 1:
M1* = L12/M1
= (4.121M) 2/3.861M
= 4.398 M
Mode 2:
M2* = L22/M2
= (-1.298M) 2/3.861M
= 0.436 M
Mode 3:
M3* = L32/M3
= (0.687M) 2/3.85M
= 0.12 M
Mode 4:
M4* = L42/M4
= (-0.381M) 2/3.861M
= 0.03 M
Mode 5:
M5* = L52/M5
= (0.175M) 2/3.861M
= 0.007 M
****************
Step 5:
- Modal mass participating ratio = Mn*/
</math>">MjM n ∗ M j
Mj = Total mass = M+M+M+M+M = 5M
Mode 1
- M1* /Mj = 0.88 = 88%
Mode 2
- M2* /Mj = 0.086 = 8.6%
Mode 3
- M3* /Mj = 0.024 = 2.4%
Mode 4
- M4* /Mj = 0.006 = 0.6%
Mode 5
- M5* /Mj = 0.001 = 0.1%
****************
Step 6 :
Now we need to obtain the base shear for each of the 5 modes of vibration.
Vbn = (
(T1 ) = 2 seconds, A1= 0.27g
(T2 ) = 0.6852 seconds, A2 = 0.76g
(T3 ) = 0.4346 seconds, A3 = 1.03g
(T4 ) = 0.3383 seconds, A4 = 1.03g
(T5 ) = 0.2966 seconds, A5 = 0.76g
Mode 1:
- Vb1= (M1* x A1) = (4.39M x 0.27g) = 2.613 kips
Mode 2:
- Vb2 = (M2* x A2) = (0.43M x 0.76g) = 0.719 kips
Mode 3:
- Vb3 = (M3* x A3) = (0.12M x 1.03g) = 0.272 kips
Mode 4:
- Vb4 = (M4* x A4) = (0.03M x 1.03g) = 0.067 kips
Mode 5:
- Vb5 = (M5* x A5) = (0.007M x 0.76g) = 0.011 kips
************************
Step 7:
Combined base shear as per SRSS rule:-
=√((2.613)2+(0.719)2+(0.272)2+(0.067)2+(0.011)2
= 3.20 kips
********************
Step 8:
- The two modes are to be considered such that a modal mass participating ratio of 90% is obtained.
88% + 8.6% = 96.6%
Result :
- Ln , Mn and Γn for each of the five modes from the given equations has been calculated
- The effective modal mass Mn* and the modal mass participating ratio for the 5 modes is calculated
- The base shear for each of the 5 modes of vibration is obtained.
- As per SRSS rule the combined base shear is obtained.
- The two modes are to be considered such that a modal mass participating ratio of 90% is obtained.