Challenge

Project on Concrete Mix Design for various grades of Concrete

AIM : The mix design calculation of M35 Grade Concrete with Fly ash & M50 grade concrete without Fly ash

INTRODUCTION

  • Concrete is the construction material consisting of cement, fine aggregate (sand) and coarse aggregate mixed with water which becomes harder with time.
  • It is extensively used in modern construction for the construction of foundation, column, beams, slabs, roads, bridges and other load bearing elements.
  • Water Cement ratio in concrete plays an important role in influencing various properties such as workability, strength and durability. Self-compacting concrete is a special condition of high performance concrete having high flow ability, segregation resistance and can reach every corner of formwork through its own self weight without the application of vibration during pouring process.
  • This concrete flows under its own weight and doesnt require vibration for compaction.
  • Different types of mineral admixtures like fly ash, silica flumes, metakaolin, etc. are used as the partly replacement of cement which helps to increase cohesion and reduce sensitivity to change in water content.
  • Mineral admixtures also helps to reduce the chemical requirement to get similar flow without altering the cement content.
  • The chemical admixture i.e. super plasticizer is an important ingredient for SCC to reduce the water demand in the concrete increasing strength and at the same time obtaining the fluidity and workability.

Step by Step Procedure

Section :1 To Calculate Mix Design for M35 grade concrete with fly ash

I. STIPULATIONS FOR PROPORTIONING OF M35 GRADE CONCRETE

This section has Specifications of the materials and requirements of the concrete to be made.

A Grade Designation M35
B Type of Cement OPC 53
C Type of Admixture Fly ash
D Maximum Nominal
Size of Aggregate
20mm
E Minimum Cement Content 340kg Table 5-IS456
F Maximum Cement Content 450kg As per code
G Partial replacement
of cement by Fly ash
30% as per requirement
H Maximum W/C ratio 0.45 Table 5-IS456
I Workability 100mm
J Chemical Admixture PCS Type

II. TEST DATA FOR MATERIALS

Various laboratory tests on materials are required to use in this action. Standard values are assumed below.

A Cement Used OPC 53 Confirming to
IS8112
B Specific Gravity of Cement 3.15 Test – IS: 2720
C Mineral Admixture Fly ash Confirming to IS12089
D Specific Gravity of Fly ash 2.90
E Chemical Admixture @0.6% IS9103
F Specific Gravity of Test – IS 2386
Coarse Aggregate 2.74
Fine Aggregate 2.74
Admixture PCE based 1.12
G Water Absorption Test – IS 2386
Coarse aggregate 0.5 %
Fine aggregate 1 %
H Sieve Analysis Test – IS 2386
Coarse aggregate Confirming to
Table 2-IS383
Fine aggregate Zone II Confirming to
Table 4-IS383

III. TARGET STRENGTH FOR MIX PROPORTIONS OF M35 GRADE CONCRETE

The strength of the concrete may deviate based on the quality of the material, method of mixing and construction practices. Hence target strength (Fck) should be higher than the required strength of the concrete (fck). The value of standard deviation(s) for different grades of concrete is given in Table 1 of IS456.

Fck = fck+1.65s “S” from Table1-IS10262
Fck = 35+1.65×5
Fck = 43.25 N/mm2

IV. SELECTION OF WATER-CEMENT RATIO

The maximum water-cement ratio for different grades of concrete is given in Table 5-IS456. You can reduce the water-cement ratio based on your requirements. The Water-cement ratio directly affects the strength of the concrete.

Maximum W/C ratio =0.45 Table 5-IS456
Adopted W/C ratio =0.45

V. SELECTION OF WATER CONTENT

Maximum Water Content =186 L Table 2-IS1026
  • Above water-content is for 25 to 50mm slump, but we need 100mm slump for our concert as per specification.
  • So we need to increase the water-content to get the required slump.
  • Clause 4.2 of IS1026 suggests to increases 3% of water-content to get an extra 25mm slump.
  • Hence we to increase water content by 6% to get an additional 50mm slump for our concrete.
Water-content for 100mm Slump =186+(0.06*186)
=197.16 L

Since we are using superplasticizers water-content can be reduced inorder to get strength in concrete.

The amount of water-content to be reduced depends on the type of superplasticizer.

Percentage of Reduction in water content =20%
Water content requirement after SP =198 – (0.20*198)
=157.73
Adopted Water Content =160 L

VI. CALCULATION OF CEMENT AND FLY ASH CONTENT

Adopted Water Cement Ratio =0.45
Total Cementitious (Cement +Fly ash) requirement = Water Content / WaterCement ratio
=160/0.45
=355.55 kg

Since Fly ash is used the amount of Cementitious content (Cement+Fly ash) shall be increased to get good workability and strength. The percentage of cementitious content to be increased depends on the experience and research. Here we have increased the cementitious content by 10%.

Final Cementitious
Content (Cement+Fly ash)
= 356*1.10
=391.6 kg
Minimum Cement Content
required for ‘severe’ exposure
=340kg Table 5-IS456
Adopted Cementious content =391.6 kg > 340kg
Fly ash content requirement = 391.6 * 0.30 30% replacement
= 117.48 ~ 118 kg
Cement Content requirement =Cementious content – Fly ash
=391.6-117.48
= 274.12

Calculation of Super Plasticiers @ 0.6 percent to the mass of cementitious content = = 391.6*(0.6/100) = 2.35 kg

VII COARSE AND FINE AGGREGATE

Coarse Aggregate ratio = 0.62 Table3-IS10262
(For W/C =0.5)
Coarse Aggregate ratio
for 0.45 w/c ratio
= 0.63 (adding 0.01 for every
decrease .05 and vice versa)
Final Fine Aggregate ratio = 0.37 (1-0.63) = 0.37

VIII MIX CALCULATIONS OF M35 GRADE CONCRETE

A Volume of Concrete = 1 cu.m
B Total Volume of Cement = Cement/(S.G*1000)
= 275/(3.15*1000)
= 0.087 cu.m
C Total Volume of Fly ash = Flyash/(S.G*1000)
= 118/(2.5*1000)
= 0.041 cu.m
D Volume of Water =Water /(S.G*1000)
= 160/(1*1000)
= 0.160 cu.m
E Volume of Superplasticizers = Superplasticizers /(S.G*1000)
= 2.35/(1.12*1000)
= 0.002 cu.m
F Total Aggregates requirement = A – (B+C+D+E)
=1 -(0.087 +0.041+0.160+0.002)
=0.71 cu.m
G Coarse Aggregate (C.A) = F * C.A ratio * S.G * 1000
= 0.71*0.63 *2.74 *1000
= 1225.6 kg
I Fine Aggregate (F.A) = F * F.A ratio * S.G * 1000
= 0.71*0.37*2.74 *1000
=719.8 kg

Cement Flyash Sand Aggregate Water and Superplasticizer needed for M35 grade concrete

S.No. MATERIALS QUANTITY
1 Cement 275 kg
2 Flyash 118 kg
3 Fine Aggregate 720 kg
4 Coarse Aggregate (20mm) 1226 kg
5 WATER 160 L
6 PCE based SuperPlasticizer 2 L

To find the design mix ratio divide the calculated value of all materials by the weight of cement.

Therefore Mix Ratio of M35 Grade concrete by weight is

Cement : Flyash: F.A : C.A : Water = 1:0.4:2.6:4.46:0.58

section 2 : The mix design M-50 grade concrete without flyash

Actual site conditions vary and thus this should be adjusted as per the location and other factors.

Parameters for mix design M50

Grade = M-50
Type of cement = O.P.C-43 grade
Fine Aggregate = Zone-II

Sp. Gravity
Cement = 3.15
Fine Aggregate = 2.61
Coarse Aggregate (20mm) = 2.65
Coarse Aggregate (10mm) = 2.66

Minimum Cement =400 kg / m3
Maximum water cement ratio = 0.45

Mix Calculation: –

1. Target Mean Strength = 50 + ( 5 X 1.65 ) = 58.25 Mpa

2. Selection of water cement ratio:-
Assume water cement ratio = 0.35

3. Calculation of water: Approximate water content for 20mm max. Size of aggregate = 180 kg /m3

(As per Table No. 5 , IS : 10262 ). As plasticizer is proposed we can reduce water content by 20%.

Now water content = 180 X 0.8 = 144 kg /m3


4. Calculation of cement content:-
Water cement ratio = 0.35
Water content per cum of concrete = 144 kg
Cement content = 144/0.35 = 411.4 kg / m3
Say cement content = 412 kg / m3 (As per contract Minimum cement content 400 kg / m3 )

5. Calculation for C.A. & F.A :

Volume of concrete = 1 m3
Volume of cement = 412 / ( 3.15 X 1000 ) = 0.1308 m3
Volume of water = 144 / ( 1 X 1000 ) = 0.1440 m3
Volume of Admixture = 4.994 / (1.145 X 1000 ) = 0.0043 m3
Total weight of other materials except coarse aggregate = 0.1308 + 0.1440 +0.0043 = 0.2791 m3

Volume of coarse and fine aggregate = 1 – 0.2791 = 0.7209 m3
Volume of F.A. = 0.7209 X 0.33 = 0.2379 m3 (Assuming 33% by volume of total aggregate )

Volume of C.A. = 0.7209 – 0.2379 = 0.4830 m3

Therefore weight of F.A. = 0.2379 X 2.61 X 1000 = 620.919 kg/ m3

Say weight of F.A. = 621 kg/ m3

Therefore weight of C.A. = 0.4830 X 2.655 X 1000 = 1282.365 kg/ m3

Say weight of C.A. = 1284 kg/ m3

Considering 20 mm: 10mm = 0.55: 0.45
20mm = 706 kg .
10mm = 578 kg .
Hence Mix details per m3
Increasing cement, water, admixture by 2.5% for this trial

Cement = 412 X 1.025 = 422 kg
Water = 144 X 1.025 = 147.6 kg
Fine aggregate = 621 kg
Coarse aggregate 20 mm = 706 kg
Coarse aggregate 10 mm = 578 kg
Admixture = 1.2 % by weight of cement = 5.064 kg.

cement:F.A:C.A: Water = 1:1.472: 3.043: 0.35

Results:

Mix Praportions for grade of M35 grade of concrete with fly ash

Cement : Flyash: F.A : C.A : Water = 1:0.4:2.6:4.46:0.58

Mix Praportions for grade of M50 grade of concrete without fly ash

Cement:F.A:C.A: Water = 1:1.472: 3.043: 0.35

Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.