Challenge

Week 5 Challenge

1.Generate manual wind loading in the design report based IS code as per the following input

  • Basic wind speed = 39m/s
  • Terrain category 2

Ans)

Aim:To generate manual wind loading in the design report based IS code as per the following input which are mentioned in the question.

Tools Required:

-> Tekla model

-> Dimensions

-> Microsoft Excel Worksheet

Procedure:

  • Firstly open the Tekla softwear and open the designed model for which you desired to apply wind load.
  • Now take the dimensions of the model such as height, lenght,width etc.

  • Now place the values in the Microsoft Excel Worksheet and type the required content.
  • Multipy the factors as in when required.
Wind load calculations as per IS: 875 P3-1987
Basic parameters
Basic wind speed Vb= 39 m/s Terrain category= 2
Probable design life= 50 years class of structure = A
Greater horizontal dimension, l= 24 m Ratio for wall and roof co-efficients:
Lesser horizontal dimension, w= 18 m
Eaves level height = 14 m wall = l/w = 1.33
Width of frame-1, grid A and B 7 m h/w = 0.78
Roof = h/w = 0.78
Topography factor, k3= 1
Risk co-efficient, k1= 1 (for 50 years)
Height(m)= upto 10
Terrain factor & str.size factor k2= 1
Important factor for cyclonic, k4= 1.15
Design wind speed , Vz= Vb*k1*k2*k3*k4= 44.85
Design wind pressure (N/m) (N/m^2), Pz= 0.6*vz^2= 1206.9
Design wind speed(kN/m^2), Pz = 1.207
Roof angle, α = 16 degree
Internal pressure coefficient, α = 0.5 (upto 20% opening) () (Cl.6.2.3.3 IS 875 P3:1987)
Internal pressure coefficient, α = -0.5 (upto 20% opening) ()
Wall loading calculations :
Wind direction : +Y
Wind load along Y-Direction (Face A): _+ Cpi _- Cpi
Height at different level = upto 10 upto 10
External pressure coefficient, Cpe = 0.7 0.7
Internal pressure coefficient, Cpi = 0.5 -0.5
Net pressure coefficient, Cp = 0.2 1.2
Design wind pressure for wall = 1.207 1.207
Loading to be applied on the wall = 0.241 1.448
factor ( loading * 1.05) = 0.253 1.52
Wind load along Y-Direction (face B): _+Cpi _-Cpi
Height at different level = upto 10 upto 10
External pressure coefficient, Cpe = -0.25 -0.25
Internal pressure coefficient, Cpi = 0.5 -0.5
Net pressure coefficient, Cp = -0.75 0.25
Design wind pressure for wall = 1.207 1.207
Loading to be applied on the wall = -0.905 0.302
factor ( loading * 1.05) = -0.95 0.32
Wind load along Y-Direction (Face C & D) _+Cpi _-Cpi
Height at different level = upto 10 upto 10
External pressure coefficient, Cpe = -0.6 -0.6
Internal pressure coefficient, Cpi = 0.5 -0.5
Net pressure coefficient, Cp = -1.1 -0.1
Design wind pressure for wall = 1.207 1.207
Loading to be applied on the wall = -1.328 -0.12
factor ( loading * 1.05) = -1.4 -0.13
Roof loading calculations
Wind direction -Y _+Cpi _-Cpi
h/w = 0.78 h/w = 0.78
External pressure coefficient, Cpe = -0.88 -0.4 -0.88 -0.4
Internal pressure coefficient, Cpi = 0.5 0.5 -0.5 -0.5
Net pressure coefficient, Cp = -1.38 -0.9 -0.38 0.1
Design wind pressure for roof, Pz = 1.207 1.207 1.207 1.207
Wind load along X-direction ( Roof EG): _+Cpi _-Cpi
Height at different level = upto 10 upto 10
External pressure coefficient, Cpe = -0.76 -0.76
Internal pressure coefficient, Cpi = 0.5 -0.5
Net pressure coefficient, Cp = -1.26 -0.26
Design wind pressure for wall = 1.207 1.207
Loading to be applied on the wall = -1.52 -0.314
factor ( loading * 1.05) = -1.596 -0.33
Wind load along X- direction ( Roof FH) : _+Cpi _-Cpi
Height at different level = upto 10 upto 10
External pressure coefficient, Cpe = 0 0
Internal pressure coefficient, Cpi = 0.5 -0.5
Net pressure coefficient, Cp = -0.5 0.5
Design wind pressure for wall = 1.207 1.207
Loading to be applied on the wall = -0.6 0.6
factor ( loading * 1.05) = -0.63 0.63

Result:

By doing this we will be able to generate wind load calculations of a model manually.

2.Based on the above calculation apply the loadings on the model.

Ans)

Aim:Based on the above calculation applying the loadings on the model.

Tools Required:

-> Loads

-> Loadcases

-> Area load

->Properties -> Direction -> Load value.

Procedure:

  • Firstly open the model that was previously designed.

  • Now select the load cases option, you will be directed to a dialogue box and in that add the load cases of your chioce and naming the load as wind load as we are doing that.

  • I named the loads as shown in the above picture.

  • Now in the below bar of the workspace assing a particular load to the frames that are to be assigned.

  • Repeat the loads for the Faces of A,B,C and D accordingly.

  • Now assign the loads for the roof too.

Result:

Hence by following the above procedure we can applying the loadings on the model.

3.On a separate model generate wind loading using wind wizard.

Ans)

Aim:To create a separate model and generate wind loading using wind wizard.

Tools Required:

-> Levels

-> Manage Properties -> New -> Members -> Concrete Column.

-> Grids

-> Columns

-> Manage Properties -> New -> Members -> steel beam.

-> Beams

-> Properties tab

Load -> Wind Wizard

Procedure:

  • Firstly on the workspace create a model of your choice.

  • That is to create the grids and then assigning the columns,beams as per the requirement for the building.

  • Now select the wind wizard option and you will be directed to a dialogue box on the workspace.

  • Now select next and finish because all the values of the structure are already taken by the software itself and there is no values that you have to change.

  • Click ok and the work is done.

Result:

Hence by following the above procedure we will be able to create a separate model and generate wind loading using wind wizard.

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