Week 2 Railwheel and Track

Objective:

Case 1: Multiply the bearing load by 5 times and compare the results with the load of 100000 N (As done in week 2 video). Compare the Total Deformation, Equivalent stress, and the life under both the loads.

PROCEDURE:

• Open the static structural
• Import the geometry by right clicking on it
• Right click on model and edit it
• Select the default contacts and right click on it, select rename based on definition
• Flip the contacts
• Define the contacts between wheel and track and assign frictional coefficient of 0.3
• Define shaft and wheel to be frictional
• Click on connections and assign 3 Joints- Planar, Translational and Fixed
• Fixed Joint - For track , select both the sides of the track and click apply in scope
• Translational Joint - select the shaft and click on apply for scope section
• Select the side of wheel for Planar joint

Mesh:

• Use the Mesh of 50mm
• Select the Three faces that will be in contact and click insert and then select sizing and apply 35mm

Analysis Settings:

• Number of steps should be 5
• For 1st step Auto time stepping should be program controlled
• Solver type should be direct
• Switch on the large deflection
• Select yes for all the Parameters in Output Controls
• In Non Linear section Switch on the Force Convergence
• For 2nd to %th step - Auto stepping step should be on
• Define by time
• Carry over time step ON
• Minimum time step be 1e-3
• Maximum - 0.1
• Large Deflection ON
• Solver Type Direct
• Force Convergence - ON

LOAD :

• Define the Translational Joint load at X Displacement of 500mm
• Select the face of bearing and apply bearing Load in the negative y axis and apply load of -1e5N. Define by Components

Load 500000N -

Equivalent Stress -

Total Deformation:

LIFE:

Load 100000N -

Equivalent Stress -

Total Deformation -

Life:

Result:

S.No	Load	Equivalent Stress (MPa)	Total Deformation (mm)	Life
1	500000N	604.36	1001.5	1e6
2	100000N	90.748	1001.3	1e6

Conclusion:

• Equivalent Stress is higher for load of 500000N
• Total deformation is mostly same for both the cases

CASE 2 :

Objective: Implement a User-defined result and calculate the Total Deformation from this result and check if it is the same as that obtained by the inbuilt result by ANSYS for a load of 100000 N.

PROCEDURE:

For the user defined we used the Formula - sqrt(UX*UX+ UY*UY+ UZ*UZ) as per the below screenshot

Total Deformation - User Defined result

Total Deformation by ANSYS:

Conclusion:

Total deformation is equal for user defined and Ansys. Total deformation remains same, hence verified.