Week 2 Challenge

Solution.1)

Aim: To determine the net sectional area of the given Plates and Angles.

Procedure:

Result: Hence, the net sectional area for the following three cases are obtained successfully and are as:

NET SECTIONAL AREA = 2064 `mm^2`

NET SECTIONAL AREA = 2189 `mm^2`

NET SECTIONAL AREA = 2808 `mm^2`

Solution.2)

Aim: To design the sag rod for the given loading conditions.

Procedure:

Given:

Center to Center Distance between Rafter = 8 m

Spacing of Purlin = 1.2 m

Self Weight of Roofing = 60 kg/`m^2`

Wind Pressure Intensity = 150 kg `/m^2`

Slope of Rafter(`theta`) = 15`degree`

Live Load = 75 kg/`m^2`

Self Weight of Purlin = 100 kg/m

Now, Finding Total Factored Load (kN) = (Dead Load + Live Load) x Factor of Safety x 9.8 x Spacing of Purlin x Distance between Rafter

Total Factored Load = (60+75) x 1.5 x 9.8 x 1.2 x 8 = 19051.2 N = 19.0512 kN

Now, calculating Load on Each Sag Rod = (Total Factored Load/3 + Load due to Self Weight of Purlin/3) x `sin(15)`

Therefore, Load on Each Sag Rod = 2.3199 kN = 2319.9 N

Since, We know load on threaded rod is tension force,

therefore, Design Tension Force (Tdn) = `(0.9*Net Area* fu)/1.25`

Tdn = 0.9 * An * fu/1.25

An = (Tdn * 1.25)/(0.9*fu) ..................Let fu = 250MPa

An = 12.88 `mm^2`

Since, An = `pi/4*d^2`

Therefore, Diameter of Sag Rod = 4.049 mm < 16 mm

Hence, we will provide Sag Rod of 16 mm.

Result: We will provide Sag Rod of Diameter = 16 mm.

Solution.3)

Aim: Design of Single Angle Member for the given Loading Conditions.

Procedure:

Result: Hence ISA 150X150X12 is safe under given loading conditions and satisfy slenderness condition.