Challenge

Section Modulus calculation and optimization

SECTION MODULUS & calculation and optimization

Intro

 section modulus is a geometric property for a given cross-section used in the design of beam and flexural members. by finding the section modulus we can find the resistance to remain unchanged when the force is applying to the object or substances.

S= I / Y

S - section modulus

I - the moment of inertia

y - the distance between the neutral axis and the end of the object.

Moment of inertia

        Here we are considering the area moment of inertia also known as the second moment of inertia. it is used in a sectional mechanical application, usually involving a section of any structure. the shape of the object and the plane of the section will give us the 2d part it is called the section.

        when the area of the section increases the moment of inertia also increases. so the final result which is the section modulus also increases.

         so we could say section modulus is proportional to the moment of inertia.

objective

          To find a section modulus of the hood, and optimizing the section modulus value using NX_cad.

CONSIDERATION:

In this study, we take the minimum of inertia moment to analyze the minimum limit of hood deformation. Thus the section modulus of the front hood was calculated and compared with the new design.

 From the result we found out that increasing the cross-section area would give a better section modulus and helps in increasing the strength of the hood.

#Convertible sketch with blue to green 

Before Optimization

The Hood which was already created is imported and the section inertia analysis is done.

We have to make sure that the curve obtained is a single/closed curve.

The elastic section modulus is defined as

 S = I / y,

where

I is the second moment of area (or area moment of inertia, not to be confused with moment of inertia)

y is the distance from the neutral axis.

y=901.4482mm

Study 1

CALCULATION=       

  S=I/Y,                                               where           I = 1.790208151e4 mm^4

                                                                                     y = 901.4482/2 mm 

                                                                                         =450.7241mm

           = 1.790208151e4mm^4/450.7241mm

             =17902.0815/450.7241

        S = 39.7184919mm^3

this is the section modulus value for the hood section

Study 2

Come up with a new section that has an improved Section Modulus compared to the previous one in order to increased the strength

When I increased  the  inner panel by 1mm outward and outer pannel same as in study 1. I got the MOI as shown below:

CALCULATION=       

  S=I/Y,                                               where           I = 1.82412827e4 mm4

                                                                                     y = 901.4482/2 mm 

                                                                                         =450.7241mm

           = 1.82412827e4 mm4/450.7241mm

             =18242.827/450.7241

        S = 40.4744876mm^3

this is the section modulus value for the hood section

DIFFERENCE =40.4744876mm^3-39.7184919mm^3

                    = 0.7559957mm^3

RESULT:

section modulus was successfully determined and improvised by increasing the section area.

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