Section Modulus calculation and optimization

AIM:

Use the Section from your Hood design and calculate the Section Modulus using the formula

S = I/y

Come up with a new section that has an improved Section Modulus compared to the previous one and mention what changes you made which resulted in the increased strength.

For Hood Design

Section modules:

Section Modulus: The section modulus (S) is geometric property of the cross section used for designing beams and flexural members. It does not represent anything physically.

Formula of Section Modulus: It may be defined as the ration of total moment resisted by the section to the stress in the extreme fibre which is equal to yield stress.

There fore

S = I/Y, Where

S = Section modulus (mm^3)

I = Moment of Inertia of the section about the bending axis. (mm^4)

Y = Distance between the neutral axis and extreme end of the object (mm)

Case 1 :

For my hood design the moment of inertia values are,

Maximum moment of inertia = 6.197614475e+08[mm^4]

Minimum moment of inertia = 1.851842433e+06[mm^4] = 5.63382 [mm^4]

The total distance of the hood Y = 980.02 mm

Distance between the neutral axis to the extreme end = (980.02/2) = 490.01 mm

To find section modulus of HOOD section, we have to calculate

S= 5.63382 /490.01

= 0.01149735 mm^3

Case 2:

The hood inner panel’s curve is offset by 0.5mm outwards and section inertia analysis is done same as case 1 for a closed curve.

So I have made some changes in my HOOD design and its section is given as follows,

Maximum moment of inertia = 6.890330888e+06[mm^4]

Minimum moment of inertia = 2.032295706e+04[mm^4] = 5.924352488 [mm^4]

To find section modulus of new HOOD section, we have to calculate

S = 5.924352/490.01

= 0.01209 mm^3

From the above calculations, I got an improvement in section modulus for about 0.01209 mm³

so that I also made an improvement in resistance to bending of my HOOD design.

THANKYOU.....