Section Modulus calculation and optimization

Section modulus

It is the ratio of Moment of inetia of section about the neutral axis to the distance of outermost layer from neutral axis.

It of denoted by S ;

Section Modulus can be calculated by using the Formula:

S=I/y

(its unit is mm or m)

Where,

S = Section Modulus

I = Moment of inertia

Y = Distance from the neutral axis to the most extreme end of the object

Total distance between extreme ends =882.13mm

Distance from the neutral axis to the most extreme end of the object (Y): 882.13/2 =441.06mm

Case1

I_{max =}1.046862215e+07mm⁴

I_min=4.787005776e+04mm⁴

Simply

I_max=10468622.15mm

I_min=47870.05776mm

Section modulus(I/Y)=  10468622.15/441.06=23,735.14mm³(maximum strength)

Section modulus(I/Y)=  47870.05776/441.06=108.534099668mm³(minimum strength)

So the strength of  hood varies from 108.53mm³ to 23735.14mm³

Case2

When inner panel distance is increased by 0.5mm

I_{max =}1.046435862e+07mm⁴

I_min=4.783572114e+04mm⁴

Simply

I_max=10464358.62mm

I_min=47835.72114mm

Section modulus(I/Y)=  10464358.62/441.06=23,725.47mm³(maximum strength)

Section modulus(I/Y)=  47835.72114/441.06=108.4562mm³(minimum strength)

So the strength of  hood varies from 108.45mm³ to 23725.45mm³

Conclusion

The strength of the material is directly proportional to the moment of inertia, hence increase  in sectional area there is have increase in overall mass of an object ,hence have increase in  strength.