Section Modulus calculation and optimization
Aim:To find the moment of inertia of the Hood design and to calculate the section modulus .
HOOD DESIGN
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Product : Face...Fill.1...Hood
Date : Monday, 12 April 2021 11:35:18
Author : Admin
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Component | Sub-Component | Area[m2] | Gx[mm] | Gy[mm] | Gz[mm] | M1[m4] | M2[m4] | IoxG[m4] | IoyG[m4] | IxyG[m4] |
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Face...Fill.1...LATCH.2 | | 0.011 | 22.882 | 745.770 | -910.480 | 1.37435e-06 | 0.000181929 | 1.374e-006 | 1.819e-004 | 2.507e-019 |
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S=I/Y
Y=479.129/2
=239.4625mm
I=1.374*10^6m^4
S=1.374*10^7/239.4625
=57.3785*10^6mm^4.
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Product : Face...Fill.2...LATCH.2
Date : Monday, 12 April 2021 12:26:41
Author : Skill_Lync
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Component | Sub-Component | Area[m2] | Gx[mm] | Gy[mm] | Gz[mm] | M1[m4] | M2[m4] | IoxG[m4] | IoyG[m4] | IxyG[m4] |
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Face...Fill.2...LATCH.2 | | 0.010 | 22.882 | 746.646 | -907.656 | 1.05384e-06 | 0.000155887 | 1.054e-006 | 1.559e-004 | -5.421e-020 |
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S=Y/I
Y=479.129/2
=239.5645mm.
I=1.054*10^6m^4
S=1.054*10^7/239.5645
S =43.96mm^4.
Conclusion
So decreasing the distance between the two panels leads to the increment in teh section modulus ,so resistance to bending also increases and the strength of the HOOD also increases.