Project on Concrete Mix Design for various grades of Concrete
*1. Calculate the Concrete Mix Design for M35 grade concrete with fly ash
mix design is used to increase the workability of concrete .instead of nominal mix , mix design perform very accurate and increase strength and durable to concret.. and with fly ash also increase workability and improve the flow of concrete...,
- aim:Calculate the Concrete Mix Design for M35 grade concrete with fly ash
procedure;
grade designation : M35
cement : grade (43)
maximum size of aggregte =20mm.. as per is 10262:2009
exposure condition: extreme .
mini cement =360kg/m^3
workability need = 100mm
methods of concrete placing=pumpable
chem adm=superplastisizer
min adm=fly ash
s-g of fly ash=2.2
s-g of superplastisizer=1.14
# findout the target mean strength
f'ck=fck+1.65(5)
=35+1.65(5)
= 43.25kn/mm^2
where,fck is a compressive strength in
28 days is n/mm^2
s is a standard deviation as per is 10262:2009
#calculate the water cement ratio
as per IS 456:2000 the water cement ratio is 0.40
its depend on the exposure condition
based on experience the w/c is 0.35<0.40 hence ok..
w/c=0.35
#cal water content
as per IS 10262:2009 the max size of aggregate for 20mm=186L
for slump (25-50mm)=186L
for 100 mm slump , for adding each 25mm to add 3% of water cont
water content=186+(0.06*186)
=197L
for adding superplastisizer the 20% of water should be reduced
By the trial method the water is reduced by 29%
=197*0.71
water =140L
# the cement content
w/c=0.35
c=140/0.35
c=400kg/m^3
400>360kg/m^3
hence ok.
#the cement material with fly ash
fly ash is used therefore the cement is increased by 10 %
=400*1.1
=440kg/m^3
fly ash @ 30% with cementious material
440*0.3=132kg/m^3(fly ash)
cement content=440-132
cement content =308kg/m^3
cement saved by adding fly ash =400-308
= 92kg/m^3
fly ash utilized=132kg/m^3
#volume of aggregate
as per is 10262:2009 20mm aggregate and fine for water cement ratio is
0.5=0.62 (zone-2)
but we have 0.35=0.62
rule is we need 0.15 to reach the number 0.5
for every 0.5 we should add 0.01 to zone value 0.62is (0.63)
here 0.35=0.65
for pumpable concrete 10% of coarse aggregate reduced
because , perhaps the angular aggregate is present
voume of coarse aggregate=0.65*0.9
=0.585
volume of fine aggregate =1-0.585
=0.415
#mix calculation
1. volume of concrete=1m^3
2.volume of cement= mass of cement/s-gof cement *1/1000
=308/3.14/1000
=0.098m^3
3.volume of water= mass of water/s-g of water *1/1000
=140/1/1000
=0.14m^3
4.volume of fly ash= mass of fly ash/s-g of fly ash *1/1000
=132/2.2/1000
=0.06m^3
5.volume of chem adm= mass of chem adm/s-g of chem adm *1/1000
[chem adm=2%*400=8] =8/1.14/1000
=0.007m^3
6.volume of aggregates=1-{2+3+4+5}
=1-{0.098m^3+0.14m^3+0.06m^3+0.007m^3}
=0.695m^3
7.mass of CA=6*vol of CA*s-g of CA*1000
=0.695*0.585*2.74*1000
=582kg/m^3
8.mass of FA=6*vol of FA*s-g of FA*1000
=0.695*0.415*2.74*1000
=412kg/m^3
# mix proportion
- cement(308)kg/m^3
- water(140)kg/m^3
- FA(412)kg/m^3
- CA(582)kg/m^3
- chem adm(8)kg/m^3
- fly ash(132)kg/m^3
- w/c=0.35
# the mix ratio for M35=1:1.3:1.8
2. calculate the concrete mix designM50 grade concrete without Fly ash
aim:calculate the concrete mix designM50 grade concrete without Fly ash
procedure:
grade designation : M35
cement : grade (53)
maximum size of aggregte =20mm.. as per is 10262:2009
exposure condition: very severe .
mini cement =340kg/m^3
workability need = 75mm
methods of concrete placing=pumpable
chem adm=superplastisizer
s-g FA=2.74
s-g FA=2.74
s-g of superplastisizer=1.15
# findout the target mean strength
f'ck=fck+1.65(5)
=35+1.65(5)
= 58.25kn/mm^2
where,fck is a compressive strength in
28 days is n/mm^2
s is a standard deviation as per is 10262:2009
#calculate the water cement ratio
as per IS 456:2000 the water cement ratio is 0.45
its depend on the exposure condition
based on experience the w/c is 0.40<0.45 hence ok..
w/c=0.40
#cal water content
as per IS 10262:2009 the max size of aggregate for 20mm=186L
for slump (25-50mm)=186L
for 100 mm slump , for adding each 25mm to add 3% of water cont
water content=186+(0.03*186)
=190L
for adding superplastisizer the 20% of water should be reduced
By the trial method the water is reduced by 29%
=190*0.71
water =134L
# the cement content
w/c=0.40
c=140/0.40
c=335kg/m^3
335<340kg/m^3
c=340kg/m^3
hence ok.
#volume of aggregate
as per is 10262:2009 20mm aggregate and fine for water cement ratio is
0.5=0.60 (zone-1)
but we have 0.40=0.60
rule is we need 0.15 to reach the number 0.5
for every 0.5 we should add 0.01 to zone value 0.60 is(0.61)
here 0.40=0.62
for pumpable concrete 10% of coarse aggregate reduced
because , perhaps the angular aggregate is present
voume of coarse aggregate=0.62*0.9
=0.558
volume of fine aggregate =1-0.558
=0.442
#mix calculation
1. volume of concrete=1m^3
2.volume of cement= mass of cement/s-gof cement *1/1000
=340/3.14/1000
=0.108m^3
3.volume of water= mass of water/s-g of water *1/1000
=134/1/1000
=0.134m^3
4.volume of chem adm= mass of chem adm/s-g of chem adm *1/1000
[chem adm=2%*340=6.8] =6.8/1.15/1000
=0.0059m^3
5.volume of aggregates=1-{2+3+4}
=1-{0.108m^3+0.134m^3+0.0059m^3}
=0.7521m^3
6.mass of CA=5*vol of CA*s-g of CA*1000
=0.7521*0.558*2.74*1000
=1149kg/m^3
7.mass of FA=6*vol of FA*s-g of FA*1000
=0.7521*0.442*2.74*1000
=910kg/m^3
# mix proportion
- cement(340)kg/m^3
- water(134)kg/m^3
- FA(910)kg/m^3
- CA(1149)kg/m^3
- chem adm(6.8)kg/m^3
- w/c=0.40
# the mix ratio for M35=1:2.6:3.3