Project on Concrete Mix Design for various grades of Concrete
ANS
CALCULATION OF M35 GRADE OF CONCRETE WITH FLY ASH
-DATA
Grade of concrete = M35
Type of cement =OPC 43
Type of mineral admixture = Fly Ash
Max size of aggregate = 20mm
Min cement content = 320Kg/m3
Max water/cement ratio = 0.45
Workability = 100mm
Exposure Condition = severe
Max cement content = 450Kg/m3
Admixture = superplasticizere
DATA FOR MATERIALS
specific gravity of cement= 3.15
specific gravity of fly ash = 2.2
specific gravity of coarse aggregate = 2.74
specific gravity of fine aggregate = 2.74
water absorption in coarse agg = 0.5%
water absorption in fine agg = 1.0%
TARGET STRENGTH FOR MIX PROPOTION
f'ck = fck+1.65s
=35+1.65(5)
=43.25N/mm2
SELECTION OF W/C RATIO
Max water content = 186 litr
Estimated water content for 100mm slump = 186+6/100*186
=197 litr
due to admixture water content can be reduced upto 30%
=197*0.71
=140 ltr
CALCULATION OF CEMENT+FLY ASH CONTENT
w/c ratio = 0.45
cement + fly ash content + 140/0.45 = 311.11<320
min content should be 320 so we take 320
Cementious Material concrete = 320*1.10
=352Kg/m3
water content is 140
so w/c ratio =140/352 = 0.397
fly ash @ 30% content=352*0.30
=105Kg/m3
cement = 352-105
= 247 Kg/m3
PROPORTION OF VOLUME OF COARSE AGG AND FINE AGG.
Frome table 3,
zone I = 50:60
so for 0.45 w/c ratio it is
0.45:0.61
For pumpable concrete these value should by 10%
Volume of coarse aggregate = 0.61*0.9 = 0.54
Volume of fine aggregate = 1-0.54 = 0.46
MIX CALCULATION
(a) volume of concrete = 1 m3
(b) volume of cement = (mass of cement /specific gravity of cement )* 1/1000
= 247/3.15 * 1/1000
= 0.078 m3
(c)volume of fly ash = (mass of fly ash/specific gravity of fly ash)* 1/1000
= 105/i * 1/1000
= 0.047 m3
(d)Volume of water = (Mass of water/specific gravity of water)* 1/1000
= 140/1 * 1/1000
= 0.140
(e)Volume of chemical admixture = 7/1.145 * 1/1000
= 0.006 m3
(f) Volume of all in aggregate = [a-(b+c+d+e)]
= [1-(0.078+0.047+0.140+0.06)]
=0.893
(g)Mass of coarse aggregate = e * volume of coarse aggreagte * specific gravity of coarse aggregate* 1000
= 0.893 * 0.54 * 2.74 * 1000
= 1321 Kg
(h)Mass of fine aggregate = e * volume of fine aggregate * specific gravity of fine aggregate * 1000
= 0.893*0.46*2.74*1000
= 1125 Kg
MIX PROPORTIONS
Cement = 247 kg/m3
Fly ash = 105 kg/m3
water = 140 kg/m3
fine aggregate = 1125 kg/m3
coarse aggregate = 1321 kg/m3
chemical admixture = 7 kg/m3
w/c ratio = 0.397.
CALCULATION OF M50 GRADE OF CONCRETE WITHOUT FLY ASH
-DATA
Grade of concrete = M50
Type of cement =OPC 43
Max size of aggregate = 20mm
Min cement content = 320Kg/m3
Max water/cement ratio = 0.45
Workability = 100mm
Exposure Condition = severe
Max cement content = 450Kg/m3
Admixture = superplasticizere
DATA FOR MATERIALS
specific gravity of cement= 3.15
specific gravity of coarse aggregate = 2.74
specific gravity of fine aggregate = 2.74
water absorption in coarse agg = 0.5%
water absorption in fine agg = 1.0%
TARGET STRENGTH FOR MIX PROPOTION
f'ck = fck+1.65s
=50+1.65(5)
=58.25N/mm2
SELECTION OF W/C RATIO
Max water content = 186 litr
Estimated water content for 100mm slump = 186+6/100*186
=197 litr
due to admixture water content can be reduced upto 30%
=197*0.71
=140 ltr
CALCULATION OF CEMENT CONTENT
w/c ratio = 0.45
cement content = 140/0.45
= 311.11<320
min cement content should be taken 320.
PROPORTION OF VOLUME OF COARSE AGG AND FINE AGG.
Frome table 3,
zone I = 50:60
so for 0.45 w/c ratio it is
0.45:0.61
For pumpable concrete these value should by 10%
Volume of coarse aggregate = 0.61*0.9 = 0.54
Volume of fine aggregate = 1-0.54 = 0.46
MIX CALCULATION
(a) volume of concrete = 1 m3
(b) volume of cement = (mass of cement /specific gravity of cement )* 1/1000
= 320/3.15 * 1/1000
= 0.101 m3
(c)Volume of water = (Mass of water/specific gravity of water)* 1/1000
= 140/1 * 1/1000
= 0.140
(d)Volume of chemical admixture = 7/1.145 * 1/1000
= 0.006 m3
(e) Volume of all in aggregate = [a-(b+c+d)]
= [1-(0.101+0.140+0.06)]
=0.753
(f)Mass of coarse aggregate = e * volume of coarse aggreagte * specific gravity of coarse aggregate* 1000
= 0.753 * 0.54 * 2.74 * 1000
= 1114Kg
(g)Mass of fine aggregate = e * volume of fine aggregate * specific gravity of fine aggregate * 1000
= 0.753*0.46*2.74*1000
= 949 Kg
MIX PROPORTIONS
Cement = 320 kg/m3
water = 140 kg/m3
fine aggregate = 949 kg/m3
coarse aggregate = 1114 kg/m3
chemical admixture = 7 kg/m3
w/c ratio = 0.397