Project on Concrete Mix Design for various grades of Concrete
Answer-1 :-
Aim :- Mix Design for M35 Grade Concrete with Fly Ash.
- Stipulations for Proportioning :-
- Grade designation : M35
- Type of cement : OPC 53 Grade Conforming to IS 8112
- Type of Admixture : Fly Ash Conforming to IS 3812
- Maximum nominal size of aggregate : 20mm
- Minimum cement content : 320 kg/m3 (IS 456:2000)
- Maximum water-cement ratio : 0.45 (Table 5 of IS 456:2000)
- Workability : 100 mm slump
- Exposure condition : Severe (For Reinforced Concrete)
- Method of concrete placing : Pumping
- Degree of supervision : Good
- Type of aggregate : Crushed Angular Aggregates
- Maximum cement content : 45 kg/m3
- Chemical admixture type : Fly Ash
- Test data for Material :-
- Cement used : OPC 53 Grade
- Specific gravity of cement : 3.15
- Chemical admixture : Fly ash conforming to IS 12089
- Specific gravity of
1) Coarse aggregate 20mm : 2.74
2) Fine aggregate : 2.74 - Water absorption:
1) Coarse aggregate : 0.5 %
2) Fine aggregate (M.sand) : 1 % - Free (surface) moisture:
1) Coarse aggregate : Nil (Absorbed Moisture also Nil)
2) Fine aggregate : Nil - Sieve analysis:
1) Coarse aggregate: Conforming to all in aggregates of Table 2 of IS 383
2) Fine aggregate : Conforming to Grading Zone II of Table 4 of IS 383
- Target Strength fo Mix Proportioning :-
f’ck =fck + 1.65 S
where
f’ck = target average compressive strength at 28 days,
fck = characteristics compressive strength at 28 days, and
S = standard deviation.
From Table I of IS 10262:2009, Standard Deviation, S = 5 N/mm2. Therefore, target strength = 35 + 1.65 x 5 = 43.25 N/mm2.
- Selection Of Water-Cement Ratio :-
Adopted maximum water-cement ratio = 0.45.
From the Table 5 of IS 456 for Very severe Exposure maximum Water Cement Ratio is 0.45. Hence ok.
- Selection of Water Content :-
From Table 2 of IS 10262:2009, maximum water content for 20 mm aggregate = 186 litre (for 25 to 50 mm slump range) Estimated water content for 100 mm slump = 186+ (6/186) = 197 litre.
Based on trials with Super plasticizer water content reduction of 20% has been achieved.
Hence the arrived water content = 197-[197 x (20/100)] = 158 litre.
Adopted Water Content = 160 L.
- Cement Content :-
Adopted w/c Ratio = 0.44
Cement Content = 160/0.45 = 356 kg/m3
Final Cementitious Content (Cement + Flyash) = 356*1.10
=391.6 Kg
From Table 5 of IS 456, Minimum cement content for ‘Severe’ exposure conditions = 340kg/m3
= 391.6 kg/m3 > 340 kg/m3 hence ok.
Fly ash content requirement = 391.6*0.30
= 117.48 = 118 Kg
Cement Content requirement = Cementious content - Fly ash
= 391.6 - 117.48
= 274.12
- Volume of Coarse aggregate and fine aggregates :-
From Table 3 of (IS 10262:2009) Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone II) for water-cement ratio of 0.50 =0.62 .
In the present case water-cement ratio is 0.44. Therefore, volume of coarse aggregate is required to be increased to decrease the fine aggregate content. As the water-cement ratio is lower by 0.06. The proportion of volume of coarse aggregate is increased by 0.02 (at the rate of -/+ 0.01 for every ± 0.05 change in water-cement ratio).
Therefore, corrected proportion of volume of coarse aggregate for the water-cement ratio of 0.44 = 0.63.
Therefore, volume of coarse aggregate =0.63.
Volume of fine aggregate content = 1 – 0.63= 0.37.
- Mix Calculations :-
The mix calculations per unit volume of concrete shall be as follows:
a) Volume of concrete = 1 m3
b) Volume of cement = [Mass of cement] / [Specific Gravity of Cement] x 1000
= 275/{3.15 x 1000}
= 0.087 m3
C)Volume of Fly ash = [Mass of Fly ash] / [Specific Gravity of Fly ash] x 1000
= 118/{2.5 x 1000}
= 0.041 m3
d) Volume of water = [Mass of water] / [Specific Gravity of water] x 1000
= 160/{1 x 1000}
= 0.160 m3
e) Volume of chemical admixture = 0.71 litres/ m3 (By Trial and Error Method used 0.4% by the weight cement)
e) Volume of all in aggregate = [a-(b+c+de)]
= [1-(0.087 +0.041+0.160+0.002)]
= 0.71 m3
f) Mass of coarse aggregate= e x Volume of Coarse Aggregate x Specific Gravity of Fine Aggregate x 1000
= 0.71*0.63 *2.74 *1000
= 1225.6 Kg
g) Mass of fine aggregate= e x Volume of Fine Aggregate x Specific Gravity of Fine Aggregate x 1000
= 0.71*0.37*2.74 *1000
= 719.8 Kg
- Mix Proportions :-
Cement = 275 kg/m3
Water = 160 l/m3
Fine aggregate = 719.8 kg
Coarse aggregate 20mm =1226 kg
Chemical admixture = 7 kg/m3 (0.4% by the weight of cement)
Density of concrete = 2430 kg/m3
Water-cement ratio = 0.44
Result :- Cement : Flyash: F.A : C.A : Water = 1 : 0.4 : 2.6 : 4.46 : 0.58
Answer-2 :-
Aim :- Mix Design for M50 Grade Concrete.
- Stipulations for Proportioning :-
a) Grade designation : M50
b) Type of cement : OPC 43 Grade Conforming to IS 8112
c) Maximum nominal size of aggregate : 20mm
d) Minimum cement content : 320 kg/m3 (IS 456:2000)
e) Maximum water-cement ratio : 0.45 (Table 5 of IS 456:2000)
f) Workability : 100 slump
g) Exposure condition : Severe (For Reinforced Concrete)
h) Method of concrete placing : Pumping
j) Degree of supervision : Good
k) Type of aggregate : Crushed Angular Aggregates
m) Maximum cement content : 450 kg/m3
n) Chemical admixture type : Super Plasticizer
- Test data for Material :-
a) Cement used : OPC 53 Grade Conforming to IS 8112
b) Specific gravity of cement : 3.15
c) Chemical admixture : Super Plasticizer conforming to IS 9103
d) Specific gravity of
1) Coarse aggregate 20mm : 2.74
2) Fine aggregate : 2.74
e) Water absorption:
1) Coarse aggregate : 0.5 %
2) Fine aggregate (M.sand) : 1 %
f) Free (surface) moisture:
1) Coarse aggregate : Nil (Absorbed Moisture also Nil)
2) Fine aggregate : Nil
g) Sieve analysis:
1) Coarse aggregate: Conforming to all in aggregates of Table 2 of IS 383
2) Fine aggregate : Conforming to Grading Zone II of Table 4 of IS 383
- Target Strength fo Mix Proportioning :-
f’ck =fck + 1.65 s
where
f’ck = target average compressive strength at 28 days,
fck = characteristics compressive strength at 28 days, and
s = standard deviation.
From Table I of IS 10262:2009, Standard Deviation, s = 5 N/mm2. Therefore, target strength = 50 + 1.65 x 5 = 58.25 N/mm2.
- Selection Of Water-Cement Ratio :-
Adopted maximum water-cement ratio = 0.4.
From the Table 5 of IS 456 for Very severe Exposure maximum Water Cement Ratio is 0.45.
0.4 < 0.45 Hence ok.
- Selection of Water Content :-
From Table 2 of IS 10262:2009, maximum water content for 20 mm aggregate = 186 litre (for 25 to 50 mm slump range) Estimated water content for 100 mm slump = 186+ (6/186) = 197 litre.
(Note: If Super plasticizer is used, the water content can be reduced upto 20% and above.)
Based on trials with Super plasticizer water content reduction of 20% has been achieved.
Hence the arrived water content = 197-[197 x (29/100)] = 140 litre.
- Cement Content :-
Adopted w/c Ratio = 0.4
Cement Content = 140/0.4 = 350 kg/m3
From Table 5 of IS 456, Minimum cement content for ‘severe’ exposure conditions 320kg/m3
= 350 kg/m3 > 340 kg/m3 hence ok.
- Volume of Coarse aggregate and fine aggregates :-
From Table 3 of (IS 10262:2009) Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone II) for water-cement ratio of 0.50 =0.6 .
In the present case water-cement ratio is 0.44. Therefore, volume of coarse aggregate is required to be increased to decrease the fine aggregate content. As the water-cement ratio is lower by 0.06. The proportion of volume of coarse aggregate is increased by 0.02 (at the rate of -/+ 0.01 for every ± 0.05 change in water-cement ratio).
Therefore, corrected proportion of volume of coarse aggregate for the water-cement ratio of 0.44 = 0.64
For pumpable concrete these values should be reduced up to 10%.
Therefore, volume of coarse aggregate =0.64 x 0.9 =0.576.
Volume of fine aggregate content = 1 – 0.576= 0.424.
- Mix Calculations :-
The mix calculations per unit volume of concrete shall be as follows:
a) Volume of concrete = 1 m3chrome://history/
b) Volume of cement = [Mass of cement] / [Specific Gravity of Cement] x 1000
= 350 / {3.15 x 1000}
= 0.111 m3
c) Volume of water = [Mass of water] / [Specific Gravity of water] x 1000
= 140 / {1 x 1000}
= 0.140 m3
d) Volume of chemical admixture = (Mass of Superplasticizer / Specific gravity of admixture) X (1/1000)
= (8.2/1.145) X (1/1000)
= 0.007 m3
e) Volume of all in aggregate = [a-(b+c+d)]
= [1-(0.111+0.140+0.006)]
= 0.743 m3
f) Mass of coarse aggregate= e x Volume of Coarse Aggregate x Specific Gravity of Fine Aggregate x 1000
= 0.743x 0.576 x 2.74 x 1000
= 1173 kg/m3
g) Mass of fine aggregate= e x Volume of Fine Aggregate x Specific Gravity of Fine Aggregate x 1000
= 0.743x 0.424x 2.74 x 1000
= 863 kg/m3
- Mix Proportions :-
Cement = 350 kg/m3
Water = 140 l/m3
Fine aggregate = 863 kg/m3
Coarse aggregate 20mm = 1173 kg/m3
Chemical admixture = 7 kg/m3 (0.4% by the weight of cement)
Density of concrete = 2430 kg/m3
Water-cement ratio = 0.4
Result :- Mix Proportion By weight = 1:2.46:3.35
Tables Used are
- Table : 8 of IS 10262
- Table : 5 of IS 456 : 2000
- Table : 8 of IS 10262 : 2009
- Table : 3 of IS 10262 : 2009