Project on Concrete Mix Design for various grades of Concrete
Mix Design Grade M35
Data Collection (Assumed)
Supervision = Good
Exposure = Severe
Minimum Cement Content = 320Kg
Specific Gravity of Cement = 3.15
Specific Gravity of Fly ash = 2.20
Specific Gravity of Coarse Aggregate = 2.74
Specific Gravity of Fine Aggregate = 2.74
Specific Gravity of Chemical Admixture = 1.14
Maximum Water Cement Ratio = 0.45 (IS 456 :2000)
Maximum WaterContent = 186Kg(IS 10262 : 2009)
Aggregate = Angular
Slump = 100mm
Admixture = Super plasticizer
Mean Target Strength
Mean Target Strength f'ck = fck + 1.65S where fck = 35, S = 5
f'ck = 35 + (1.65*5)
= 43.25
Water Cement Ratio
Water Cement Ratio, Maximum water cement ratio shall be 0.45, By experience & conservative 0.40 shall be adopted
Maximum Water content
186kg is the maximum water content given for 20mm nominal size aggregate 50mm slump in IS 10262 : 2009, For every 25mm increase in slump 3% water can be added hence
Water content = 186 + (186 * 6/100 )
= 197 Kg
If Superplasticizer was used, Water content can be reduced by 30%, However by trail and error method 29% can be adopted by experience
= 197 - (197*0.29)
= 197 - 57
= 140 kg
Cement Content & Fly ash
Cement Content shall be
WC ratio = W /C
0.4 = 140 / C
C = 140/0.4
C = 350 Kg > 320 Kg
Fly Ash Shall be added maximum upto 30%,
Fly ash = 0.3 * 350
= 105 kg
Cement = 350 - 105
= 245 kg
Cement shall be increased by 10 %
Cement = 245 *1.10
= 270 kg
Chemical Admixture
Chemical Admixture @2 percent mass of cementious material
2% of Cement = 350*.02
= 7 kg
Volume of Cement, Water, Flyash and Chemical Admixture
Volume of Cement = Mass of Cement / Specific gravity * 1 /1000
= 270/3.15 * 1/1000
= 0.086
Volume of Flyash = Mass of Flyash / Specific gravity * 1 /1000
= 105/2.2 * 1 /1000
= 0.047
Volume of Water = Mass of Water / Specific gravity * 1 /1000
= 140/1*1/1000
= 0.14
Volume of Admixture = Mass of Chemical Admixture / Specific gravity * 1 /1000
= 7/2.2*1/1000
= 0.0032
Volume of Coarse aggregate and Fine Aggregate
= a-(b+c+d)
a = volume of concrete = 1
b = volume of cement + fly ash
c = volume of water
d = volume of chemical admixture
= 1 - (0.086+0.047+.014+0.0032)
= 1 - 0.2762
= 0.7238
Volume of Coarse aggregate and Fine Aggregate
Volume of Coarse aggregate given in IS 10262 : 2009 for given water cement ratio 0.45 Zone 1 grading = 0.60, + or - 5% in WC ratio will increase the value by 0.01, 10% reduction change the volume of coarse aggregate by 0.62
Since it was pumpable concrete, to increase the fine aggregate, the coarse aggregate was reduced by 10 %
= 0.62 *.9
= 0.56
Volume of Fine Aggregate = 1 - Volume of Fine Aggregate
= 1 - 0.56
= 0.44
Mass of Fine Aggregate and Coarse Aggregate
Mass of Coarse Aggregate = e * Volume of Coarse Aggregate * Specific Gravity * 1000
e = Volume obtained by deducting the volume of cement, water, and admixture
e = 0.7238
= 0.7238 * 0.56 *2.74 * 1000
Mass of CA = 1110 Kg
Mass of Fine Aggregate = e * Volume of Fine Aggregate * Specific Gravity * 1000
e = Volume obtained by deducting the volume of cement, water, and admixture
e = 0.7238
= 0.7238 * 0.44 *2.74 * 1000
Mass of CA = 872.6 Kg
Mix proportions of Cement, Fly ash, Water, CA, FA and Chemical Admixture
Cement = 270 kg
Fly Ash = 105 kg
Water = 197 kg
Chemical Admixture = 7 kg
Coarse Aggregate = 1110 kg
Fine Aggregate = 872.6 kg
Water cement ration = 0.40
Cement saved = 80 kg
Mix ratio
1 : 2.33 : 2.96
Mix Design Grade M50
Data Collection (Assumed)
Supervision = Good
Exposure = Extreme
Minimum Cement Content = 360Kg
Specific Gravity of Cement = 3.15
Specific Gravity of Fly ash = 2.20
Specific Gravity of Coarse Aggregate = 2.74
Specific Gravity of Fine Aggregate = 2.74
Specific Gravity of Chemical Admixture = 1.14
Maximum Water Cement Ratio = 0.40 (IS 456 :2000)
Maximum WaterContent = 186Kg(IS 10262 : 2009)
Aggregate = Angular
Slump = 100mm
Admixture = Super plasticizer
Water Absorbtion for Coarse Aggregate = 5
Water Absorbtion for Fine Aggregate = 1
Mean Target Strength
Mean Target Strength f'ck = fck + 1.65S where fck = 50, S = 5
f'ck = 50 + (1.65*5)
= 58.25
Water Cement Ratio
Water Cement Ratio, Maximum water cement ratio shall be 0.40, By experience & conservative 0.36 shall be adopted
Maximum Water content
186kg is the maximum water content given for 20mm nominal size aggregate 50mm slump in IS 10262 : 2009, For every 25mm increase in slump 3% water can be added hence
Water content = 186 + (186 * 6/100 )
= 197 Kg
If Superplasticizer was used, Water content can be reduced by 30%, However by trail and error method 29% can be adopted by experience
= 197 - (197*0.29)
= 197 - 57
= 140 kg
Cement Content
Cement Content shall be
WC ratio = W /C
0.36 = 140 / C
C = 140/0.36
C = 388 Kg > 360 Kg
Chemical Admixture
Chemical Admixture @2 percent mass of cementious material
2% of Cement = 388*.02
= 7.76 kg
Volume of Cement, Water and Chemical Admixture
Volume of Cement = Mass of Cement / Specific gravity * 1 /1000
= 388/3.15 * 1/1000
= 0.123
Volume of Water = Mass of Water / Specific gravity * 1 /1000
= 140/1*1/1000
= 0.14
Volume of Admixture = Mass of Chemical Admixture / Specific gravity * 1 /1000
= 7/2.2*1/1000
= 0.0032
Volume of Coarse aggregate and Fine Aggregate
= a-(b+c+d)
a = volume of concrete = 1
b = volume of cement + fly ash
c = volume of water
d = volume of chemical admixture
= 1 - (0.0123+.014+0.0032)
= 1 - 0.2662
= 0.7338
Volume of Coarse aggregate and Fine Aggregate
Volume of Coarse aggregate given in IS 10262 : 2009 for given water cement ratio 0.40 Zone 1 grading = 0.60, + or - 5% in WC ratio will increase the value by 0.01, 10% reduction change the volume of coarse aggregate by 0.62
Since it was pumpable concrete, to increase the fine aggregate, the coarse aggregate was reduced by 10 %
= 0.62 *.9
= 0.56
Volume of Fine Aggregate = 1 - Volume of Fine Aggregate
= 1 - 0.56
= 0.44
Mass of Fine Aggregate and Coarse Aggregate
Mass of Coarse Aggregate = e * Volume of Coarse Aggregate * Specific Gravity * 1000
e = Volume obtained by deducting the volume of cement, water, and admixture
e = 0.7338
= 0.7338 * 0.56 *2.74 * 1000
Mass of CA = 1126 Kg
Mass of Fine Aggregate = e * Volume of Fine Aggregate * Specific Gravity * 1000
e = Volume obtained by deducting the volume of cement, water, and admixture
e = 0.7338
= 0.7338 * 0.44 *2.74 * 1000
Mass of CA = 884.6 Kg
Mix proportions of Cement, Water, CA, FA and Chemical Admixture
Cement = 388 kg
Water = 197 kg
Chemical Admixture = 7.76 kg
Coarse Aggregate = 1126 kg
Fine Aggregate = 884.6 kg
Water cement ratio = 0.36
Mix ratio
1 : 2.27 : 2.90