Challenge

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory)

Overview of the Project:

In this project, interfaces for mathematical Set Theory are implemented using C programming language. User can give the input like two list of data and this program will give the output as the union and intersection of these two lists.

Goals:

  • Implementation of interface for mathematical Set Theory using C programming.
  • Giving two list of data as input to get the output as union & intersection for given list of data.

Key Highlights of the Project:

  • Creating two list of data using linked list method.
  • Insert the node to 1st and 2nd list accordingly.
  • Intersection of data of two lists.
  • Getting Union of two list.

Deliverables of this project:

  • Intersection of data of two list.
  • Union of data of two list.

Program:

//Program that utilizes the linked lists and nodes for giving the union and intersection of two lists
//header files of
//standard boolean library
#include <stdbool.h>
//standard input output library
#include <stdio.h>
//standard C library
#include <stdlib.h>
// Linked list node using a structure
struct Node {
    //data as integer
	int data;
    //creating the node pointer
	struct Node* next;
};
//function declaration
void push(struct Node** head_ref, int new_data);
int isPresent(struct Node* head, int data);
// Function to get union of two linked lists head1 and head2
struct Node* getUnion(struct Node* head1, struct Node* head2)
{
    struct Node* result = NULL;
    struct Node *t1 = head1, *t2 = head2;
    // Insert all elements of list1 to the result list
    while (t1 != NULL)
    {
        push(&result, t1->data);
        t1 = t1->next;
     }
    // Insert those elements of list2 which are not present in result list
    while (t2 != NULL)
    {
        if (!isPresent(result, t2->data))
        {
            push(&result, t2->data);
        }
        t2 = t2->next;
    }
    return result;
}
// Function to get intersection of two linked lists head1 and head2
struct Node* getIntersection(struct Node* head1, struct Node* head2)
{
    struct Node* result = NULL;
    struct Node* t1 = head1;
    // Traverse list1 and search each element of it in list2.
    //If the element is present in list 2, then insert the element to result list
    while (t1 != NULL)
    {
        if (isPresent(head2, t1->data))
        {
            push(&result, t1->data);
        }
        t1 = t1->next;
    }
    return result;
}
// A utility function to insert a node at the beginning of a linked list
void push(struct Node** head_ref, int new_data)
{
    // allocating the  node
    struct Node* new_node = (struct Node*)malloc(sizeof(struct Node));
    // putting in the data
    new_node->data = new_data;
    // link the old list to the new node
    new_node->next = (*head_ref);
    // move the head to point the new node
    (*head_ref) = new_node;
}
// function to print a linked list
void printList(struct Node* node)
{
    while (node != NULL)
    {
        printf("%d ", node->data);
        node = node->next;
    }
}
// function that returns true if data is present in linked list else return false
int isPresent(struct Node* head, int data)
{
    struct Node* t = head;
    while (t != NULL)
    {
        if (t->data == data)
        {
            return 1;
        }
        t = t->next;
    }
    return 0;
}
// Main program to test above functions
int main()
{
    //creating three values n as first list and m as second list
	int n,m,temp;
    printf("enter the total elements in list1:");
    fflush(stdout);
    scanf("%d", &n);
    printf("enter the total elements in list1:");
    fflush(stdout);
    scanf("%d", &m);
    // Start structure pointer with the empty list
    struct Node* head1 = NULL;
    struct Node* head2 = NULL;
    struct Node* intersection = NULL;
    struct Node* getunion = NULL;
    //for loop to link list1
    for(int i=0;i<n;i++)
    {
        printf("Enter the values of list1:");
        fflush(stdout);
        scanf("%d", &temp);
        push(&head1, temp);
    }
   //for loop to link list2
   for(int i=0;i<m;i++)
   {
       printf("Enter the values of list2:");
        fflush(stdout);
        scanf("%d", &temp);
        push(&head2, temp);

   }
   //calling the function of intersection
    intersection = getIntersection(head1, head2);
    //calling the function of union
    getunion = getUnion(head1, head2);
    printf("\n First list is ");
    //function calling with structure pointer as argument
    //printing the head1 as it has the list1
    printList(head1);
    printf("\n Second list is: ");
    //printing the head2 as it has list2
    printList(head2);
    printf("\n Intersection of the two lists is: ");
    printList(intersection);
    printf("\n Union of the two lists is: ");
    printList(getunion);
    return 0;
}

Output of the above program

"In the output it seems that the entered numbers are printed in a peculiar order"

Expected Outcomes:

  • Knowledge of creating the nodes using Linked List.
  • Getting the intersection and Union of data of two list.
  • Comparing the elements of two list.
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