Design of Shallow Foundation (Isolated Footings)
Aim & Introduction :
To Design a square footing for a column size of 400x400. The compression axial load for the load combination of (1.5 DL + 1.5 LL) is 2000 KN. The safe soil bearing capacity is 150 KN/m2 at a depth of 2 metres below E.G.L. Participants are free to go for either a tapered or stepped footing. Besides the total axial load, also account for the self-weight of the footing and soil above it. Assume M25 concrete grade. Do the following checks:
- If the gross bearing pressure under the footing is within safe bearing capacity
- Provide sufficient depth and longitudinal steel for resisting bending and shear
- Sufficient anchorage for column steel into the footing
- If the bearing pressure at column-footing joint is within 0.45 times the maximum concrete compressive strength
Provide a simple sketch showing the size of the footing, maximum and minimum depth of the section, flexural reinforcement in both directions and anchorage of column steel.
Procedure :
- Steps involved in Footing Designs
- Calculation of Gross Soil Pressure for footing area
- Calculation of net soil pressure for flexural and Shear Design
- Initial depth of footing calculation
- flexural reinforcement Calculation
- One way Shear Check
- Two way Shear Chech
Calculation of Gross Soil Pressure for footing area
(Unfactored Load with Surcharge x Self weight of footing)/Allowable Soil Pressure
=(2000/1.5 x 1.11)/150
=9.78mm2
Assume we have square footing
=√ (9.78)
=3.12m WIDE footing
=3.2 m Isolated Footing
Calculation of net soil pressure for flexural and Shear Design
= Factored Load/Actual Area of footing
= 2000x1000 / (3.2 x 3.2)
Pn = 195.3 Kn/m2
Assume depth of footing 500mm and check it for bearing Stress as per IS 456-2000
√(Footing base area/Loaded area)<= 2
Permissible Bearing Stress = .45 x fck = 11.25KN/m2
Permissible bearing Stress x Area of factor = 11.25 x 2 = 22.5N/mm2
Actual bearing Stress at Column BAse = 2000 x 2000 /(400 x 400) = 12.5N/mm2
Therefore, 12.5N/mm2 Actual Bearing Stress is less than Permissible bearing Stress
hence it's Okay
WE CAN proceed with Cover of 50mm and effective Cover depth is 450mm
Flexural Reinforcement
Conversion of Net Pressure into uniformly Distributed Load
= 195.3 x 3.2 = 625KN/m
Bending Moment due to UDL over cantilever Section
=wl2/2
=.626 x 1.6 x 1.6 / 2
M = 800KNm
Reinforcement Calculation as per IS 456-2000
Mu = .87fy Ast d (1-(Ast fy/bd fck)
Assume Fy = 500N/mm2 and Ast required = 4350mm2
Place 16mm dia of rebar at spacing of 125mm
Actual Rebar Provided =(3200/125 x 201)
Ast Provided = 5146mm2
Hence Ast Provided is greater than ast required hence it is okay
One Way Shear Check
Shear Force in One Way
=.95 x 3.2 x 195.3 = 593.7KN
Design Shear Stress at one way
=593.7 x 1000 / (3200 x 450)
=.412N/mm2
Shear Stress Capacity of Section as Per IS 456-2000
= .425n/mm2
design Shear stress is less than Shear capacity
Hence it is okay
Two way Shear Stress
Shear force in two way
=(3.2 x 3.2) - (.85 x .85) x 195.3 = 1859 KN
Design Shear Stress at two way
= 1895 x 1000 / (3400 x450) = 1.215 N/mm2
Shear Stress Capacity of Section as Per IS 456-2000
=.25 x √fck = 1.25N/mm2
design Shear Stress is less than the Shear Capacity
hence okay
Diagram

Result :
From the above procedure we come to know how design and Check for footing