Wiring harness routing & packaging Rules Week 3 Challenge
Wiring harness routing & packaging Rules Week 3 Challenge
Question 1:
Download following cad data & define it as Electrical support using Electrical Part design Workbench. Define all the necessary properties.
Solution:
Given cad data
Create center points on entry and exit section of p clip . wrt the the rubber casing that is used to protect the wire.
Create 3 planes : basepalne , entry and exit point plane
use Electrical part Design
use support definition
Question 2:
Download following Back shell cad data & define it as Electrical back shell using Electrical Part design Workbench. Define all the necessary properties.
Solution:
given data:
link - https://www.te.com/usa-en/product-1738312-1.html
create center point
mid point reference to mating surface
creating axis system
use electrical part design
define given part as backshell
define bundle connection point
Question 3:
Create Following Corrugated tubes & Add them in Catalogue under “Slit COT” family.
|
Name |
ID (mm) |
OD (mm) |
Thickness (mm) |
|
15mm COT |
12 |
15 |
1.5 |
|
20mm COT |
17 |
20 |
1.5 |
|
35mm COT |
32 |
35 |
1.5 |
|
10mm COT |
7 |
10 |
1.5 |
|
5mm COT |
3 |
5 |
1 |
Solution:
Initaly lets create a CatalogDocument
use Add family tool, add name , change type to conduit.
save the file in desired location.
15mm COT
create new part file
As per data given
innerdia =12mm
outerdia=15mm
thickness=(15-12)/2=1.5
min bent radus=outer dia *1.5 =22.5,asume 23mm
save the file where cataloge is added
add to catalog slit COT
use Slit COT as famly and press OK
20mm COT
create new part file
As per data given
innerdia =17mm
outerdia=20mm
thickness=(20-17)/2=1.5mm
min bent radus=outer dia *1.5 =30,assume 32mm
save file, add to catalog . as in same methord as done above.
35mm COT
create new part file
As per data given
innerdia =32mm
outerdia=35mm
thickness=(35-32)/2=1.5mm
min bent radus=outer dia *1.5 =52.5,assume 54mm
save andd add to catalog
10mm COT
create new part file
As per data given
innerdia =7mm
outerdia=10mm
thickness=(10-7)/2=1.5mm
min bent radus=outer dia *1.5 =15,assume 17mm
save and add to catalog
5mm COT
create new part file
As per data given
innerdia =3mm
outerdia=5mm
thickness=(5-3)/2=1mm
min bent radus=outer dia *1.5 =7.5mm,assume 9mm
save and add to catalog
Catalog data
