Week-6 Challenge: EV Drivetrain
1)POWER CONVERTERS USED IN HEV & EV VECHICLES
- By using power converter we can varry the output with minimum losses and high stability with better control.
- Without the help of power converters the HEV&EV cannot the operated.
- With the help of power converts are used to
- Stabilizes the input power (AC to AC converters).
- Charging the battery from the power source (AC to DC converters).
- And controlling the other controllers in case of both step up and step down(DC to DC converters).
- Powering the induction motor (DC to AC convertres).
Generally used power converters are listed below
AC-AC CONVERTERS
- These converters are used for stabilizing the input AC supply (from the grid) in the case of controlling/varrying both voltage and frequency of the supply before entering to the rectifing unit.
- This is done by the help of inverters,auto transformers etc.
- By the help of Auto transformer we can only varry/control the voltage we cannot varry/control the frequency of the supply.
- By the help of inverter we can control/varry both the frequency and the voltage of the supply.
- This fig represents the basic circuit diagram of the inverter.
AC-DC CONVERTERS
- These converter are used to converting AC-DC source for charging the battery and to operate the other control units which are present in the vechicle like speakers,dashboard and othe control unit like battery management system,Motor speed controller etc.
- These operation is done by the help of rectification unit.
- In this we can control the output voltage & current.
- It consists of both controlled (using diodes) and uncontrolled (using thyrist) converters
- There are different type of converters used are
- Half wave rectifier
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- In half-wave rectification of a single-phase supply, either the positive or negative half of the AC wave is passed, while the other half is blocked.
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- Full wave rectifier
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- A full-wave rectifier converts the whole of the input waveform (AC supply) to one of constant polarity (positive or negative) at its output.
- Half wave rectifier
DC-DC CONVERTERS
- These converter plays an vital role in HEV and EV vechicle.
- These converters are also known as SMPS (switched mode power supply).
- By the help of these converters we can varry the output voltage in both step up and step down .
- Here if the output voltage is stepped up the output current is decreased and vise versa.
- The different types are
- Buck converter

- This converter will step down the output voltage by varrying the duty cycle ratio.
- Here the 'OFF' period is long comparing to 'ON' period .
- The output voltage is lower than input voltage (Vin > Vout).
- Boost converter

- This converter will step up the output voltage by varrying the duty cycle ratio.
- Here the 'ON' period is long comparing to 'OFF' period.
- The output voltage is higher than input voltage (Vin < Vout).
- Buck-Boost converter
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- It is a combination of both buck and boost conveter.
- It consists of two transistors T1 & T2 .
- It works on both DC and AC supply as input.
- It can produce output voltage in terms of
- Same as the input voltage (Vin = Vout).
- Lower than input voltage (Vin > Vout).
- Higher than input voltage (Vin < Vout).
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- Buck converter
DC-AC CONVERTERS
- This is also known as inverter.
- The inverter is an electronic device used to convert Direct Current (DC) into Alternating current(AC). The Alternating Current is a current that consistently changes its magnitude with respect to time.
- In EV the inverters are used for powering the induction motor.
2)TO FIND THE STAEDY STATE SPEED IF DUTY CYCLE IS 70%
Given:
Va= 72 V
Ia = 400 A
Ra = 0.5 Ω
Kφ = 0.7
Fc= 400 Hz
D = 70% = 0.7
Tv = 24.7+(0.0051)w2 -------------->①
Solution:
Vavg = Va * D = 72 * 0.7
Vavg = 50.4 V
The average voltage is 50.4 V
W.K.T
T = ((V* Kφ)/ Ra) - (( w* Kφ2)/ Ra)
T = ((50.4 * 0.7) / 0.5) – (w * 0.72) / 0.5)
T = 70.56 – (0.98) w ---------->②
Comparing equ ① & ②
24.7+(0.0051)w2 = 70.56 – (0.98) w
(0.0051)w2 + (0.98) w - 45.86 = 0
This equation represents the quadratic equation
w = -b ± 0√(b^2-4a*c)/(2*a)
w = - 0.98±√((0.98)^2-(4* 0.0051*(-45.86)))/((2*0.0051))
w =(- 0.98 ± 1.377)/0.0102
From solving the above equation, we got
W = 38.9149 rad/sec and W = -231.07184 rad/sec
By considering the forward direction of the motor we consider only the positive steady state speed of the motor by we neglect the negative value
W = 38.9149 rad/sec
3) TO DEVELOP A MATHEMATICAL MODEL OF THE DC MACHINE FOR THE GIVEN EQUATION
GIVEN
ω">ω= V/Kϕ">ϕ -Ra/Kϕ">ϕ^2 .T
MODEL

This is the mathematical model for the given equatio n
Where the values of voltage , armature resistance ,motor konstant are feeded into the workspace
4)INDUCTION VS DC BRUSHLESS MOTORS BY WALLY RIPPEL,TESLA
- From the author perspective he compares the Induction and Brushless motor over the time period .
- There is no perticular winner between Induction Vs DC brushless Dc motor because each having its loyal proponents and religious detractors.
- COMBUSTION ENGINE
- He starts with the gas powered engine vechicles , Those engines are not alike in all vechicle.
- According to the performance and price the vechicle those engine are selected .
- And there is no best engine (having low effienciey).
- ELECTRIC MACHINE
- In his young period there is only lead acid batteries,lead acid batteries.
- Nowadays Lead has been replaced by lithium and DC by either DC brushless or induction.
- After the inverter modules are developed the brushless DC motor and Induction motor become used in EV ,Each will have its loyal proponents and religious detractors.
- A Closer Look
| INDUCTION MOTOR | DC BRUSHLESS MOTOR | RESULT | |
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